TSTP Solution File: SEV215^5 by Refute---2015

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Refute---2015
% Problem  : SEV215^5 : TPTP v6.4.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : isabelle tptp_refute %d %s

% Computer : n146.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.75MB
% OS       : Linux 3.10.0-327.10.1.el7.x86_64
% CPULimit : 300s
% DateTime : Thu Apr 14 04:28:22 EDT 2016

% Result   : Timeout 300.04s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : SEV215^5 : TPTP v6.4.0. Released v4.0.0.
% 0.00/0.04  % Command  : isabelle tptp_refute %d %s
% 0.02/0.23  % Computer : n146.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.75MB
% 0.02/0.23  % OS       : Linux 3.10.0-327.10.1.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Apr  8 07:15:24 CDT 2016
% 0.02/0.23  % CPUTime  : 
% 6.31/5.84  > val it = (): unit
% 6.51/6.08  Trying to find a model that refutes: ((((ALL Xx Xy. bnd_cP Xx Xy ~= bnd_c0) &
% 6.51/6.08     (ALL Xx Xy Xu Xv. bnd_cP Xx Xu = bnd_cP Xy Xv --> Xx = Xy & Xu = Xv)) &
% 6.51/6.08    (ALL X.
% 6.51/6.08        X bnd_c0 & (ALL Xx Xy. X Xx & X Xy --> X (bnd_cP Xx Xy)) -->
% 6.51/6.08        (ALL Xx. X Xx))) &
% 6.51/6.08   (ALL Xz. bnd_cX0 Xz = (~ bnd_cX1 Xz))) &
% 6.51/6.08  (ALL Xz. bnd_cX0 Xz --> bnd_cL Xz = Xz & bnd_cR Xz = Xz) -->
% 6.51/6.08  (EX Xf.
% 6.51/6.08      (((ALL Xb.
% 6.51/6.08            (Xf Xb bnd_c0 &
% 6.51/6.08             (ALL Xx Xy.
% 6.51/6.08                 Xf Xb Xy &
% 6.51/6.08                 (ALL R0.
% 6.51/6.08                     True &
% 6.51/6.08                     (ALL Xa Xb0 Xc.
% 6.51/6.08                         (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.51/6.08                         (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.51/6.08                             (((Xa = bnd_cP Xx1 Xx2 & Xb0 = bnd_cP Xy1 Xy2) &
% 6.51/6.08                               Xc = bnd_cP Xz1 Xz2) &
% 6.51/6.08                              R0 Xx1 Xy1 Xz1) &
% 6.51/6.08                             R0 Xx2 Xy2 Xz2) -->
% 6.51/6.08                         R0 Xa Xb0 Xc) -->
% 6.51/6.08                     R0 Xx Xy Xy) -->
% 6.51/6.08                 Xf Xb Xx)) &
% 6.51/6.08            (ALL Xx Xy Xz.
% 6.51/6.08                (Xf Xb Xx & Xf Xb Xy) &
% 6.51/6.08                (ALL R0.
% 6.51/6.08                    True &
% 6.51/6.08                    (ALL Xa Xb0 Xc.
% 6.51/6.08                        (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.51/6.08                        (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.51/6.08                            (((Xa = bnd_cP Xx1 Xx2 & Xb0 = bnd_cP Xy1 Xy2) &
% 6.51/6.08                              Xc = bnd_cP Xz1 Xz2) &
% 6.51/6.08                             R0 Xx1 Xy1 Xz1) &
% 6.51/6.08                            R0 Xx2 Xy2 Xz2) -->
% 6.51/6.08                        R0 Xa Xb0 Xc) -->
% 6.51/6.08                    R0 Xx Xy Xz) -->
% 6.51/6.08                Xf Xb Xz)) &
% 6.51/6.08        (ALL Xc. bnd_cX0 Xc = (Xf Xc = op = bnd_c0))) &
% 6.51/6.08       (ALL Xb.
