TSTP Solution File: SEV301^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV301^5 : TPTP v6.2.0. Bugfixed v6.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n096.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-504.8.1.el6.x86_64
% CPULimit : 300s
% DateTime : Wed May  6 14:27:25 EDT 2015

% Result   : Unknown 16.50s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : SEV301^5 : TPTP v6.2.0. Bugfixed v6.2.0.
% 0.00/0.03  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/1.08  % Computer : n096.star.cs.uiowa.edu
% 0.02/1.08  % Model    : x86_64 x86_64
% 0.02/1.08  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/1.08  % Memory   : 32286.75MB
% 0.02/1.08  % OS       : Linux 2.6.32-504.8.1.el6.x86_64
% 0.02/1.08  % CPULimit : 300
% 0.02/1.08  % DateTime : Thu Apr 16 12:25:52 CDT 2015
% 0.02/1.08  % CPUTime  : 
% 0.02/1.09  Python 2.7.5
% 0.04/1.41  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.04/1.41  FOF formula (<kernel.Constant object at 0x1f70710>, <kernel.DependentProduct object at 0x1f70050>) of role type named cNAT_type
% 0.04/1.41  Using role type
% 0.04/1.41  Declaring cNAT:(((fofType->Prop)->Prop)->Prop)
% 0.04/1.41  FOF formula (<kernel.Constant object at 0x1ebd3f8>, <kernel.DependentProduct object at 0x1f70050>) of role type named cSUCC_type
% 0.04/1.41  Using role type
% 0.04/1.41  Declaring cSUCC:(((fofType->Prop)->Prop)->((fofType->Prop)->Prop))
% 0.04/1.41  FOF formula (<kernel.Constant object at 0x1f70680>, <kernel.DependentProduct object at 0x1f70710>) of role type named cZERO_type
% 0.04/1.41  Using role type
% 0.04/1.41  Declaring cZERO:((fofType->Prop)->Prop)
% 0.04/1.41  FOF formula (((eq ((fofType->Prop)->Prop)) cZERO) (fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False))) of role definition named cZERO_def
% 0.04/1.41  A new definition: (((eq ((fofType->Prop)->Prop)) cZERO) (fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False)))
% 0.04/1.41  Defined: cZERO:=(fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False))
% 0.04/1.41  FOF formula (((eq (((fofType->Prop)->Prop)->((fofType->Prop)->Prop))) cSUCC) (fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt))))))))) of role definition named cSUCC_def
% 0.04/1.41  A new definition: (((eq (((fofType->Prop)->Prop)->((fofType->Prop)->Prop))) cSUCC) (fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt)))))))))
% 0.04/1.41  Defined: cSUCC:=(fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt))))))))
% 0.04/1.41  FOF formula (((eq (((fofType->Prop)->Prop)->Prop)) cNAT) (fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn))))) of role definition named cNAT_def
% 0.04/1.41  A new definition: (((eq (((fofType->Prop)->Prop)->Prop)) cNAT) (fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn)))))
% 0.04/1.41  Defined: cNAT:=(fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn))))
% 0.04/1.41  FOF formula (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))->(forall (Xm:((fofType->Prop)->Prop)), ((forall (Xp0:(((fofType->Prop)->Prop)->Prop)), (((and (Xp0 cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp0 Xx)->(Xp0 (cSUCC Xx)))))->(Xp0 Xm)))->(Xp Xm))))) of role conjecture named cX6102_A
% 0.04/1.41  Conjecture to prove = (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))->(forall (Xm:((fofType->Prop)->Prop)), ((forall (Xp0:(((fofType->Prop)->Prop)->Prop)), (((and (Xp0 cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp0 Xx)->(Xp0 (cSUCC Xx)))))->(Xp0 Xm)))->(Xp Xm))))):Prop
% 0.04/1.41  Parameter fofType_DUMMY:fofType.
% 0.04/1.41  We need to prove ['(forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))->(forall (Xm:((fofType->Prop)->Prop)), ((forall (Xp0:(((fofType->Prop)->Prop)->Prop)), (((and (Xp0 cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp0 Xx)->(Xp0 (cSUCC Xx)))))->(Xp0 Xm)))->(Xp Xm)))))']
% 0.04/1.41  Parameter fofType:Type.
% 0.04/1.41  Definition cNAT:=(fun (Xn:((fofType->Prop)->Prop))=> (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp Xn)))):(((fofType->Prop)->Prop)->Prop).
% 0.04/1.41  Definition cSUCC:=(fun (Xn:((fofType->Prop)->Prop)) (Xp:(fofType->Prop))=> ((ex fofType) (fun (Xx:fofType)=> ((and (Xp Xx)) (Xn (fun (Xt:fofType)=> ((and (not (((eq fofType) Xt) Xx))) (Xp Xt)))))))):(((fofType->Prop)->Prop)->((fofType->Prop)->Prop)).
% 4.09/5.29  Definition cZERO:=(fun (Xp:(fofType->Prop))=> (((ex fofType) (fun (Xx:fofType)=> (Xp Xx)))->False)):((fofType->Prop)->Prop).
