TSTP Solution File: SEV217^5 by Refute---2015
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%------------------------------------------------------------------------------
% File : Refute---2015
% Problem : SEV217^5 : TPTP v6.4.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : isabelle tptp_refute %d %s
% Computer : n050.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.75MB
% OS : Linux 3.10.0-327.10.1.el7.x86_64
% CPULimit : 300s
% DateTime : Thu Apr 14 04:28:22 EDT 2016
% Result : Timeout 300.01s
% Output : None
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : SEV217^5 : TPTP v6.4.0. Released v4.0.0.
% 0.00/0.04 % Command : isabelle tptp_refute %d %s
% 0.02/0.23 % Computer : n050.star.cs.uiowa.edu
% 0.02/0.23 % Model : x86_64 x86_64
% 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23 % Memory : 32218.75MB
% 0.02/0.23 % OS : Linux 3.10.0-327.10.1.el7.x86_64
% 0.02/0.23 % CPULimit : 300
% 0.02/0.23 % DateTime : Fri Apr 8 07:15:54 CDT 2016
% 0.02/0.23 % CPUTime :
% 6.30/5.84 > val it = (): unit
% 6.60/6.13 Trying to find a model that refutes: ((((ALL Xx Xy. bnd_cP Xx Xy ~= bnd_c0) &
% 6.60/6.13 (ALL Xx Xy Xu Xv. bnd_cP Xx Xu = bnd_cP Xy Xv --> Xx = Xy & Xu = Xv)) &
% 6.60/6.13 (ALL X.
% 6.60/6.13 X bnd_c0 & (ALL Xx Xy. X Xx & X Xy --> X (bnd_cP Xx Xy)) -->
% 6.60/6.13 (ALL Xx. X Xx))) &
% 6.60/6.13 (ALL Xz. bnd_cX0 Xz = (~ bnd_cX1 Xz))) &
% 6.60/6.13 (ALL Xz. bnd_cX0 Xz --> bnd_cL Xz = Xz & bnd_cR Xz = Xz) -->
% 6.60/6.13 (ALL R0.
% 6.60/6.13 (ALL Xc.
% 6.60/6.13 (R0 Xc bnd_c0 &
% 6.60/6.13 (ALL Xx Xy.
% 6.60/6.13 R0 Xc Xy &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xy) -->
% 6.60/6.13 R0 Xc Xx)) &
% 6.60/6.13 (ALL Xx Xy Xz.
% 6.60/6.13 (R0 Xc Xx & R0 Xc Xy) &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xz) -->
% 6.60/6.13 R0 Xc Xz)) -->
% 6.60/6.13 (ALL Xc.
% 6.60/6.13 ((bnd_c0 = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (bnd_c0 = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2)) &
% 6.60/6.13 (ALL Xx Xy.
% 6.60/6.13 (Xy = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xy = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2)) &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xy) -->
% 6.60/6.13 Xx = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xx = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2))) &
% 6.60/6.13 (ALL Xx Xy Xz.
% 6.60/6.13 ((Xx = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xx = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2)) &
% 6.60/6.13 (Xy = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xy = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2))) &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xz) -->
% 6.60/6.13 Xz = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xc &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xz = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xc) Xu2)))) &
% 6.60/6.13 (ALL R0 S.
% 6.60/6.13 ((ALL Xc.
% 6.60/6.13 (R0 Xc bnd_c0 &
% 6.60/6.13 (ALL Xx Xy.
% 6.60/6.13 R0 Xc Xy &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xy) -->
% 6.60/6.13 R0 Xc Xx)) &
% 6.60/6.13 (ALL Xx Xy Xz.
% 6.60/6.13 (R0 Xc Xx & R0 Xc Xy) &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xz) -->
% 6.60/6.13 R0 Xc Xz)) &
% 6.60/6.13 (ALL Xc.
% 6.60/6.13 (S Xc bnd_c0 &
% 6.60/6.13 (ALL Xx Xy.
