TSTP Solution File: SEV390^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV390^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:52 EDT 2023
% Result : Theorem 5.41s 5.62s
% Output : Proof 5.41s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEV390^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.16/0.34 % Computer : n015.cluster.edu
% 0.16/0.34 % Model : x86_64 x86_64
% 0.16/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.34 % Memory : 8042.1875MB
% 0.16/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.34 % CPULimit : 300
% 0.16/0.34 % WCLimit : 300
% 0.16/0.34 % DateTime : Thu Aug 24 03:27:50 EDT 2023
% 0.16/0.34 % CPUTime :
% 5.41/5.62 SZS status Theorem for theBenchmark.p
% 5.41/5.62 SZS output start Proof for theBenchmark.p
% 5.41/5.62 Clause #0 (by assumption #[]): Eq (Not (Eq (fun Xx => And (cR Xx) (cS Xx)) cR → ∀ (Xx : Iota), cR Xx → cS Xx)) True
% 5.41/5.62 Clause #1 (by clausification #[0]): Eq (Eq (fun Xx => And (cR Xx) (cS Xx)) cR → ∀ (Xx : Iota), cR Xx → cS Xx) False
% 5.41/5.62 Clause #2 (by clausification #[1]): Eq (Eq (fun Xx => And (cR Xx) (cS Xx)) cR) True
% 5.41/5.62 Clause #3 (by clausification #[1]): Eq (∀ (Xx : Iota), cR Xx → cS Xx) False
% 5.41/5.62 Clause #4 (by clausification #[2]): Eq (fun Xx => And (cR Xx) (cS Xx)) cR
% 5.41/5.62 Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq ((fun Xx => And (cR Xx) (cS Xx)) a) (cR a)
% 5.41/5.62 Clause #6 (by clausification #[3]): ∀ (a : Iota), Eq (Not (cR (skS.0 0 a) → cS (skS.0 0 a))) True
% 5.41/5.62 Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (cR (skS.0 0 a) → cS (skS.0 0 a)) False
% 5.41/5.62 Clause #8 (by clausification #[7]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) True
% 5.41/5.62 Clause #9 (by clausification #[7]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) False
% 5.41/5.62 Clause #10 (by betaEtaReduce #[5]): ∀ (a : Iota), Eq (And (cR a) (cS a)) (cR a)
% 5.41/5.62 Clause #12 (by identity boolHoist #[10]): ∀ (a : Iota), Or (Eq (And (cR a) False) (cR a)) (Eq (cS a) True)
% 5.41/5.62 Clause #14 (by bool simp #[12]): ∀ (a : Iota), Or (Eq False (cR a)) (Eq (cS a) True)
% 5.41/5.62 Clause #17 (by superposition #[14, 8]): ∀ (a : Iota), Or (Eq (cS (skS.0 0 a)) True) (Eq False True)
% 5.41/5.62 Clause #19 (by clausification #[17]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) True
% 5.41/5.62 Clause #20 (by superposition #[19, 9]): Eq True False
% 5.41/5.62 Clause #21 (by clausification #[20]): False
% 5.41/5.62 SZS output end Proof for theBenchmark.p
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