TSTP Solution File: SEV017^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV017^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n002.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:03 EDT 2023

% Result   : Theorem 3.81s 4.00s
% Output   : Proof 3.81s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : SEV017^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n002.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Thu Aug 24 03:27:46 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.81/4.00  SZS status Theorem for theBenchmark.p
% 3.81/4.00  SZS output start Proof for theBenchmark.p
% 3.81/4.00  Clause #0 (by assumption #[]): Eq
% 3.81/4.00    (Not
% 3.81/4.00      (∀ (Xr : a → a → Prop),
% 3.81/4.00        And (And (∀ (Xx : a), Xr Xx Xx) (∀ (Xx Xy : a), Xr Xx Xy → Xr Xy Xx))
% 3.81/4.00            (∀ (Xx Xy Xz : a), And (Xr Xx Xy) (Xr Xy Xz) → Xr Xx Xz) →
% 3.81/4.00          ∀ (Xx Xy Xz : a), Xr Xx Xy → Xr Xy Xz → Xr Xx Xz))
% 3.81/4.00    True
% 3.81/4.00  Clause #1 (by clausification #[0]): Eq
% 3.81/4.00    (∀ (Xr : a → a → Prop),
% 3.81/4.00      And (And (∀ (Xx : a), Xr Xx Xx) (∀ (Xx Xy : a), Xr Xx Xy → Xr Xy Xx))
% 3.81/4.00          (∀ (Xx Xy Xz : a), And (Xr Xx Xy) (Xr Xy Xz) → Xr Xx Xz) →
% 3.81/4.00        ∀ (Xx Xy Xz : a), Xr Xx Xy → Xr Xy Xz → Xr Xx Xz)
% 3.81/4.00    False
% 3.81/4.00  Clause #2 (by clausification #[1]): ∀ (a_1 : a → a → Prop),
% 3.81/4.00    Eq
% 3.81/4.00      (Not
% 3.81/4.00        (And (And (∀ (Xx : a), skS.0 0 a_1 Xx Xx) (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx))
% 3.81/4.00            (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) →
% 3.81/4.00          ∀ (Xx Xy Xz : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xz → skS.0 0 a_1 Xx Xz))
% 3.81/4.00      True
% 3.81/4.00  Clause #3 (by clausification #[2]): ∀ (a_1 : a → a → Prop),
% 3.81/4.00    Eq
% 3.81/4.00      (And (And (∀ (Xx : a), skS.0 0 a_1 Xx Xx) (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx))
% 3.81/4.00          (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) →
% 3.81/4.00        ∀ (Xx Xy Xz : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xz → skS.0 0 a_1 Xx Xz)
% 3.81/4.00      False
% 3.81/4.00  Clause #4 (by clausification #[3]): ∀ (a_1 : a → a → Prop),
% 3.81/4.00    Eq
% 3.81/4.00      (And (And (∀ (Xx : a), skS.0 0 a_1 Xx Xx) (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx))
% 3.81/4.00        (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz))
% 3.81/4.00      True
% 3.81/4.00  Clause #5 (by clausification #[3]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy Xz : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xz → skS.0 0 a_1 Xx Xz) False
% 3.81/4.00  Clause #6 (by clausification #[4]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) True
% 3.81/4.00  Clause #8 (by clausification #[6]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.81/4.00    Eq (∀ (Xy Xz : a), And (skS.0 0 a_1 a_2 Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 a_2 Xz) True
% 3.81/4.00  Clause #9 (by clausification #[8]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.81/4.00    Eq (∀ (Xz : a), And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 Xz) → skS.0 0 a_1 a_2 Xz) True
% 3.81/4.00  Clause #10 (by clausification #[9]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.00    Eq (And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 a_4) → skS.0 0 a_1 a_2 a_4) True
% 3.81/4.00  Clause #11 (by clausification #[10]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.00    Or (Eq (And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 a_4)) False) (Eq (skS.0 0 a_1 a_2 a_4) True)
% 3.81/4.00  Clause #12 (by clausification #[11]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.00    Or (Eq (skS.0 0 a_1 a_2 a_3) True) (Or (Eq (skS.0 0 a_1 a_2 a_4) False) (Eq (skS.0 0 a_1 a_4 a_3) False))
% 3.81/4.00  Clause #13 (by clausification #[5]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.81/4.00    Eq (Not (∀ (Xy Xz : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy → skS.0 0 a_1 Xy Xz → skS.0 0 a_1 (skS.0 1 a_1 a_2) Xz)) True
% 3.81/4.00  Clause #14 (by clausification #[13]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.81/4.00    Eq (∀ (Xy Xz : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy → skS.0 0 a_1 Xy Xz → skS.0 0 a_1 (skS.0 1 a_1 a_2) Xz) False
% 3.81/4.00  Clause #15 (by clausification #[14]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.81/4.00    Eq
% 3.81/4.00      (Not
% 3.81/4.00        (∀ (Xz : a),
% 3.81/4.00          skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.81/4.00            skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) Xz → skS.0 0 a_1 (skS.0 1 a_1 a_2) Xz))
% 3.81/4.00      True
% 3.81/4.00  Clause #16 (by clausification #[15]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.81/4.00    Eq
% 3.81/4.00      (∀ (Xz : a),
% 3.81/4.00        skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.81/4.00          skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) Xz → skS.0 0 a_1 (skS.0 1 a_1 a_2) Xz)
% 3.81/4.00      False
% 3.81/4.00  Clause #17 (by clausification #[16]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.00    Eq
% 3.81/4.00      (Not
% 3.81/4.00        (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.81/4.00          skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4) →
% 3.81/4.01            skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.81/4.01      True
% 3.81/4.01  Clause #18 (by clausification #[17]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Eq
% 3.81/4.01      (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) →
% 3.81/4.01        skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4) →
% 3.81/4.01          skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4))
% 3.81/4.01      False
% 3.81/4.01  Clause #19 (by clausification #[18]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True
% 3.81/4.01  Clause #20 (by clausification #[18]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Eq
% 3.81/4.01      (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4) →
% 3.81/4.01        skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4))
% 3.81/4.01      False
% 3.81/4.01  Clause #21 (by superposition #[19, 12]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3) True)
% 3.81/4.01      (Or (Eq True False) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_4) a_3) False))
% 3.81/4.01  Clause #31 (by clausification #[20]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a), Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)) True
% 3.81/4.01  Clause #32 (by clausification #[20]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4)) False
% 3.81/4.01  Clause #42 (by clausification #[21]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3) True) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_4) a_3) False)
% 3.81/4.01  Clause #43 (by superposition #[42, 31]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Or (Eq (skS.0 0 (fun x x_1 => a_1 x x_1) (skS.0 1 (fun x x_1 => a_1 x x_1) a_2) (skS.0 3 a_1 a_2 a_3 a_4)) True)
% 3.81/4.01      (Eq False True)
% 3.81/4.01  Clause #48 (by betaEtaReduce #[43]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.81/4.01    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4)) True) (Eq False True)
% 3.81/4.01  Clause #49 (by clausification #[48]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 3 a_1 a_2 a_3 a_4)) True
% 3.81/4.01  Clause #50 (by superposition #[49, 32]): Eq True False
% 3.81/4.01  Clause #53 (by clausification #[50]): False
% 3.81/4.01  SZS output end Proof for theBenchmark.p
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