TSTP Solution File: SEV168^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV168^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:24 EDT 2023
% Result : Theorem 3.52s 3.75s
% Output : Proof 3.52s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEV168^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n018.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Thu Aug 24 03:32:27 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.52/3.75 SZS status Theorem for theBenchmark.p
% 3.52/3.75 SZS output start Proof for theBenchmark.p
% 3.52/3.75 Clause #0 (by assumption #[]): Eq
% 3.52/3.75 (Not
% 3.52/3.75 (And (Eq q fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy))
% 3.52/3.75 (Eq p fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)) →
% 3.52/3.75 Eq p q))
% 3.52/3.75 True
% 3.52/3.75 Clause #1 (by clausification #[0]): Eq
% 3.52/3.75 (And (Eq q fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy))
% 3.52/3.75 (Eq p fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)) →
% 3.52/3.75 Eq p q)
% 3.52/3.75 False
% 3.52/3.75 Clause #2 (by clausification #[1]): Eq
% 3.52/3.75 (And (Eq q fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy))
% 3.52/3.75 (Eq p fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)))
% 3.52/3.75 True
% 3.52/3.75 Clause #3 (by clausification #[1]): Eq (Eq p q) False
% 3.52/3.75 Clause #4 (by clausification #[2]): Eq (Eq p fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)) True
% 3.52/3.75 Clause #5 (by clausification #[2]): Eq (Eq q fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)) True
% 3.52/3.75 Clause #6 (by clausification #[4]): Eq p fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)
% 3.52/3.75 Clause #8 (by clausification #[3]): Ne p q
% 3.52/3.75 Clause #12 (by clausification #[5]): Eq q fun Xg => Xg (q fun Xx Xy => Xx) (q fun Xx Xy => Xy)
% 3.52/3.75 Clause #13 (by superposition #[12, 6]): Eq p q
% 3.52/3.75 Clause #15 (by forward contextual literal cutting #[13, 8]): False
% 3.52/3.75 SZS output end Proof for theBenchmark.p
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