TSTP Solution File: SEV273^5 by Satallax---3.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Satallax---3.5
% Problem  : SEV273^5 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 18:05:40 EDT 2022

% Result   : Theorem 2.93s 3.15s
% Output   : Proof 2.93s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.12  % Problem  : SEV273^5 : TPTP v8.1.0. Released v4.0.0.
% 0.09/0.12  % Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
% 0.12/0.33  % Computer : n013.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Tue Jun 28 17:30:29 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 2.93/3.15  % SZS status Theorem
% 2.93/3.15  % Mode: mode506
% 2.93/3.15  % Inferences: 21077
% 2.93/3.15  % SZS output start Proof
% 2.93/3.15  thf(cTHM542_pme,conjecture,((![X1:a>$o]:((~((![X2:a]:(~((X1 @ X2)))))) => (~((![X2:a]:((~(((X1 @ X2) => (~((![X3:a]:((X1 @ X3) => ((cR @ X2) @ X3)))))))) => (~((![X3:a]:((~(((X1 @ X3) => (~((![X4:a]:((X1 @ X4) => ((cR @ X3) @ X4)))))))) => (X3 = X2))))))))))) => (![X1:a]:((cR @ X1) @ X1)))).
% 2.93/3.15  thf(h0,negated_conjecture,(~(((![X1:a>$o]:((~((![X2:a]:(~((X1 @ X2)))))) => (~((![X2:a]:((~(((X1 @ X2) => (~((![X3:a]:((X1 @ X3) => ((cR @ X2) @ X3)))))))) => (~((![X3:a]:((~(((X1 @ X3) => (~((![X4:a]:((X1 @ X4) => ((cR @ X3) @ X4)))))))) => (X3 = X2))))))))))) => (![X1:a]:((cR @ X1) @ X1))))),inference(assume_negation,[status(cth)],[cTHM542_pme])).
% 2.93/3.15  thf(ax1242, axiom, ~(p1), file('<stdin>', ax1242)).
% 2.93/3.15  thf(ax1240, axiom, (p1|~(p3)), file('<stdin>', ax1240)).
% 2.93/3.15  thf(ax913, axiom, (~(p2)|p330), file('<stdin>', ax913)).
% 2.93/3.15  thf(ax1241, axiom, (p1|p2), file('<stdin>', ax1241)).
% 2.93/3.15  thf(ax1239, axiom, (p3|~(p4)), file('<stdin>', ax1239)).
% 2.93/3.15  thf(pax330, axiom, (p330=>(~(![X1:a]:~((f__0)=(X1)))=>~(![X1:a]:(~(((f__0)=(X1)=>~(![X2:a]:((f__0)=(X2)=>fcR @ X1 @ X2))))=>~(![X2:a]:(~(((f__0)=(X2)=>~(![X3:a]:((f__0)=(X3)=>fcR @ X2 @ X3))))=>(X2)=(X1))))))), file('<stdin>', pax330)).
% 2.93/3.15  thf(nax4, axiom, (p4<=fcR @ f__0 @ f__0), file('<stdin>', nax4)).
% 2.93/3.15  thf(c_0_7, plain, ~p1, inference(fof_simplification,[status(thm)],[ax1242])).
% 2.93/3.15  thf(c_0_8, plain, (p1|~p3), inference(fof_simplification,[status(thm)],[ax1240])).
% 2.93/3.15  thf(c_0_9, plain, (~p2|p330), inference(fof_simplification,[status(thm)],[ax913])).
% 2.93/3.15  thf(c_0_10, plain, (p1|p2), inference(split_conjunct,[status(thm)],[ax1241])).
% 2.93/3.15  thf(c_0_11, plain, ~p1, inference(split_conjunct,[status(thm)],[c_0_7])).
% 2.93/3.15  thf(c_0_12, plain, (p3|~p4), inference(fof_simplification,[status(thm)],[ax1239])).
