TSTP Solution File: SEV383^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV383^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n183.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:34:07 EDT 2014

% Result   : Theorem 0.38s
% Output   : Proof 0.38s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV383^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n183.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 09:01:56 CDT 2014
% % CPUTime  : 0.38 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1912878>, <kernel.Constant object at 0x1912d88>) of role type named a
% Using role type
% Declaring a:fofType
% FOF formula ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))) of role conjecture named cBLEDSOE_FENG_7
% Conjecture to prove = ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))):Prop
% We need to prove ['((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))']
% Parameter fofType:Type.
% Parameter a:fofType.
% Trying to prove ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Found x0:(x a)
% Found x0 as proof of False
% Found (fun (x0:(x a))=> x0) as proof of False
% Found (fun (x0:(x a))=> x0) as proof of ((x a)->False)
% Found (ex_intro000 (fun (x0:(x a))=> x0)) as proof of ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Found ((ex_intro00 (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0)) as proof of ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Found (((ex_intro0 (fun (A:(fofType->Prop))=> ((A a)->False))) (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0)) as proof of ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Found ((((ex_intro (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))) (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0)) as proof of ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Found ((((ex_intro (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))) (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0)) as proof of ((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False)))
% Got proof ((((ex_intro (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))) (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0))
% Time elapsed = 0.064324s
% node=11 cost=222.000000 depth=7
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% ((((ex_intro (fofType->Prop)) (fun (A:(fofType->Prop))=> ((A a)->False))) (fun (a0:fofType)=> False)) (fun (x0:((fun (a0:fofType)=> False) a))=> x0))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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