%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU919^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:44:18 EDT 2023

% Result   : Theorem 3.55s 3.71s
% Output   : Proof 3.55s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU919^5 : TPTP v8.1.2. Released v4.0.0.
% 0.13/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n004.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Wed Aug 23 18:49:53 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.55/3.71  SZS status Theorem for theBenchmark.p
% 3.55/3.71  SZS output start Proof for theBenchmark.p
% 3.55/3.71  Clause #0 (by assumption #[]): Eq (Not ((Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) → cP (f (g a)) → cP (g (f a)))) True
% 3.55/3.71  Clause #1 (by clausification #[0]): Eq ((Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) → cP (f (g a)) → cP (g (f a))) False
% 3.55/3.71  Clause #2 (by clausification #[1]): Eq (Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)) True
% 3.55/3.71  Clause #3 (by clausification #[1]): Eq (cP (f (g a)) → cP (g (f a))) False
% 3.55/3.71  Clause #4 (by clausification #[2]): Eq (fun Xx => f (g Xx)) fun Xx => g (f Xx)
% 3.55/3.71  Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq ((fun Xx => f (g Xx)) a) ((fun Xx => g (f Xx)) a)
% 3.55/3.71  Clause #6 (by clausification #[3]): Eq (cP (f (g a))) True
% 3.55/3.71  Clause #7 (by clausification #[3]): Eq (cP (g (f a))) False
% 3.55/3.71  Clause #8 (by betaEtaReduce #[5]): ∀ (a : Iota), Eq (f (g a)) (g (f a))
% 3.55/3.71  Clause #9 (by backward demodulation #[8, 6]): Eq (cP (g (f a))) True
% 3.55/3.71  Clause #10 (by superposition #[9, 7]): Eq True False
% 3.55/3.71  Clause #11 (by clausification #[10]): False
% 3.55/3.71  SZS output end Proof for theBenchmark.p
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