TSTP Solution File: SEV228^5 by cocATP---0.2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SEV228^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n091.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32286.75MB
% OS : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:54 EDT 2014
% Result : Unknown 0.41s
% Output : None
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem : SEV228^5 : TPTP v6.1.0. Released v4.0.0.
% % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n091.star.cs.uiowa.edu
% % Model : x86_64 x86_64
% % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory : 32286.75MB
% % OS : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:33:31 CDT 2014
% % CPUTime : 0.41
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x18a7b90>, <kernel.Type object at 0x18a78c0>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x1cd8d88>, <kernel.DependentProduct object at 0x18a77e8>) of role type named cS
% Using role type
% Declaring cS:(a->Prop)
% FOF formula (forall (Xx:a), ((cS Xx)->((ex (a->Prop)) (fun (S_11:(a->Prop))=> ((and (forall (Xx0:a), ((S_11 Xx0)->(cS Xx0)))) (S_11 Xx)))))) of role conjecture named cTHM91A_pme
% Conjecture to prove = (forall (Xx:a), ((cS Xx)->((ex (a->Prop)) (fun (S_11:(a->Prop))=> ((and (forall (Xx0:a), ((S_11 Xx0)->(cS Xx0)))) (S_11 Xx)))))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['(forall (Xx:a), ((cS Xx)->((ex (a->Prop)) (fun (S_11:(a->Prop))=> ((and (forall (Xx0:a), ((S_11 Xx0)->(cS Xx0)))) (S_11 Xx))))))']
% Parameter a:Type.
% Parameter cS:(a->Prop).
% Trying to prove (forall (Xx:a), ((cS Xx)->((ex (a->Prop)) (fun (S_11:(a->Prop))=> ((and (forall (Xx0:a), ((S_11 Xx0)->(cS Xx0)))) (S_11 Xx))))))
% Found x00:(x0 Xx0)
% Found x00 as proof of (cS Xx0)
% Found (fun (x00:(x0 Xx0))=> x00) as proof of (cS Xx0)
% Found (fun (Xx0:a) (x00:(x0 Xx0))=> x00) as proof of ((x0 Xx0)->(cS Xx0))
% Found (fun (Xx0:a) (x00:(x0 Xx0))=> x00) as proof of (forall (Xx0:a), ((x0 Xx0)->(cS Xx0)))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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