TSTP Solution File: SEU925^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU925^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n012.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:44:19 EDT 2023
% Result : Theorem 3.24s 3.58s
% Output : Proof 3.24s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SEU925^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n012.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Wed Aug 23 15:52:57 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.24/3.58 SZS status Theorem for theBenchmark.p
% 3.24/3.58 SZS output start Proof for theBenchmark.p
% 3.24/3.58 Clause #0 (by assumption #[]): Eq (Not (∀ (Xx Xy : Iota), (Eq (fun Xy0 => Eq Xx Xy0) fun Xy_2 => Eq Xy Xy_2) → Eq Xx Xy)) True
% 3.24/3.58 Clause #1 (by betaEtaReduce #[0]): Eq (Not (∀ (Xx Xy : Iota), Eq (Eq Xx) (Eq Xy) → Eq Xx Xy)) True
% 3.24/3.58 Clause #2 (by clausification #[1]): Eq (∀ (Xx Xy : Iota), Eq (Eq Xx) (Eq Xy) → Eq Xx Xy) False
% 3.24/3.58 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (Not (∀ (Xy : Iota), Eq (Eq (skS.0 0 a)) (Eq Xy) → Eq (skS.0 0 a) Xy)) True
% 3.24/3.58 Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (∀ (Xy : Iota), Eq (Eq (skS.0 0 a)) (Eq Xy) → Eq (skS.0 0 a) Xy) False
% 3.24/3.58 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (Not (Eq (Eq (skS.0 0 a)) (Eq (skS.0 1 a a_1)) → Eq (skS.0 0 a) (skS.0 1 a a_1))) True
% 3.24/3.58 Clause #6 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (Eq (Eq (skS.0 0 a)) (Eq (skS.0 1 a a_1)) → Eq (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.24/3.58 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (Eq (Eq (skS.0 0 a)) (Eq (skS.0 1 a a_1))) True
% 3.24/3.58 Clause #8 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.24/3.58 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (Eq (skS.0 0 a)) (Eq (skS.0 1 a a_1))
% 3.24/3.58 Clause #10 (by argument congruence #[9]): ∀ (a a_1 a_2 : Iota), Eq (Eq (skS.0 0 a) a_1) (Eq (skS.0 1 a a_2) a_1)
% 3.24/3.58 Clause #11 (by clausification #[8]): ∀ (a a_1 : Iota), Ne (skS.0 0 a) (skS.0 1 a a_1)
% 3.24/3.58 Clause #14 (by eqHoist #[10]): ∀ (a a_1 a_2 : Iota), Or (Eq (Eq (skS.0 0 a) a_1) False) (Eq (skS.0 1 a a_2) a_1)
% 3.24/3.58 Clause #15 (by clausification #[14]): ∀ (a a_1 a_2 : Iota), Or (Eq (skS.0 1 a a_1) a_2) (Ne (skS.0 0 a) a_2)
% 3.24/3.58 Clause #16 (by destructive equality resolution #[15]): ∀ (a a_1 : Iota), Eq (skS.0 1 a a_1) (skS.0 0 a)
% 3.24/3.58 Clause #17 (by forward contextual literal cutting #[16, 11]): False
% 3.24/3.58 SZS output end Proof for theBenchmark.p
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