TSTP Solution File: SEU922^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU922^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n006.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:44:19 EDT 2023
% Result : Theorem 3.52s 3.72s
% Output : Proof 3.52s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU922^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.34 % Computer : n006.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Wed Aug 23 13:04:38 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.52/3.72 SZS status Theorem for theBenchmark.p
% 3.52/3.72 SZS output start Proof for theBenchmark.p
% 3.52/3.72 Clause #0 (by assumption #[]): Eq (Not ((Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) → cP (f (f (g a))) → cP (g (f (f a))))) True
% 3.52/3.72 Clause #1 (by clausification #[0]): Eq ((Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) → cP (f (f (g a))) → cP (g (f (f a)))) False
% 3.52/3.72 Clause #2 (by clausification #[1]): Eq (Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) True
% 3.52/3.72 Clause #3 (by clausification #[1]): Eq (cP (f (f (g a))) → cP (g (f (f a)))) False
% 3.52/3.72 Clause #4 (by clausification #[2]): Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)
% 3.52/3.72 Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq ((fun Xx => f (g Xx)) a) ((fun Xx => g (f Xx)) a)
% 3.52/3.72 Clause #6 (by clausification #[3]): Eq (cP (f (f (g a)))) True
% 3.52/3.72 Clause #7 (by clausification #[3]): Eq (cP (g (f (f a)))) False
% 3.52/3.72 Clause #8 (by betaEtaReduce #[5]): ∀ (a : Iota), Eq (f (g a)) (g (f a))
% 3.52/3.72 Clause #9 (by backward demodulation #[8, 7]): Eq (cP (f (g (f a)))) False
% 3.52/3.72 Clause #10 (by forward demodulation #[9, 8]): Eq (cP (f (f (g a)))) False
% 3.52/3.72 Clause #11 (by superposition #[10, 6]): Eq False True
% 3.52/3.72 Clause #12 (by clausification #[11]): False
% 3.52/3.72 SZS output end Proof for theBenchmark.p
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