TSTP Solution File: SEV134^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV134^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:19 EDT 2023
% Result : Theorem 3.58s 3.78s
% Output : Proof 3.58s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.14 % Problem : SEV134^5 : TPTP v8.1.2. Released v4.0.0.
% 0.14/0.15 % Command : duper %s
% 0.15/0.37 % Computer : n031.cluster.edu
% 0.15/0.37 % Model : x86_64 x86_64
% 0.15/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.37 % Memory : 8042.1875MB
% 0.15/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.37 % CPULimit : 300
% 0.15/0.37 % WCLimit : 300
% 0.15/0.37 % DateTime : Thu Aug 24 03:18:05 EDT 2023
% 0.15/0.37 % CPUTime :
% 3.58/3.78 SZS status Theorem for theBenchmark.p
% 3.58/3.78 SZS output start Proof for theBenchmark.p
% 3.58/3.78 Clause #0 (by assumption #[]): Eq
% 3.58/3.78 (Not
% 3.58/3.78 (∀ (Xr : a → a → Prop) (Xx : a) (Xx0 : a → Prop),
% 3.58/3.78 (∀ (Xy Xz : a), And (Xr Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 Xx → Xx0 Xx))
% 3.58/3.78 True
% 3.58/3.78 Clause #1 (by clausification #[0]): Eq
% 3.58/3.78 (∀ (Xr : a → a → Prop) (Xx : a) (Xx0 : a → Prop), (∀ (Xy Xz : a), And (Xr Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 Xx → Xx0 Xx)
% 3.58/3.78 False
% 3.58/3.78 Clause #2 (by clausification #[1]): ∀ (a_1 : a → a → Prop),
% 3.58/3.78 Eq (Not (∀ (Xx : a) (Xx0 : a → Prop), (∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 Xx → Xx0 Xx))
% 3.58/3.78 True
% 3.58/3.78 Clause #3 (by clausification #[2]): ∀ (a_1 : a → a → Prop),
% 3.58/3.78 Eq (∀ (Xx : a) (Xx0 : a → Prop), (∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 Xx → Xx0 Xx) False
% 3.58/3.78 Clause #4 (by clausification #[3]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.58/3.78 Eq
% 3.58/3.78 (Not
% 3.58/3.78 (∀ (Xx0 : a → Prop),
% 3.58/3.78 (∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 (skS.0 1 a_1 a_2) → Xx0 (skS.0 1 a_1 a_2)))
% 3.58/3.78 True
% 3.58/3.78 Clause #5 (by clausification #[4]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.58/3.78 Eq
% 3.58/3.78 (∀ (Xx0 : a → Prop),
% 3.58/3.78 (∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (Xx0 Xy) → Xx0 Xz) → Xx0 (skS.0 1 a_1 a_2) → Xx0 (skS.0 1 a_1 a_2))
% 3.58/3.78 False
% 3.58/3.78 Clause #6 (by clausification #[5]): ∀ (a_1 : a → a → Prop) (a_2 : a) (a_3 : a → Prop),
% 3.58/3.78 Eq
% 3.58/3.78 (Not
% 3.58/3.78 ((∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (skS.0 2 a_1 a_2 a_3 Xy) → skS.0 2 a_1 a_2 a_3 Xz) →
% 3.58/3.78 skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2) → skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2)))
% 3.58/3.78 True
% 3.58/3.78 Clause #7 (by clausification #[6]): ∀ (a_1 : a → a → Prop) (a_2 : a) (a_3 : a → Prop),
% 3.58/3.78 Eq
% 3.58/3.78 ((∀ (Xy Xz : a), And (skS.0 0 a_1 Xy Xz) (skS.0 2 a_1 a_2 a_3 Xy) → skS.0 2 a_1 a_2 a_3 Xz) →
% 3.58/3.78 skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2) → skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2))
% 3.58/3.78 False
% 3.58/3.78 Clause #9 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 : a) (a_3 : a → Prop),
% 3.58/3.78 Eq (skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2) → skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2)) False
% 3.58/3.78 Clause #14 (by clausification #[9]): ∀ (a_1 : a → a → Prop) (a_2 : a) (a_3 : a → Prop), Eq (skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2)) True
% 3.58/3.78 Clause #15 (by clausification #[9]): ∀ (a_1 : a → a → Prop) (a_2 : a) (a_3 : a → Prop), Eq (skS.0 2 a_1 a_2 a_3 (skS.0 1 a_1 a_2)) False
% 3.58/3.78 Clause #16 (by superposition #[15, 14]): Eq False True
% 3.58/3.78 Clause #17 (by clausification #[16]): False
% 3.58/3.78 SZS output end Proof for theBenchmark.p
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