TSTP Solution File: SWV133+1 by SPASS---3.9
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% File : SPASS---3.9
% Problem : SWV133+1 : TPTP v8.1.0. Bugfixed v3.3.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Wed Jul 20 21:41:23 EDT 2022
% Result : Theorem 1.25s 1.48s
% Output : Refutation 1.25s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13 % Problem : SWV133+1 : TPTP v8.1.0. Bugfixed v3.3.0.
% 0.08/0.14 % Command : run_spass %d %s
% 0.13/0.35 % Computer : n011.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 600
% 0.13/0.35 % DateTime : Wed Jun 15 04:30:50 EDT 2022
% 0.13/0.35 % CPUTime :
% 1.25/1.48
% 1.25/1.48 SPASS V 3.9
% 1.25/1.48 SPASS beiseite: Proof found.
% 1.25/1.48 % SZS status Theorem
% 1.25/1.48 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 1.25/1.48 SPASS derived 4742 clauses, backtracked 960 clauses, performed 8 splits and kept 2876 clauses.
% 1.25/1.48 SPASS allocated 89152 KBytes.
% 1.25/1.48 SPASS spent 0:00:01.10 on the problem.
% 1.25/1.48 0:00:00.04 for the input.
% 1.25/1.48 0:00:00.08 for the FLOTTER CNF translation.
% 1.25/1.48 0:00:00.03 for inferences.
% 1.25/1.48 0:00:00.03 for the backtracking.
% 1.25/1.48 0:00:00.84 for the reduction.
% 1.25/1.48
% 1.25/1.48
% 1.25/1.48 Here is a proof with depth 2, length 8 :
% 1.25/1.48 % SZS output start Refutation
% 1.25/1.48 5[0:Inp] || -> leq(n2,pv1325)*l.
% 1.25/1.48 20[0:Inp] || -> gt(n2,n0)*l.
% 1.25/1.48 32[0:Inp] || leq(n0,pv1325)*l -> .
% 1.25/1.48 70[0:Inp] || gt(u,v)* -> leq(v,u).
% 1.25/1.48 106[0:Inp] || leq(u,v)* leq(v,w)* -> leq(u,w)*.
% 1.25/1.48 6394[0:Res:20.0,70.0] || -> leq(n0,n2)*r.
% 1.25/1.48 6989[0:OCh:106.1,106.0,6394.0,5.0] || -> leq(n0,pv1325)*l.
% 1.25/1.48 6994[0:MRR:6989.0,32.0] || -> .
% 1.25/1.48 % SZS output end Refutation
% 1.25/1.48 Formulae used in the proof : gauss_array_0003 gt_2_0 leq_gt1 transitivity_leq
% 1.25/1.48
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