TSTP Solution File: SEU661^2 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SEU661^2 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:43:16 EDT 2023

% Result   : Theorem 3.18s 3.52s
% Output   : Proof 3.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU661^2 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n015.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Thu Aug 24 00:43:05 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.18/3.52  SZS status Theorem for theBenchmark.p
% 3.18/3.52  SZS output start Proof for theBenchmark.p
% 3.18/3.52  Clause #0 (by assumption #[]): Eq (Not (∀ (A B Xx : Iota), in Xx A → ∀ (Xy : Iota), in Xy B → Eq (kpair Xx Xy) (kpair Xx Xy))) True
% 3.18/3.52  Clause #1 (by clausification #[0]): Eq (∀ (A B Xx : Iota), in Xx A → ∀ (Xy : Iota), in Xy B → Eq (kpair Xx Xy) (kpair Xx Xy)) False
% 3.18/3.52  Clause #2 (by clausification #[1]): ∀ (a : Iota),
% 3.18/3.52    Eq (Not (∀ (B Xx : Iota), in Xx (skS.0 0 a) → ∀ (Xy : Iota), in Xy B → Eq (kpair Xx Xy) (kpair Xx Xy))) True
% 3.18/3.52  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (∀ (B Xx : Iota), in Xx (skS.0 0 a) → ∀ (Xy : Iota), in Xy B → Eq (kpair Xx Xy) (kpair Xx Xy)) False
% 3.18/3.52  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota),
% 3.18/3.52    Eq (Not (∀ (Xx : Iota), in Xx (skS.0 0 a) → ∀ (Xy : Iota), in Xy (skS.0 1 a a_1) → Eq (kpair Xx Xy) (kpair Xx Xy)))
% 3.18/3.52      True
% 3.18/3.52  Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota),
% 3.18/3.52    Eq (∀ (Xx : Iota), in Xx (skS.0 0 a) → ∀ (Xy : Iota), in Xy (skS.0 1 a a_1) → Eq (kpair Xx Xy) (kpair Xx Xy)) False
% 3.18/3.52  Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota),
% 3.18/3.52    Eq
% 3.18/3.52      (Not
% 3.18/3.52        (in (skS.0 2 a a_1 a_2) (skS.0 0 a) →
% 3.18/3.52          ∀ (Xy : Iota), in Xy (skS.0 1 a a_1) → Eq (kpair (skS.0 2 a a_1 a_2) Xy) (kpair (skS.0 2 a a_1 a_2) Xy)))
% 3.18/3.52      True
% 3.18/3.52  Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 : Iota),
% 3.18/3.52    Eq
% 3.18/3.52      (in (skS.0 2 a a_1 a_2) (skS.0 0 a) →
% 3.18/3.52        ∀ (Xy : Iota), in Xy (skS.0 1 a a_1) → Eq (kpair (skS.0 2 a a_1 a_2) Xy) (kpair (skS.0 2 a a_1 a_2) Xy))
% 3.18/3.52      False
% 3.18/3.52  Clause #9 (by clausification #[7]): ∀ (a a_1 a_2 : Iota),
% 3.18/3.52    Eq (∀ (Xy : Iota), in Xy (skS.0 1 a a_1) → Eq (kpair (skS.0 2 a a_1 a_2) Xy) (kpair (skS.0 2 a a_1 a_2) Xy)) False
% 3.18/3.52  Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.18/3.52    Eq
% 3.18/3.52      (Not
% 3.18/3.52        (in (skS.0 3 a a_1 a_2 a_3) (skS.0 1 a a_1) →
% 3.18/3.52          Eq (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3)) (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3))))
% 3.18/3.52      True
% 3.18/3.52  Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.18/3.52    Eq
% 3.18/3.52      (in (skS.0 3 a a_1 a_2 a_3) (skS.0 1 a a_1) →
% 3.18/3.52        Eq (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3)) (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3)))
% 3.18/3.52      False
% 3.18/3.52  Clause #13 (by clausification #[11]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.18/3.52    Eq (Eq (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3)) (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3))) False
% 3.18/3.52  Clause #14 (by clausification #[13]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.18/3.52    Ne (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3)) (kpair (skS.0 2 a a_1 a_2) (skS.0 3 a a_1 a_2 a_3))
% 3.18/3.52  Clause #15 (by eliminate resolved literals #[14]): False
% 3.18/3.52  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------