% 4.09/5.29  Trying to prove (forall (Xp:(((fofType->Prop)->Prop)->Prop)), (((and (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))->(forall (Xm:((fofType->Prop)->Prop)), ((forall (Xp0:(((fofType->Prop)->Prop)->Prop)), (((and (Xp0 cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((Xp0 Xx)->(Xp0 (cSUCC Xx)))))->(Xp0 Xm)))->(Xp Xm)))))
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found x1 as proof of (Xp cZERO)
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of (Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found x1 as proof of (Xp cZERO)
% 4.09/5.29  Found x10:(Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of (Xp cZERO)
% 4.09/5.29  Found (fun (x10:(Xp cZERO)) (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 4.09/5.29  Found (fun (x10:(Xp cZERO)) (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of ((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO)))
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found x1 as proof of (Xp cZERO)
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of (Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found x1 as proof of (Xp cZERO)
% 4.09/5.29  Found x10:(Xp cZERO)
% 4.09/5.29  Found (fun (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of (Xp cZERO)
% 4.09/5.29  Found (fun (x10:(Xp cZERO)) (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 4.09/5.29  Found (fun (x10:(Xp cZERO)) (x20:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x10) as proof of ((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO)))
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x21:=(x2 x20):(Xp Xx)
% 4.09/5.29  Found (x2 x20) as proof of (Xp Xx)
% 4.09/5.29  Found (x2 x20) as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x3:(Xp Xx)
% 4.09/5.29  Found x3 as proof of (Xp Xx)
% 4.09/5.29  Found x1:(Xp cZERO)
% 4.09/5.29  Found (fun (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of (Xp cZERO)
% 4.09/5.29  Found (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 4.09/5.29  Found (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO)))
% 4.09/5.29  Found (and_rect00 (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found ((and_rect0 (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found (((fun (P:Type) (x1:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))) P) x1) x)) (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found (((fun (P:Type) (x1:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))) P) x1) x)) (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found x1:(Xp Xx)
% 10.08/11.28  Found x1 as proof of (Xp Xx)
% 10.08/11.28  Found x3:(Xp Xx)
% 10.08/11.28  Found x3 as proof of (Xp Xx)
% 10.08/11.28  Found x21:=(x2 x20):(Xp Xx)
% 10.08/11.28  Found (x2 x20) as proof of (Xp Xx)
% 10.08/11.28  Found (x2 x20) as proof of (Xp Xx)
% 10.08/11.28  Found x3:(Xp Xx)
% 10.08/11.28  Found x3 as proof of (Xp Xx)
% 10.08/11.28  Found x110:=(x11 x20):(Xp Xx)
% 10.08/11.28  Found (x11 x20) as proof of (Xp Xx)
% 10.08/11.28  Found ((x1 x10) x20) as proof of (Xp Xx)
% 10.08/11.28  Found ((x1 x10) x20) as proof of (Xp Xx)
% 10.08/11.28  Found x1:(Xp cZERO)
% 10.08/11.28  Found (fun (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of (Xp cZERO)
% 10.08/11.28  Found (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO))
% 10.08/11.28  Found (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1) as proof of ((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->(Xp cZERO)))
% 10.08/11.28  Found (and_rect00 (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found ((and_rect0 (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found (((fun (P:Type) (x1:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))) P) x1) x)) (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found (((fun (P:Type) (x1:((Xp cZERO)->((forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))->P)))=> (((((and_rect (Xp cZERO)) (forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx)))))) P) x1) x)) (Xp cZERO)) (fun (x1:(Xp cZERO)) (x2:(forall (Xx:((fofType->Prop)->Prop)), ((cNAT Xx)->((Xp Xx)->(Xp (cSUCC Xx))))))=> x1)) as proof of (Xp cZERO)
% 10.08/11.28  Found x1:(Xp Xx)
% 10.08/11.28  Found x1 as proof of (Xp Xx)
% 10.08/11.28  Found x110:=(x11 x20):(Xp Xx)
% 10.08/11.28  Found (x11 x20) as proof of (Xp Xx)
% 10.08/11.28  Found ((x1 x10) x20) as proof of (Xp Xx)
% 10.08/11.28  Found ((x1 x10) x20) as proof of (Xp Xx)
% 10.08/11.28  Found x20:(Xp Xx)
% 10.08/11.28  Found x20 as proof of (Xp Xx)
% 10.08/11.28  Found x20:(Xp Xx)
% 10.08/11.28  Found x20 as proof of (Xp Xx)
% 10.08/11.28  Found x200:(forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x200 as proof of (forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x200:(forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x200 as proof of (forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x21:(Xp Xx)
% 10.08/11.28  Found x21 as proof of (Xp Xx)
% 10.08/11.28  Found x200:(forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x200 as proof of (forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 10.08/11.28  Found x21:(Xp Xx)
% 10.08/11.28  Found x21 as proof of (Xp Xx)
% 10.08/11.28  Found x200:(forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 16.50/17.63  Found x200 as proof of (forall (Xx0:((fofType->Prop)->Prop)), ((cNAT Xx0)->((Xp Xx0)->(Xp (cSUCC Xx0)))))
% 16.50/17.63  % SZS status GaveUp for /export/starexec/sandbox2/benchmark/theBenchmark.p
%------------------------------------------------------------------------------