TSTP Solution File: SEV232^5 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SEV232^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:33 EDT 2023
% Result : Theorem 3.43s 3.65s
% Output : Proof 3.43s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SEV232^5 : TPTP v8.1.2. Released v4.0.0.
% 0.07/0.13 % Command : duper %s
% 0.12/0.34 % Computer : n009.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Thu Aug 24 03:18:06 EDT 2023
% 0.12/0.34 % CPUTime :
% 3.43/3.65 SZS status Theorem for theBenchmark.p
% 3.43/3.65 SZS output start Proof for theBenchmark.p
% 3.43/3.65 Clause #0 (by assumption #[]): Eq
% 3.43/3.65 (Not
% 3.43/3.65 (Eq
% 3.43/3.65 (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65 fun Xx =>
% 3.43/3.65 ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx))
% 3.43/3.65 True
% 3.43/3.65 Clause #1 (by clausification #[0]): Eq
% 3.43/3.65 (Eq (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65 fun Xx =>
% 3.43/3.65 ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx)
% 3.43/3.65 False
% 3.43/3.65 Clause #2 (by clausification #[1]): Ne (fun N => ∀ (P : ((Iota → Prop) → Prop) → Prop), And (P c0) (∀ (X : (Iota → Prop) → Prop), P X → P (cS X)) → P N)
% 3.43/3.65 fun Xx => ∀ (S0 : ((Iota → Prop) → Prop) → Prop), And (S0 c0) (∀ (X : (Iota → Prop) → Prop), S0 X → S0 (cS X)) → S0 Xx
% 3.43/3.65 Clause #3 (by eliminate resolved literals #[2]): False
% 3.43/3.65 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------