TSTP Solution File: SWC317+1 by Twee---2.4.2

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Twee---2.4.2
% Problem  : SWC317+1 : TPTP v8.1.2. Released v2.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 20:54:57 EDT 2023

% Result   : Theorem 3.27s 0.83s
% Output   : Proof 3.27s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : SWC317+1 : TPTP v8.1.2. Released v2.4.0.
% 0.10/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.34  % Computer : n011.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Mon Aug 28 15:06:55 EDT 2023
% 0.12/0.34  % CPUTime  : 
% 3.27/0.83  Command-line arguments: --no-flatten-goal
% 3.27/0.83  
% 3.27/0.83  % SZS status Theorem
% 3.27/0.83  
% 3.27/0.84  % SZS output start Proof
% 3.27/0.84  Take the following subset of the input axioms:
% 3.27/0.84    fof(ax1, axiom, ![U]: (ssItem(U) => ![V]: (ssItem(V) => (neq(U, V) <=> U!=V)))).
% 3.27/0.84    fof(ax13, axiom, ![U2]: (ssList(U2) => (duplicatefreeP(U2) <=> ![V2]: (ssItem(V2) => ![W]: (ssItem(W) => ![X]: (ssList(X) => ![Y]: (ssList(Y) => ![Z]: (ssList(Z) => (app(app(X, cons(V2, Y)), cons(W, Z))=U2 => V2!=W))))))))).
% 3.27/0.84    fof(ax15, axiom, ![U2]: (ssList(U2) => ![V2]: (ssList(V2) => (neq(U2, V2) <=> U2!=V2)))).
% 3.27/0.84    fof(ax18, axiom, ![U2]: (ssList(U2) => ![V2]: (ssItem(V2) => cons(V2, U2)!=U2))).
% 3.27/0.84    fof(ax21, axiom, ![U2]: (ssList(U2) => ![V2]: (ssItem(V2) => nil!=cons(V2, U2)))).
% 3.27/0.84    fof(ax33, axiom, ![U2]: (ssItem(U2) => ![V2]: (ssItem(V2) => (lt(U2, V2) => ~lt(V2, U2))))).
% 3.27/0.84    fof(ax38, axiom, ![U2]: (ssItem(U2) => ~memberP(nil, U2))).
% 3.27/0.85    fof(ax8, axiom, ![U2]: (ssList(U2) => (cyclefreeP(U2) <=> ![V2]: (ssItem(V2) => ![W2]: (ssItem(W2) => ![X3]: (ssList(X3) => ![Y2]: (ssList(Y2) => ![Z2]: (ssList(Z2) => (app(app(X3, cons(V2, Y2)), cons(W2, Z2))=U2 => ~(leq(V2, W2) & leq(W2, V2))))))))))).
% 3.27/0.85    fof(ax90, axiom, ![U2]: (ssItem(U2) => ~lt(U2, U2))).
% 3.27/0.85    fof(ax93, axiom, ![U2]: (ssItem(U2) => ![V2]: (ssItem(V2) => (lt(U2, V2) <=> (U2!=V2 & leq(U2, V2)))))).
% 3.27/0.85    fof(ax94, axiom, ![U2]: (ssItem(U2) => ![V2]: (ssItem(V2) => (gt(U2, V2) => ~gt(V2, U2))))).
% 3.27/0.85    fof(co1, conjecture, ![U2]: (ssList(U2) => ![V2]: (ssList(V2) => ![W2]: (ssList(W2) => ![X3]: (ssList(X3) => (V2!=X3 | (U2!=W2 | ((~neq(V2, nil) | (?[Y2]: (ssItem(Y2) & ?[Z2]: (ssList(Z2) & (app(cons(Y2, nil), Z2)=U2 & app(Z2, cons(Y2, nil))=V2))) | ![X1]: (ssItem(X1) => ![X2]: (ssList(X2) => (app(cons(X1, nil), X2)!=W2 | app(X2, cons(X1, nil))!=X3))))) & (~neq(V2, nil) | neq(X3, nil)))))))))).
% 3.27/0.85  
% 3.27/0.85  Now clausify the problem and encode Horn clauses using encoding 3 of
% 3.27/0.85  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 3.27/0.85  We repeatedly replace C & s=t => u=v by the two clauses:
% 3.27/0.85    fresh(y, y, x1...xn) = u
% 3.27/0.85    C => fresh(s, t, x1...xn) = v
% 3.27/0.85  where fresh is a fresh function symbol and x1..xn are the free
% 3.27/0.85  variables of u and v.
% 3.27/0.85  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 3.27/0.85  input problem has no model of domain size 1).
% 3.27/0.85  
% 3.27/0.85  The encoding turns the above axioms into the following unit equations and goals:
% 3.27/0.85  
% 3.27/0.85  Axiom 1 (co1_2): u = w.