% 6.51/6.08           (%Xx. Xx = bnd_c0 | (EX Xy. Xf Xb (bnd_cP Xx Xy))) =
% 6.51/6.08           Xf (bnd_cL Xb) &
% 6.51/6.08           (%Xy. Xy = bnd_c0 | (EX Xx. Xf Xb (bnd_cP Xx Xy))) =
% 6.51/6.08           Xf (bnd_cR Xb))) &
% 6.51/6.08      (ALL Xg.
% 6.51/6.08          ((ALL Xb.
% 6.51/6.08               (Xg Xb bnd_c0 &
% 6.51/6.08                (ALL Xx Xy.
% 6.51/6.08                    Xg Xb Xy &
% 6.51/6.08                    (ALL R0.
% 6.51/6.08                        True &
% 6.51/6.08                        (ALL Xa Xb0 Xc.
% 6.51/6.08                            (Xa = bnd_c0 & Xb0 = Xc |
% 6.51/6.08                             Xb0 = bnd_c0 & Xa = Xc) |
% 6.51/6.08                            (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.51/6.08                                (((Xa = bnd_cP Xx1 Xx2 &
% 6.51/6.08                                   Xb0 = bnd_cP Xy1 Xy2) &
% 6.51/6.08                                  Xc = bnd_cP Xz1 Xz2) &
% 6.51/6.08                                 R0 Xx1 Xy1 Xz1) &
% 6.51/6.08                                R0 Xx2 Xy2 Xz2) -->
% 6.51/6.08                            R0 Xa Xb0 Xc) -->
% 6.51/6.08                        R0 Xx Xy Xy) -->
% 6.51/6.08                    Xg Xb Xx)) &
% 6.51/6.08               (ALL Xx Xy Xz.
% 6.51/6.08                   (Xg Xb Xx & Xg Xb Xy) &
% 6.51/6.08                   (ALL R0.
% 6.51/6.08                       True &
% 6.51/6.08                       (ALL Xa Xb0 Xc.
% 6.51/6.08                           (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.51/6.08                           (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.51/6.08                               (((Xa = bnd_cP Xx1 Xx2 &
% 6.51/6.08                                  Xb0 = bnd_cP Xy1 Xy2) &
% 6.51/6.08                                 Xc = bnd_cP Xz1 Xz2) &
% 6.51/6.08                                R0 Xx1 Xy1 Xz1) &
% 6.51/6.08                               R0 Xx2 Xy2 Xz2) -->
% 6.51/6.08                           R0 Xa Xb0 Xc) -->
% 6.51/6.08                       R0 Xx Xy Xz) -->
% 6.51/6.08                   Xg Xb Xz)) &
% 6.51/6.08           (ALL Xc. bnd_cX0 Xc = (Xg Xc = op = bnd_c0))) &
% 6.51/6.08          (ALL Xb.
% 6.51/6.08              (%Xx. Xx = bnd_c0 | (EX Xy. Xg Xb (bnd_cP Xx Xy))) =
% 6.51/6.08              Xg (bnd_cL Xb) &
% 6.51/6.08              (%Xy. Xy = bnd_c0 | (EX Xx. Xg Xb (bnd_cP Xx Xy))) =
% 6.51/6.08              Xg (bnd_cR Xb)) -->
% 6.51/6.08          Xf = Xg))
% 6.91/6.42  Unfolded term: ((((ALL Xx Xy. bnd_cP Xx Xy ~= bnd_c0) &
% 6.91/6.42     (ALL Xx Xy Xu Xv. bnd_cP Xx Xu = bnd_cP Xy Xv --> Xx = Xy & Xu = Xv)) &
% 6.91/6.42    (ALL X.
