%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEU976^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n104.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:27 EDT 2014

% Result   : Timeout 300.04s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEU976^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n104.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 11:47:26 CDT 2014
% % CPUTime  : 300.04 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1b0b830>, <kernel.Type object at 0x1b0bf38>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x1ce9098>, <kernel.DependentProduct object at 0x1b0bc68>) of role type named cR
% Using role type
% Declaring cR:(a->a)
% FOF formula (<kernel.Constant object at 0x1b0bdd0>, <kernel.DependentProduct object at 0x1b0b680>) of role type named cP
% Using role type
% Declaring cP:(a->(a->a))
% FOF formula (<kernel.Constant object at 0x1b0b7e8>, <kernel.DependentProduct object at 0x1b0b5f0>) of role type named cL
% Using role type
% Declaring cL:(a->a)
% FOF formula (<kernel.Constant object at 0x1b0bc68>, <kernel.Constant object at 0x1b0b5f0>) of role type named cZ
% Using role type
% Declaring cZ:a
% FOF formula (((and ((and ((and ((and ((and (((eq a) (cL cZ)) cZ)) (((eq a) (cR cZ)) cZ))) (forall (Xx:a) (Xy:a), (((eq a) (cL ((cP Xx) Xy))) Xx)))) (forall (Xx:a) (Xy:a), (((eq a) (cR ((cP Xx) Xy))) Xy)))) (forall (Xt:a), ((iff (not (((eq a) Xt) cZ))) (((eq a) Xt) ((cP (cL Xt)) (cR Xt))))))) (forall (X:(a->Prop)), ((forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((iff (((eq a) Xt) cZ)) (((eq a) Xu) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu))))))->(forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->(((eq a) Xt) Xu))))))->(forall (Xx:a) (Xy:a), (((and (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X ((cP Xx0) cZ)))))->(X Xx)))) (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X ((cP Xx0) cZ)))))->(X Xy))))->((or ((ex (a->Prop)) (fun (X:(a->Prop))=> ((and (X ((cP Xx) Xy))) (forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((((eq a) Xu) cZ)->(((eq a) Xt) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu)))))))))) ((ex (a->Prop)) (fun (X:(a->Prop))=> ((and (X ((cP Xy) Xx))) (forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((((eq a) Xu) cZ)->(((eq a) Xt) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu))))))))))))) of role conjecture named cPU_LEM3B_pme
% Conjecture to prove = (((and ((and ((and ((and ((and (((eq a) (cL cZ)) cZ)) (((eq a) (cR cZ)) cZ))) (forall (Xx:a) (Xy:a), (((eq a) (cL ((cP Xx) Xy))) Xx)))) (forall (Xx:a) (Xy:a), (((eq a) (cR ((cP Xx) Xy))) Xy)))) (forall (Xt:a), ((iff (not (((eq a) Xt) cZ))) (((eq a) Xt) ((cP (cL Xt)) (cR Xt))))))) (forall (X:(a->Prop)), ((forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((iff (((eq a) Xt) cZ)) (((eq a) Xu) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu))))))->(forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->(((eq a) Xt) Xu))))))->(forall (Xx:a) (Xy:a), (((and (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X ((cP Xx0) cZ)))))->(X Xx)))) (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X ((cP Xx0) cZ)))))->(X Xy))))->((or ((ex (a->Prop)) (fun (X:(a->Prop))=> ((and (X ((cP Xx) Xy))) (forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((((eq a) Xu) cZ)->(((eq a) Xt) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu)))))))))) ((ex (a->Prop)) (fun (X:(a->Prop))=> ((and (X ((cP Xy) Xx))) (forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((((eq a) Xu) cZ)->(((eq a) Xt) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu))))))))))))):Prop
% We need to prove ['(((and ((and ((and ((and ((and (((eq a) (cL cZ)) cZ)) (((eq a) (cR cZ)) cZ))) (forall (Xx:a) (Xy:a), (((eq a) (cL ((cP Xx) Xy))) Xx)))) (forall (Xx:a) (Xy:a), (((eq a) (cR ((cP Xx) Xy))) Xy)))) (forall (Xt:a), ((iff (not (((eq a) Xt) cZ))) (((eq a) Xt) ((cP (cL Xt)) (cR Xt))))))) (forall (X:(a->Prop)), ((forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->((and ((and ((iff (((eq a) Xt) cZ)) (((eq a) Xu) cZ))) (X ((cP (cL Xt)) (cL Xu))))) (X ((cP (cR Xt)) (cR Xu))))))->(forall (Xt:a) (Xu:a), ((X ((cP Xt) Xu))->(((eq a) Xt) Xu))))))->(forall (Xx:a) (Xy:a), (((and (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X ((cP Xx0) cZ)))))->(X Xx)))) (forall (X:(a->Prop)), (((and (X cZ)) (forall (Xx0:a), ((X Xx0)->(X
% EOF
%------------------------------------------------------------------------------