% 6.60/6.13 S Xc Xy &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xy) -->
% 6.60/6.13 S Xc Xx)) &
% 6.60/6.13 (ALL Xx Xy Xz.
% 6.60/6.13 (S Xc Xx & S Xc Xy) &
% 6.60/6.13 (ALL R1.
% 6.60/6.13 True &
% 6.60/6.13 (ALL Xa Xb Xc0.
% 6.60/6.13 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 6.60/6.13 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.60/6.13 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 6.60/6.13 Xc0 = bnd_cP Xz1 Xz2) &
% 6.60/6.13 R1 Xx1 Xy1 Xz1) &
% 6.60/6.13 R1 Xx2 Xy2 Xz2) -->
% 6.60/6.13 R1 Xa Xb Xc0) -->
% 6.60/6.13 R1 Xx Xy Xz) -->
% 6.60/6.13 S Xc Xz))) &
% 6.60/6.13 (ALL Xa Xb. R0 Xa Xb --> S Xa Xb) -->
% 6.60/6.13 (ALL Xa Xb.
% 6.60/6.13 Xb = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xa &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xb = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xa) Xu1) &
% 6.60/6.13 R0 (bnd_cR Xa) Xu2) -->
% 6.60/6.13 Xb = bnd_c0 |
% 6.60/6.13 bnd_cX1 Xa &
% 6.60/6.13 (EX Xu1 Xu2.
% 6.60/6.13 (Xb = bnd_cP Xu1 Xu2 & S (bnd_cL Xa) Xu1) & S (bnd_cR Xa) Xu2)))
% 7.20/6.70 Unfolded term: ((((ALL Xx Xy. bnd_cP Xx Xy ~= bnd_c0) &
% 7.20/6.70 (ALL Xx Xy Xu Xv. bnd_cP Xx Xu = bnd_cP Xy Xv --> Xx = Xy & Xu = Xv)) &
% 7.20/6.70 (ALL X.
% 7.20/6.70 X bnd_c0 & (ALL Xx Xy. X Xx & X Xy --> X (bnd_cP Xx Xy)) --> All X)) &
% 7.20/6.70 (ALL Xz. bnd_cX0 Xz = (~ bnd_cX1 Xz))) &
% 7.20/6.70 (ALL Xz. bnd_cX0 Xz --> bnd_cL Xz = Xz & bnd_cR Xz = Xz) -->
% 7.20/6.70 (ALL R0.
% 7.20/6.70 (ALL Xc.
% 7.20/6.70 (R0 Xc bnd_c0 &
% 7.20/6.70 (ALL Xx Xy.
% 7.20/6.70 R0 Xc Xy &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xy) -->
% 7.20/6.70 R0 Xc Xx)) &
% 7.20/6.70 (ALL Xx Xy Xz.
% 7.20/6.70 (R0 Xc Xx & R0 Xc Xy) &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xz) -->
% 7.20/6.70 R0 Xc Xz)) -->
% 7.20/6.70 (ALL Xc.
% 7.20/6.70 ((bnd_c0 = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (bnd_c0 = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2)) &
% 7.20/6.70 (ALL Xx Xy.
% 7.20/6.70 (Xy = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xy = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2)) &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xy) -->
% 7.20/6.70 Xx = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xx = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2))) &
% 7.20/6.70 (ALL Xx Xy Xz.
% 7.20/6.70 ((Xx = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xx = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2)) &
% 7.20/6.70 (Xy = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xy = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2))) &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xz) -->
% 7.20/6.70 Xz = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xc &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xz = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xc) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xc) Xu2)))) &
% 7.20/6.70 (ALL R0 S.
% 7.20/6.70 ((ALL Xc.
% 7.20/6.70 (R0 Xc bnd_c0 &
% 7.20/6.70 (ALL Xx Xy.
% 7.20/6.70 R0 Xc Xy &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xy) -->
% 7.20/6.70 R0 Xc Xx)) &
% 7.20/6.70 (ALL Xx Xy Xz.
