TSTP Solution File: SEU608^2 by Duper---1.0
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% File : Duper---1.0
% Problem : SEU608^2 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:42:58 EDT 2023
% Result : Theorem 3.50s 3.75s
% Output : Proof 3.50s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : SEU608^2 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.15 % Command : duper %s
% 0.16/0.37 % Computer : n007.cluster.edu
% 0.16/0.37 % Model : x86_64 x86_64
% 0.16/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37 % Memory : 8042.1875MB
% 0.16/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37 % CPULimit : 300
% 0.16/0.37 % WCLimit : 300
% 0.16/0.37 % DateTime : Wed Aug 23 20:35:54 EDT 2023
% 0.16/0.37 % CPUTime :
% 3.50/3.75 SZS status Theorem for theBenchmark.p
% 3.50/3.75 SZS output start Proof for theBenchmark.p
% 3.50/3.75 Clause #0 (by assumption #[]): Eq (Eq setminusER (∀ (A B Xx : Iota), in Xx (setminus A B) → Not (in Xx B))) True
% 3.50/3.75 Clause #1 (by assumption #[]): Eq (Not (setminusER → ∀ (A B Xx : Iota), in Xx B → Not (in Xx (setminus A B)))) True
% 3.50/3.75 Clause #2 (by clausification #[0]): Eq setminusER (∀ (A B Xx : Iota), in Xx (setminus A B) → Not (in Xx B))
% 3.50/3.75 Clause #19 (by clausification #[1]): Eq (setminusER → ∀ (A B Xx : Iota), in Xx B → Not (in Xx (setminus A B))) False
% 3.50/3.75 Clause #20 (by clausification #[19]): Eq setminusER True
% 3.50/3.75 Clause #21 (by clausification #[19]): Eq (∀ (A B Xx : Iota), in Xx B → Not (in Xx (setminus A B))) False
% 3.50/3.75 Clause #22 (by backward demodulation #[20, 2]): Eq True (∀ (A B Xx : Iota), in Xx (setminus A B) → Not (in Xx B))
% 3.50/3.75 Clause #27 (by clausification #[22]): ∀ (a : Iota), Eq (∀ (B Xx : Iota), in Xx (setminus a B) → Not (in Xx B)) True
% 3.50/3.75 Clause #28 (by clausification #[27]): ∀ (a a_1 : Iota), Eq (∀ (Xx : Iota), in Xx (setminus a a_1) → Not (in Xx a_1)) True
% 3.50/3.75 Clause #29 (by clausification #[28]): ∀ (a a_1 a_2 : Iota), Eq (in a (setminus a_1 a_2) → Not (in a a_2)) True
% 3.50/3.75 Clause #30 (by clausification #[29]): ∀ (a a_1 a_2 : Iota), Or (Eq (in a (setminus a_1 a_2)) False) (Eq (Not (in a a_2)) True)
% 3.50/3.75 Clause #31 (by clausification #[30]): ∀ (a a_1 a_2 : Iota), Or (Eq (in a (setminus a_1 a_2)) False) (Eq (in a a_2) False)
% 3.50/3.75 Clause #32 (by clausification #[21]): ∀ (a : Iota), Eq (Not (∀ (B Xx : Iota), in Xx B → Not (in Xx (setminus (skS.0 3 a) B)))) True
% 3.50/3.75 Clause #33 (by clausification #[32]): ∀ (a : Iota), Eq (∀ (B Xx : Iota), in Xx B → Not (in Xx (setminus (skS.0 3 a) B))) False
% 3.50/3.75 Clause #34 (by clausification #[33]): ∀ (a a_1 : Iota),
% 3.50/3.75 Eq (Not (∀ (Xx : Iota), in Xx (skS.0 4 a a_1) → Not (in Xx (setminus (skS.0 3 a) (skS.0 4 a a_1))))) True
% 3.50/3.75 Clause #35 (by clausification #[34]): ∀ (a a_1 : Iota), Eq (∀ (Xx : Iota), in Xx (skS.0 4 a a_1) → Not (in Xx (setminus (skS.0 3 a) (skS.0 4 a a_1)))) False
% 3.50/3.75 Clause #36 (by clausification #[35]): ∀ (a a_1 a_2 : Iota),
% 3.50/3.75 Eq
% 3.50/3.75 (Not (in (skS.0 5 a a_1 a_2) (skS.0 4 a a_1) → Not (in (skS.0 5 a a_1 a_2) (setminus (skS.0 3 a) (skS.0 4 a a_1)))))
% 3.50/3.75 True
% 3.50/3.75 Clause #37 (by clausification #[36]): ∀ (a a_1 a_2 : Iota),
% 3.50/3.75 Eq (in (skS.0 5 a a_1 a_2) (skS.0 4 a a_1) → Not (in (skS.0 5 a a_1 a_2) (setminus (skS.0 3 a) (skS.0 4 a a_1))))
% 3.50/3.75 False
% 3.50/3.75 Clause #38 (by clausification #[37]): ∀ (a a_1 a_2 : Iota), Eq (in (skS.0 5 a a_1 a_2) (skS.0 4 a a_1)) True
% 3.50/3.75 Clause #39 (by clausification #[37]): ∀ (a a_1 a_2 : Iota), Eq (Not (in (skS.0 5 a a_1 a_2) (setminus (skS.0 3 a) (skS.0 4 a a_1)))) False
% 3.50/3.75 Clause #40 (by clausification #[39]): ∀ (a a_1 a_2 : Iota), Eq (in (skS.0 5 a a_1 a_2) (setminus (skS.0 3 a) (skS.0 4 a a_1))) True
% 3.50/3.75 Clause #41 (by superposition #[40, 31]): ∀ (a a_1 a_2 : Iota), Or (Eq True False) (Eq (in (skS.0 5 a a_1 a_2) (skS.0 4 a a_1)) False)
% 3.50/3.75 Clause #42 (by clausification #[41]): ∀ (a a_1 a_2 : Iota), Eq (in (skS.0 5 a a_1 a_2) (skS.0 4 a a_1)) False
% 3.50/3.75 Clause #43 (by superposition #[42, 38]): Eq False True
% 3.50/3.75 Clause #44 (by clausification #[43]): False
% 3.50/3.75 SZS output end Proof for theBenchmark.p
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