TSTP Solution File: SEV182^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV182^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n095.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:51 EDT 2014

% Result   : Unknown 2.03s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV182^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n095.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:23:01 CDT 2014
% % CPUTime  : 2.03 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (forall (S:(fofType->Prop)), (((ex (fofType->Prop)) (fun (Z:(fofType->Prop))=> ((and (forall (Xx:fofType), ((Z Xx)->(S Xx)))) ((ex ((fofType->Prop)->fofType)) (fun (Xs:((fofType->Prop)->fofType))=> ((and (forall (Xx:(fofType->Prop)), ((forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))->(Z (Xs Xx))))) (forall (Xy:fofType), ((Z Xy)->((ex (fofType->Prop)) (fun (Xy0:(fofType->Prop))=> (((eq ((fofType->Prop)->Prop)) (fun (Xx:(fofType->Prop))=> ((and (forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))) (((eq fofType) Xy) (Xs Xx))))) ((fun (Xx:(fofType->Prop)) (Xy:(fofType->Prop))=> (((eq (fofType->Prop)) Xx) Xy)) Xy0))))))))))))->False)) of role conjecture named cTHM110_pme
% Conjecture to prove = (forall (S:(fofType->Prop)), (((ex (fofType->Prop)) (fun (Z:(fofType->Prop))=> ((and (forall (Xx:fofType), ((Z Xx)->(S Xx)))) ((ex ((fofType->Prop)->fofType)) (fun (Xs:((fofType->Prop)->fofType))=> ((and (forall (Xx:(fofType->Prop)), ((forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))->(Z (Xs Xx))))) (forall (Xy:fofType), ((Z Xy)->((ex (fofType->Prop)) (fun (Xy0:(fofType->Prop))=> (((eq ((fofType->Prop)->Prop)) (fun (Xx:(fofType->Prop))=> ((and (forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))) (((eq fofType) Xy) (Xs Xx))))) ((fun (Xx:(fofType->Prop)) (Xy:(fofType->Prop))=> (((eq (fofType->Prop)) Xx) Xy)) Xy0))))))))))))->False)):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['(forall (S:(fofType->Prop)), (((ex (fofType->Prop)) (fun (Z:(fofType->Prop))=> ((and (forall (Xx:fofType), ((Z Xx)->(S Xx)))) ((ex ((fofType->Prop)->fofType)) (fun (Xs:((fofType->Prop)->fofType))=> ((and (forall (Xx:(fofType->Prop)), ((forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))->(Z (Xs Xx))))) (forall (Xy:fofType), ((Z Xy)->((ex (fofType->Prop)) (fun (Xy0:(fofType->Prop))=> (((eq ((fofType->Prop)->Prop)) (fun (Xx:(fofType->Prop))=> ((and (forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))) (((eq fofType) Xy) (Xs Xx))))) ((fun (Xx:(fofType->Prop)) (Xy:(fofType->Prop))=> (((eq (fofType->Prop)) Xx) Xy)) Xy0))))))))))))->False))']
% Parameter fofType:Type.
% Trying to prove (forall (S:(fofType->Prop)), (((ex (fofType->Prop)) (fun (Z:(fofType->Prop))=> ((and (forall (Xx:fofType), ((Z Xx)->(S Xx)))) ((ex ((fofType->Prop)->fofType)) (fun (Xs:((fofType->Prop)->fofType))=> ((and (forall (Xx:(fofType->Prop)), ((forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))->(Z (Xs Xx))))) (forall (Xy:fofType), ((Z Xy)->((ex (fofType->Prop)) (fun (Xy0:(fofType->Prop))=> (((eq ((fofType->Prop)->Prop)) (fun (Xx:(fofType->Prop))=> ((and (forall (Xx0:fofType), ((Xx Xx0)->(S Xx0)))) (((eq fofType) Xy) (Xs Xx))))) ((fun (Xx:(fofType->Prop)) (Xy:(fofType->Prop))=> (((eq (fofType->Prop)) Xx) Xy)) Xy0))))))))))))->False))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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