TSTP Solution File: SEV189^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV189^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n105.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:51 EDT 2014

% Result   : Unknown 0.84s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV189^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n105.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:25:16 CDT 2014
% % CPUTime  : 0.84 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0xc086c8>, <kernel.Type object at 0xc08ef0>) of role type named b_type
% Using role type
% Declaring b:Type
% FOF formula (<kernel.Constant object at 0x105c3b0>, <kernel.DependentProduct object at 0xc08638>) of role type named cQ
% Using role type
% Declaring cQ:((b->Prop)->Prop)
% FOF formula (<kernel.Constant object at 0xc08d88>, <kernel.DependentProduct object at 0xc08830>) of role type named cP
% Using role type
% Declaring cP:((b->Prop)->Prop)
% FOF formula (((and (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cP Xx)))->(cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))) (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cQ Xx)))->(cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))->(forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->((and (cP Xx)) (cQ Xx))))->((and (cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))) (cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))) of role conjecture named cTHM567_pme
% Conjecture to prove = (((and (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cP Xx)))->(cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))) (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cQ Xx)))->(cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))->(forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->((and (cP Xx)) (cQ Xx))))->((and (cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))) (cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))):Prop
% Parameter b_DUMMY:b.
% We need to prove ['(((and (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cP Xx)))->(cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))) (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cQ Xx)))->(cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))->(forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->((and (cP Xx)) (cQ Xx))))->((and (cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))) (cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))))']
% Parameter b:Type.
% Parameter cQ:((b->Prop)->Prop).
% Parameter cP:((b->Prop)->Prop).
% Trying to prove (((and (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cP Xx)))->(cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))) (forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->(cQ Xx)))->(cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx))))))))->(forall (S:((b->Prop)->Prop)), ((forall (Xx:(b->Prop)), ((S Xx)->((and (cP Xx)) (cQ Xx))))->((and (cP (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))) (cQ (fun (Xx:b)=> (forall (S0:(b->Prop)), ((S S0)->(S0 Xx)))))))))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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