TSTP Solution File: SEU937^5 by Duper---1.0
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- Process Solution
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% File : Duper---1.0
% Problem : SEU937^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n012.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:44:21 EDT 2023
% Result : Theorem 3.59s 3.78s
% Output : Proof 3.59s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU937^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n012.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Wed Aug 23 18:36:57 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.59/3.78 SZS status Theorem for theBenchmark.p
% 3.59/3.78 SZS output start Proof for theBenchmark.p
% 3.59/3.78 Clause #0 (by assumption #[]): Eq
% 3.59/3.78 (Not
% 3.59/3.78 (∀ (F : b → a) (G : c → b),
% 3.59/3.78 And (∀ (Xx Xy : b), Eq (F Xx) (F Xy) → Eq Xx Xy) (∀ (Xx Xy : c), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (F (G Xx)) (F (G Xy)) → Eq Xx Xy))
% 3.59/3.78 True
% 3.59/3.78 Clause #1 (by clausification #[0]): Eq
% 3.59/3.78 (∀ (F : b → a) (G : c → b),
% 3.59/3.78 And (∀ (Xx Xy : b), Eq (F Xx) (F Xy) → Eq Xx Xy) (∀ (Xx Xy : c), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (F (G Xx)) (F (G Xy)) → Eq Xx Xy)
% 3.59/3.78 False
% 3.59/3.78 Clause #2 (by clausification #[1]): ∀ (a_1 : b → a),
% 3.59/3.78 Eq
% 3.59/3.78 (Not
% 3.59/3.78 (∀ (G : c → b),
% 3.59/3.78 And (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.59/3.78 (∀ (Xx Xy : c), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (skS.0 0 a_1 (G Xx)) (skS.0 0 a_1 (G Xy)) → Eq Xx Xy))
% 3.59/3.78 True
% 3.59/3.78 Clause #3 (by clausification #[2]): ∀ (a_1 : b → a),
% 3.59/3.78 Eq
% 3.59/3.78 (∀ (G : c → b),
% 3.59/3.78 And (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.59/3.78 (∀ (Xx Xy : c), Eq (G Xx) (G Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (skS.0 0 a_1 (G Xx)) (skS.0 0 a_1 (G Xy)) → Eq Xx Xy)
% 3.59/3.78 False
% 3.59/3.78 Clause #4 (by clausification #[3]): ∀ (a_1 : b → a) (a_2 : c → b),
% 3.59/3.78 Eq
% 3.59/3.78 (Not
% 3.59/3.78 (And (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.59/3.78 (∀ (Xx Xy : c), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xx)) (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xy)) → Eq Xx Xy))
% 3.59/3.78 True
% 3.59/3.78 Clause #5 (by clausification #[4]): ∀ (a_1 : b → a) (a_2 : c → b),
% 3.59/3.78 Eq
% 3.59/3.78 (And (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.59/3.78 (∀ (Xx Xy : c), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) →
% 3.59/3.78 ∀ (Xx Xy : c), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xx)) (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xy)) → Eq Xx Xy)
% 3.59/3.78 False
% 3.59/3.78 Clause #6 (by clausification #[5]): ∀ (a_1 : b → a) (a_2 : c → b),
% 3.59/3.78 Eq
% 3.59/3.78 (And (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy)
% 3.59/3.78 (∀ (Xx Xy : c), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy))
% 3.59/3.78 True
% 3.59/3.78 Clause #7 (by clausification #[5]): ∀ (a_1 : b → a) (a_2 : c → b),
% 3.59/3.78 Eq (∀ (Xx Xy : c), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xx)) (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xy)) → Eq Xx Xy) False
% 3.59/3.78 Clause #8 (by clausification #[6]): ∀ (a_1 : b → a) (a_2 : c → b), Eq (∀ (Xx Xy : c), Eq (skS.0 1 a_1 a_2 Xx) (skS.0 1 a_1 a_2 Xy) → Eq Xx Xy) True
% 3.59/3.78 Clause #9 (by clausification #[6]): ∀ (a_1 : b → a), Eq (∀ (Xx Xy : b), Eq (skS.0 0 a_1 Xx) (skS.0 0 a_1 Xy) → Eq Xx Xy) True
% 3.59/3.78 Clause #10 (by clausification #[8]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 : c), Eq (∀ (Xy : c), Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 Xy) → Eq a_3 Xy) True
% 3.59/3.78 Clause #11 (by clausification #[10]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c), Eq (Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4) → Eq a_3 a_4) True
% 3.59/3.78 Clause #12 (by clausification #[11]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.78 Or (Eq (Eq (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4)) False) (Eq (Eq a_3 a_4) True)
