%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV134^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n118.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:47 EDT 2014

% Result   : Theorem 0.38s
% Output   : Proof 0.38s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV134^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n118.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:12:06 CDT 2014
% % CPUTime  : 0.38 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1785908>, <kernel.Type object at 0x1785638>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (forall (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx)))) of role conjecture named cTHM201_pme
% Conjecture to prove = (forall (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx)))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['(forall (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx))))']
% Parameter a:Type.
% Trying to prove (forall (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx))))
% Found x0:(Xx0 Xx)
% Found (fun (x0:(Xx0 Xx))=> x0) as proof of (Xx0 Xx)
% Found (fun (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0) as proof of ((Xx0 Xx)->(Xx0 Xx))
% Found (fun (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0) as proof of ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx)))
% Found (fun (Xx:a) (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0) as proof of (forall (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx))))
% Found (fun (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0) as proof of (forall (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx))))
% Found (fun (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0) as proof of (forall (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)), ((forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))->((Xx0 Xx)->(Xx0 Xx))))
% Got proof (fun (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0)
% Time elapsed = 0.069954s
% node=5 cost=20.000000 depth=5
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (fun (Xr:(a->(a->Prop))) (Xx:a) (Xx0:(a->Prop)) (x:(forall (Xy:a) (Xz:a), (((and ((Xr Xy) Xz)) (Xx0 Xy))->(Xx0 Xz)))) (x0:(Xx0 Xx))=> x0)
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------