% 7.20/6.70 (R0 Xc Xx & R0 Xc Xy) &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xz) -->
% 7.20/6.70 R0 Xc Xz)) &
% 7.20/6.70 (ALL Xc.
% 7.20/6.70 (S Xc bnd_c0 &
% 7.20/6.70 (ALL Xx Xy.
% 7.20/6.70 S Xc Xy &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xy) -->
% 7.20/6.70 S Xc Xx)) &
% 7.20/6.70 (ALL Xx Xy Xz.
% 7.20/6.70 (S Xc Xx & S Xc Xy) &
% 7.20/6.70 (ALL R1.
% 7.20/6.70 True &
% 7.20/6.70 (ALL Xa Xb Xc0.
% 7.20/6.70 (Xa = bnd_c0 & Xb = Xc0 | Xb = bnd_c0 & Xa = Xc0) |
% 7.20/6.70 (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 7.20/6.70 (((Xa = bnd_cP Xx1 Xx2 & Xb = bnd_cP Xy1 Xy2) &
% 7.20/6.70 Xc0 = bnd_cP Xz1 Xz2) &
% 7.20/6.70 R1 Xx1 Xy1 Xz1) &
% 7.20/6.70 R1 Xx2 Xy2 Xz2) -->
% 7.20/6.70 R1 Xa Xb Xc0) -->
% 7.20/6.70 R1 Xx Xy Xz) -->
% 7.20/6.70 S Xc Xz))) &
% 7.20/6.70 (ALL Xa Xb. R0 Xa Xb --> S Xa Xb) -->
% 7.20/6.70 (ALL Xa Xb.
% 7.20/6.70 Xb = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xa &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xb = bnd_cP Xu1 Xu2 & R0 (bnd_cL Xa) Xu1) &
% 7.20/6.70 R0 (bnd_cR Xa) Xu2) -->
% 7.20/6.70 Xb = bnd_c0 |
% 7.20/6.70 bnd_cX1 Xa &
% 7.20/6.70 (EX Xu1 Xu2.
% 7.20/6.70 (Xb = bnd_cP Xu1 Xu2 & S (bnd_cL Xa) Xu1) & S (bnd_cR Xa) Xu2)))
% 7.20/6.70 Adding axioms...
% 7.20/6.71 Typedef.type_definition_def
% 7.70/7.28 Typedef.type_definition_def
% 13.21/12.72 ...done.
% 13.21/12.73 Ground types: ?'b, bnd_iS, bnd_c
% 13.21/12.73 Translating term (sizes: 1, 1, 1) ...
% 24.23/23.72 Invoking SAT solver...
% 24.23/23.72 No model exists.
% 24.23/23.72 Translating term (sizes: 2, 1, 1) ...
% 36.55/36.06 Invoking SAT solver...
% 36.55/36.06 No model exists.
% 36.55/36.06 Translating term (sizes: 1, 2, 1) ...
% 300.01/297.92 /export/starexec/sandbox/solver/lib/scripts/run-polyml-5.5.2: line 82: 54356 CPU time limit exceeded (core dumped) "$ISABELLE_HOME/lib/scripts/feeder" -p -h "$MLTEXT" -t "$MLEXIT" $FEEDER_OPTS
% 300.01/297.92 54357 (core dumped) | { read FPID; "$POLY" -q -i $ML_OPTIONS; RC="$?"; kill -TERM "$FPID"; exit "$RC"; }
% 300.01/297.93 /export/starexec/sandbox/solver/src/HOL/TPTP/lib/Tools/tptp_refute: line 26: 54302 Exit 152 "$ISABELLE_PROCESS" -q -e "use_thy \"/tmp/$SCRATCH\"; exit 1;" HOL-TPTP
% 300.01/297.93 54303 CPU time limit exceeded (core dumped) | grep --line-buffered -v "^###\|^PROOF FAILED for depth\|^Failure node\|inferences so far. Searching to depth\|^val \|^Loading theory\|^Warning-The type of\|^ monotype.$"
%------------------------------------------------------------------------------