TSTP Solution File: SEV079^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV079^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n002.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:12 EDT 2023
% Result : Theorem 3.58s 3.80s
% Output : Proof 3.58s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : SEV079^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.16 % Command : duper %s
% 0.14/0.37 % Computer : n002.cluster.edu
% 0.14/0.37 % Model : x86_64 x86_64
% 0.14/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.37 % Memory : 8042.1875MB
% 0.14/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.37 % CPULimit : 300
% 0.14/0.37 % WCLimit : 300
% 0.14/0.37 % DateTime : Thu Aug 24 02:08:46 EDT 2023
% 0.14/0.37 % CPUTime :
% 3.58/3.80 SZS status Theorem for theBenchmark.p
% 3.58/3.80 SZS output start Proof for theBenchmark.p
% 3.58/3.80 Clause #0 (by assumption #[]): Eq (Not (∀ (X Y Z : Iota), And (Eq X Y) (Eq Y Z) → Eq X Z)) True
% 3.58/3.80 Clause #1 (by clausification #[0]): Eq (∀ (X Y Z : Iota), And (Eq X Y) (Eq Y Z) → Eq X Z) False
% 3.58/3.80 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Not (∀ (Y Z : Iota), And (Eq (skS.0 0 a) Y) (Eq Y Z) → Eq (skS.0 0 a) Z)) True
% 3.58/3.80 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (Y Z : Iota), And (Eq (skS.0 0 a) Y) (Eq Y Z) → Eq (skS.0 0 a) Z) False
% 3.58/3.80 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota),
% 3.58/3.80 Eq (Not (∀ (Z : Iota), And (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq (skS.0 1 a a_1) Z) → Eq (skS.0 0 a) Z)) True
% 3.58/3.80 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota),
% 3.58/3.80 Eq (∀ (Z : Iota), And (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq (skS.0 1 a a_1) Z) → Eq (skS.0 0 a) Z) False
% 3.58/3.80 Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota),
% 3.58/3.80 Eq
% 3.58/3.80 (Not
% 3.58/3.80 (And (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)) →
% 3.58/3.80 Eq (skS.0 0 a) (skS.0 2 a a_1 a_2)))
% 3.58/3.80 True
% 3.58/3.80 Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 : Iota),
% 3.58/3.80 Eq
% 3.58/3.80 (And (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)) → Eq (skS.0 0 a) (skS.0 2 a a_1 a_2))
% 3.58/3.80 False
% 3.58/3.80 Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Eq (And (Eq (skS.0 0 a) (skS.0 1 a a_1)) (Eq (skS.0 1 a a_1) (skS.0 2 a a_1 a_2))) True
% 3.58/3.80 Clause #9 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Eq (Eq (skS.0 0 a) (skS.0 2 a a_1 a_2)) False
% 3.58/3.80 Clause #10 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Eq (Eq (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)) True
% 3.58/3.80 Clause #11 (by clausification #[8]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.58/3.80 Clause #12 (by clausification #[10]): ∀ (a a_1 a_2 : Iota), Eq (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)
% 3.58/3.80 Clause #13 (by clausification #[11]): ∀ (a a_1 : Iota), Eq (skS.0 0 a) (skS.0 1 a a_1)
% 3.58/3.80 Clause #14 (by backward demodulation #[13, 12]): ∀ (a a_1 a_2 : Iota), Eq (skS.0 0 a) (skS.0 2 a a_1 a_2)
% 3.58/3.80 Clause #15 (by clausification #[9]): ∀ (a a_1 a_2 : Iota), Ne (skS.0 0 a) (skS.0 2 a a_1 a_2)
% 3.58/3.80 Clause #16 (by forward demodulation #[15, 14]): ∀ (a : Iota), Ne (skS.0 0 a) (skS.0 0 a)
% 3.58/3.80 Clause #17 (by eliminate resolved literals #[16]): False
% 3.58/3.80 SZS output end Proof for theBenchmark.p
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