% 6.91/6.42        X bnd_c0 & (ALL Xx Xy. X Xx & X Xy --> X (bnd_cP Xx Xy)) --> All X)) &
% 6.91/6.42   (ALL Xz. bnd_cX0 Xz = (~ bnd_cX1 Xz))) &
% 6.91/6.42  (ALL Xz. bnd_cX0 Xz --> bnd_cL Xz = Xz & bnd_cR Xz = Xz) -->
% 6.91/6.42  (EX Xf.
% 6.91/6.42      (((ALL Xb.
% 6.91/6.42            (Xf Xb bnd_c0 &
% 6.91/6.42             (ALL Xx Xy.
% 6.91/6.42                 Xf Xb Xy &
% 6.91/6.42                 (ALL R0.
% 6.91/6.42                     True &
% 6.91/6.42                     (ALL Xa Xb0 Xc.
% 6.91/6.42                         (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.91/6.42                         (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.91/6.42                             (((Xa = bnd_cP Xx1 Xx2 & Xb0 = bnd_cP Xy1 Xy2) &
% 6.91/6.42                               Xc = bnd_cP Xz1 Xz2) &
% 6.91/6.42                              R0 Xx1 Xy1 Xz1) &
% 6.91/6.42                             R0 Xx2 Xy2 Xz2) -->
% 6.91/6.42                         R0 Xa Xb0 Xc) -->
% 6.91/6.42                     R0 Xx Xy Xy) -->
% 6.91/6.42                 Xf Xb Xx)) &
% 6.91/6.42            (ALL Xx Xy Xz.
% 6.91/6.42                (Xf Xb Xx & Xf Xb Xy) &
% 6.91/6.42                (ALL R0.
% 6.91/6.42                    True &
% 6.91/6.42                    (ALL Xa Xb0 Xc.
% 6.91/6.42                        (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.91/6.42                        (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.91/6.42                            (((Xa = bnd_cP Xx1 Xx2 & Xb0 = bnd_cP Xy1 Xy2) &
% 6.91/6.42                              Xc = bnd_cP Xz1 Xz2) &
% 6.91/6.42                             R0 Xx1 Xy1 Xz1) &
% 6.91/6.42                            R0 Xx2 Xy2 Xz2) -->
% 6.91/6.42                        R0 Xa Xb0 Xc) -->
% 6.91/6.42                    R0 Xx Xy Xz) -->
% 6.91/6.42                Xf Xb Xz)) &
% 6.91/6.42        (ALL Xc. bnd_cX0 Xc = (Xf Xc = op = bnd_c0))) &
% 6.91/6.42       (ALL Xb.
% 6.91/6.42           (%Xx. Xx = bnd_c0 | (EX Xy. Xf Xb (bnd_cP Xx Xy))) =
% 6.91/6.42           Xf (bnd_cL Xb) &
% 6.91/6.42           (%Xy. Xy = bnd_c0 | (EX Xx. Xf Xb (bnd_cP Xx Xy))) =
% 6.91/6.42           Xf (bnd_cR Xb))) &
% 6.91/6.42      (ALL Xg.
% 6.91/6.42          ((ALL Xb.
% 6.91/6.42               (Xg Xb bnd_c0 &
% 6.91/6.42                (ALL Xx Xy.
% 6.91/6.42                    Xg Xb Xy &
% 6.91/6.42                    (ALL R0.
% 6.91/6.42                        True &
% 6.91/6.42                        (ALL Xa Xb0 Xc.
% 6.91/6.42                            (Xa = bnd_c0 & Xb0 = Xc |
% 6.91/6.42                             Xb0 = bnd_c0 & Xa = Xc) |
% 6.91/6.42                            (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.91/6.42                                (((Xa = bnd_cP Xx1 Xx2 &
% 6.91/6.42                                   Xb0 = bnd_cP Xy1 Xy2) &
% 6.91/6.42                                  Xc = bnd_cP Xz1 Xz2) &
% 6.91/6.42                                 R0 Xx1 Xy1 Xz1) &
% 6.91/6.42                                R0 Xx2 Xy2 Xz2) -->
% 6.91/6.42                            R0 Xa Xb0 Xc) -->
% 6.91/6.42                        R0 Xx Xy Xy) -->
% 6.91/6.42                    Xg Xb Xx)) &
% 6.91/6.42               (ALL Xx Xy Xz.