% 3.27/0.85  Axiom 2 (co1_3): v = x.
% 3.27/0.85  Axiom 3 (co1_13): fresh18(X, X) = w.
% 3.27/0.85  Axiom 4 (co1_14): fresh17(X, X) = x.
% 3.27/0.85  Axiom 5 (co1_15): fresh16(X, X) = true2.
% 3.27/0.85  Axiom 6 (co1_17): fresh14(X, X) = true2.
% 3.27/0.85  Axiom 7 (co1_5): neq(v, nil) = true2.
% 3.27/0.85  Axiom 8 (co1_15): fresh16(neq(x, nil), true2) = ssItem(x1).
% 3.27/0.85  Axiom 9 (co1_17): fresh14(neq(x, nil), true2) = ssList(x2).
% 3.27/0.85  Axiom 10 (co1_14): fresh17(neq(x, nil), true2) = app(x2, cons(x1, nil)).
% 3.27/0.85  Axiom 11 (ax81): fresh30(X, X, Y, Z) = app(cons(Z, nil), Y).
% 3.27/0.85  Axiom 12 (co1_13): fresh18(neq(x, nil), true2) = app(cons(x1, nil), x2).
% 3.27/0.85  
% 3.27/0.85  Goal 1 (co1_11): tuple6(app(X, cons(Y, nil)), app(cons(Y, nil), X), ssItem(Y), neq(x, nil), ssList(X)) = tuple6(v, u, true2, true2, true2).
% 3.27/0.85  The goal is true when:
% 3.27/0.85    X = x2
% 3.27/0.85    Y = x1
% 3.27/0.85  
% 3.27/0.85  Proof:
% 3.27/0.85    tuple6(app(x2, cons(x1, nil)), app(cons(x1, nil), x2), ssItem(x1), neq(x, nil), ssList(x2))
% 3.27/0.85  = { by axiom 11 (ax81) R->L }
% 3.27/0.85    tuple6(app(x2, cons(x1, nil)), fresh30(X, X, x2, x1), ssItem(x1), neq(x, nil), ssList(x2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(app(x2, cons(x1, nil)), fresh30(X, X, x2, x1), ssItem(x1), neq(v, nil), ssList(x2))
% 3.27/0.85  = { by axiom 7 (co1_5) }
% 3.27/0.85    tuple6(app(x2, cons(x1, nil)), fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 10 (co1_14) R->L }
% 3.27/0.85    tuple6(fresh17(neq(x, nil), true2), fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(fresh17(neq(v, nil), true2), fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 7 (co1_5) }
% 3.27/0.85    tuple6(fresh17(true2, true2), fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 4 (co1_14) }
% 3.27/0.85    tuple6(x, fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(v, fresh30(X, X, x2, x1), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 11 (ax81) }
% 3.27/0.85    tuple6(v, app(cons(x1, nil), x2), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 12 (co1_13) R->L }
% 3.27/0.85    tuple6(v, fresh18(neq(x, nil), true2), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(v, fresh18(neq(v, nil), true2), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 7 (co1_5) }
% 3.27/0.85    tuple6(v, fresh18(true2, true2), ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 3 (co1_13) }
% 3.27/0.85    tuple6(v, w, ssItem(x1), true2, ssList(x2))
% 3.27/0.85  = { by axiom 8 (co1_15) R->L }
% 3.27/0.85    tuple6(v, w, fresh16(neq(x, nil), true2), true2, ssList(x2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(v, w, fresh16(neq(v, nil), true2), true2, ssList(x2))
% 3.27/0.85  = { by axiom 7 (co1_5) }
% 3.27/0.85    tuple6(v, w, fresh16(true2, true2), true2, ssList(x2))
% 3.27/0.85  = { by axiom 5 (co1_15) }
% 3.27/0.85    tuple6(v, w, true2, true2, ssList(x2))
% 3.27/0.85  = { by axiom 9 (co1_17) R->L }
% 3.27/0.85    tuple6(v, w, true2, true2, fresh14(neq(x, nil), true2))
% 3.27/0.85  = { by axiom 2 (co1_3) R->L }
% 3.27/0.85    tuple6(v, w, true2, true2, fresh14(neq(v, nil), true2))
% 3.27/0.85  = { by axiom 7 (co1_5) }
% 3.27/0.85    tuple6(v, w, true2, true2, fresh14(true2, true2))
% 3.27/0.85  = { by axiom 6 (co1_17) }
% 3.27/0.85    tuple6(v, w, true2, true2, true2)
% 3.27/0.85  = { by axiom 1 (co1_2) R->L }
% 3.27/0.85    tuple6(v, u, true2, true2, true2)
% 3.27/0.85  % SZS output end Proof
% 3.27/0.85  
% 3.27/0.85  RESULT: Theorem (the conjecture is true).
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