% 2.93/3.15  thf(c_0_13, plain, (p1|~p3), inference(split_conjunct,[status(thm)],[c_0_8])).
% 2.93/3.15  thf(c_0_14, plain, ![X8335:a, X8337:a, X8338:a]:((((f__0)=(esk4166_0)|(f__0)!=(X8335)|~p330)&((f__0)!=(X8337)|fcR @ esk4166_0 @ X8337|(f__0)!=(X8335)|~p330))&(((f__0)=(esk4167_1 @ X8338)|(f__0)!=(X8338)|(X8338)=(esk4166_0)|(f__0)!=(X8335)|~p330)&(~fcR @ X8338 @ (esk4167_1 @ X8338)|(f__0)!=(X8338)|(X8338)=(esk4166_0)|(f__0)!=(X8335)|~p330))), inference(distribute,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[inference(fof_simplification,[status(thm)],[pax330])])])])])])).
% 2.93/3.15  thf(c_0_15, plain, (p330|~p2), inference(split_conjunct,[status(thm)],[c_0_9])).
% 2.93/3.15  thf(c_0_16, plain, p2, inference(sr,[status(thm)],[c_0_10, c_0_11])).
% 2.93/3.15  thf(c_0_17, plain, (~fcR @ f__0 @ f__0|p4), inference(fof_nnf,[status(thm)],[inference(fof_simplification,[status(thm)],[nax4])])).
% 2.93/3.15  thf(c_0_18, plain, (p3|~p4), inference(split_conjunct,[status(thm)],[c_0_12])).
% 2.93/3.15  thf(c_0_19, plain, ~p3, inference(sr,[status(thm)],[c_0_13, c_0_11])).
% 2.93/3.15  thf(c_0_20, plain, ![X1:a]:((f__0)=(esk4166_0)|(f__0)!=(X1)|~p330), inference(split_conjunct,[status(thm)],[c_0_14])).
% 2.93/3.15  thf(c_0_21, plain, p330, inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_15, c_0_16])])).
% 2.93/3.15  thf(c_0_22, plain, (p4|~fcR @ f__0 @ f__0), inference(split_conjunct,[status(thm)],[c_0_17])).
% 2.93/3.15  thf(c_0_23, plain, ~p4, inference(sr,[status(thm)],[c_0_18, c_0_19])).
% 2.93/3.15  thf(c_0_24, plain, ![X1:a, X2:a]:(fcR @ esk4166_0 @ X1|(f__0)!=(X1)|(f__0)!=(X2)|~p330), inference(split_conjunct,[status(thm)],[c_0_14])).
% 2.93/3.15  thf(c_0_25, plain, (esk4166_0)=(f__0), inference(er,[status(thm)],[inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_20, c_0_21])])])).
% 2.93/3.15  thf(c_0_26, plain, ~fcR @ f__0 @ f__0, inference(sr,[status(thm)],[c_0_22, c_0_23])).
% 2.93/3.15  thf(c_0_27, plain, ($false), inference(sr,[status(thm)],[inference(er,[status(thm)],[inference(er,[status(thm)],[inference(cn,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[c_0_24, c_0_25]), c_0_21])])])]), c_0_26]), ['proof']).
% 2.93/3.15  thf(1,plain,$false,inference(eprover,[status(thm),assumptions([h0])],[])).
% 2.93/3.15  thf(0,theorem,((![X1:a>$o]:((~((![X2:a]:(~((X1 @ X2)))))) => (~((![X2:a]:((~(((X1 @ X2) => (~((![X3:a]:((X1 @ X3) => ((cR @ X2) @ X3)))))))) => (~((![X3:a]:((~(((X1 @ X3) => (~((![X4:a]:((X1 @ X4) => ((cR @ X3) @ X4)))))))) => (X3 = X2))))))))))) => (![X1:a]:((cR @ X1) @ X1))),inference(contra,[status(thm),contra(discharge,[h0])],[1,h0])).
% 2.93/3.15  % SZS output end Proof
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