% 6.91/6.42                   (Xg Xb Xx & Xg Xb Xy) &
% 6.91/6.42                   (ALL R0.
% 6.91/6.42                       True &
% 6.91/6.42                       (ALL Xa Xb0 Xc.
% 6.91/6.42                           (Xa = bnd_c0 & Xb0 = Xc | Xb0 = bnd_c0 & Xa = Xc) |
% 6.91/6.42                           (EX Xx1 Xx2 Xy1 Xy2 Xz1 Xz2.
% 6.91/6.42                               (((Xa = bnd_cP Xx1 Xx2 &
% 6.91/6.42                                  Xb0 = bnd_cP Xy1 Xy2) &
% 6.91/6.42                                 Xc = bnd_cP Xz1 Xz2) &
% 6.91/6.42                                R0 Xx1 Xy1 Xz1) &
% 6.91/6.42                               R0 Xx2 Xy2 Xz2) -->
% 6.91/6.42                           R0 Xa Xb0 Xc) -->
% 6.91/6.42                       R0 Xx Xy Xz) -->
% 6.91/6.42                   Xg Xb Xz)) &
% 6.91/6.42           (ALL Xc. bnd_cX0 Xc = (Xg Xc = op = bnd_c0))) &
% 6.91/6.42          (ALL Xb.
% 6.91/6.42              (%Xx. Xx = bnd_c0 | (EX Xy. Xg Xb (bnd_cP Xx Xy))) =
% 6.91/6.42              Xg (bnd_cL Xb) &
% 6.91/6.42              (%Xy. Xy = bnd_c0 | (EX Xx. Xg Xb (bnd_cP Xx Xy))) =
% 6.91/6.42              Xg (bnd_cR Xb)) -->
% 6.91/6.42          Xf = Xg))
% 6.91/6.42  Adding axioms...
% 6.91/6.43  Typedef.type_definition_def
% 7.41/6.92  Typedef.type_definition_def
% 10.22/9.77   ...done.
% 10.22/9.77  Ground types: ?'b, bnd_iS, bnd_c
% 10.22/9.77  Translating term (sizes: 1, 1, 1) ...
% 16.03/15.56  Invoking SAT solver...
% 16.03/15.56  No model exists.
% 16.03/15.56  Translating term (sizes: 2, 1, 1) ...
% 23.56/23.10  Invoking SAT solver...
% 23.56/23.10  No model exists.
% 23.56/23.10  Translating term (sizes: 1, 2, 1) ...
% 300.04/297.82  /export/starexec/sandbox2/solver/lib/scripts/run-polyml-5.5.2: line 82: 46723 CPU time limit exceeded (core dumped) "$ISABELLE_HOME/lib/scripts/feeder" -p -h "$MLTEXT" -t "$MLEXIT" $FEEDER_OPTS
% 300.04/297.82       46724                       (core dumped) | { read FPID; "$POLY" -q -i $ML_OPTIONS; RC="$?"; kill -TERM "$FPID"; exit "$RC"; }
% 300.04/297.83  /export/starexec/sandbox2/solver/src/HOL/TPTP/lib/Tools/tptp_refute: line 26: 46646 Exit 152                "$ISABELLE_PROCESS" -q -e "use_thy \"/tmp/$SCRATCH\"; exit 1;" HOL-TPTP
% 300.04/297.83       46647 CPU time limit exceeded (core dumped) | grep --line-buffered -v "^###\|^PROOF FAILED for depth\|^Failure node\|inferences so far.  Searching to depth\|^val \|^Loading theory\|^Warning-The type of\|^   monotype.$"
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