TSTP Solution File: SEV232^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV232^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:33 EDT 2023

% Result   : Theorem 3.43s 3.65s
% Output   : Proof 3.43s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SEV232^5 : TPTP v8.1.2. Released v4.0.0.
% 0.07/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n009.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Thu Aug 24 03:18:06 EDT 2023
% 0.12/0.34  % CPUTime    : 
% 3.43/3.65  SZS status Theorem for theBenchmark.p
% 3.43/3.65  SZS output start Proof for theBenchmark.p
% 3.43/3.65  Clause #0 (by assumption #[]): Eq
% 3.43/3.65    (Not
% 3.43/3.65      (Eq
% 3.43/3.65        (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65        fun Xx =>
% 3.43/3.65        ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx))
% 3.43/3.65    True
% 3.43/3.65  Clause #1 (by clausification #[0]): Eq
% 3.43/3.65    (Eq (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65      fun Xx =>
% 3.43/3.65      ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx)
% 3.43/3.65    False
% 3.43/3.65  Clause #2 (by clausification #[1]): Ne (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65    fun Xx => ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx
% 3.43/3.65  Clause #3 (by eliminate resolved literals #[2]): False
% 3.43/3.65  SZS output end Proof for theBenchmark.p
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