% 3.59/3.78 Clause #13 (by clausification #[12]): ∀ (a_1 a_2 : c) (a_3 : b → a) (a_4 : c → b), Or (Eq (Eq a_1 a_2) True) (Ne (skS.0 1 a_3 a_4 a_1) (skS.0 1 a_3 a_4 a_2))
% 3.59/3.78 Clause #14 (by clausification #[13]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c), Or (Ne (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 a_4)) (Eq a_3 a_4)
% 3.59/3.78 Clause #16 (by clausification #[9]): ∀ (a_1 : b → a) (a_2 : b), Eq (∀ (Xy : b), Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 Xy) → Eq a_2 Xy) True
% 3.59/3.78 Clause #17 (by clausification #[16]): ∀ (a_1 : b → a) (a_2 a_3 : b), Eq (Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3) → Eq a_2 a_3) True
% 3.59/3.78 Clause #18 (by clausification #[17]): ∀ (a_1 : b → a) (a_2 a_3 : b), Or (Eq (Eq (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3)) False) (Eq (Eq a_2 a_3) True)
% 3.59/3.78 Clause #19 (by clausification #[18]): ∀ (a_1 a_2 : b) (a_3 : b → a), Or (Eq (Eq a_1 a_2) True) (Ne (skS.0 0 a_3 a_1) (skS.0 0 a_3 a_2))
% 3.59/3.79 Clause #20 (by clausification #[19]): ∀ (a_1 : b → a) (a_2 a_3 : b), Or (Ne (skS.0 0 a_1 a_2) (skS.0 0 a_1 a_3)) (Eq a_2 a_3)
% 3.59/3.79 Clause #22 (by clausification #[7]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 : c),
% 3.59/3.79 Eq
% 3.59/3.79 (Not
% 3.59/3.79 (∀ (Xy : c),
% 3.59/3.79 Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xy)) →
% 3.59/3.79 Eq (skS.0 2 a_1 a_2 a_3) Xy))
% 3.59/3.79 True
% 3.59/3.79 Clause #23 (by clausification #[22]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 : c),
% 3.59/3.79 Eq
% 3.59/3.79 (∀ (Xy : c),
% 3.59/3.79 Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) (skS.0 0 a_1 (skS.0 1 a_1 a_2 Xy)) →
% 3.59/3.79 Eq (skS.0 2 a_1 a_2 a_3) Xy)
% 3.59/3.79 False
% 3.59/3.79 Clause #24 (by clausification #[23]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.79 Eq
% 3.59/3.79 (Not
% 3.59/3.79 (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))
% 3.59/3.79 (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4))) →
% 3.59/3.79 Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.59/3.79 True
% 3.59/3.79 Clause #25 (by clausification #[24]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.79 Eq
% 3.59/3.79 (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3)))
% 3.59/3.79 (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4))) →
% 3.59/3.79 Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4))
% 3.59/3.79 False
% 3.59/3.79 Clause #26 (by clausification #[25]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.79 Eq
% 3.59/3.79 (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4))))
% 3.59/3.79 True
% 3.59/3.79 Clause #27 (by clausification #[25]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c), Eq (Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)) False
% 3.59/3.79 Clause #28 (by clausification #[26]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.79 Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)))
% 3.59/3.79 Clause #29 (by superposition #[28, 20]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 : c) (a_4 : b) (a_5 : c),
% 3.59/3.79 Or (Ne (skS.0 0 a_1 (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))) (skS.0 0 a_1 a_4))
% 3.59/3.79 (Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_5)) a_4)
% 3.59/3.79 Clause #31 (by clausification #[27]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c), Ne (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)
% 3.59/3.79 Clause #32 (by equality resolution #[29]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c),
% 3.59/3.79 Eq (skS.0 1 a_1 a_2 (skS.0 3 a_1 a_2 a_3 a_4)) (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_3))
% 3.59/3.79 Clause #37 (by superposition #[32, 14]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 a_5 : c),
% 3.59/3.79 Or (Ne (skS.0 1 a_1 a_2 a_3) (skS.0 1 a_1 a_2 (skS.0 2 a_1 a_2 a_4))) (Eq a_3 (skS.0 3 a_1 a_2 a_4 a_5))
% 3.59/3.79 Clause #38 (by equality resolution #[37]): ∀ (a_1 : b → a) (a_2 : c → b) (a_3 a_4 : c), Eq (skS.0 2 a_1 a_2 a_3) (skS.0 3 a_1 a_2 a_3 a_4)
% 3.59/3.79 Clause #40 (by forward contextual literal cutting #[38, 31]): False
% 3.59/3.79 SZS output end Proof for theBenchmark.p
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