TSTP Solution File: SEU186+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SEU186+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Tue Jul 19 14:34:48 EDT 2022

% Result   : Theorem 0.17s 0.42s
% Output   : Refutation 0.17s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (   8 unt;   2 nHn;  14 RR)
%            Number of literals    :   22 (   0 equ;  11 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   4 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    relation(skc5),
    file('SEU186+1.p',unknown),
    [] ).

cnf(11,axiom,
    ~ equal(skc5,empty_set),
    file('SEU186+1.p',unknown),
    [] ).

cnf(12,axiom,
    element(skf9(u),u),
    file('SEU186+1.p',unknown),
    [] ).

cnf(17,axiom,
    ~ in(ordered_pair(u,v),skc5),
    file('SEU186+1.p',unknown),
    [] ).

cnf(19,axiom,
    ( ~ empty(u)
    | equal(u,empty_set) ),
    file('SEU186+1.p',unknown),
    [] ).

cnf(25,axiom,
    ( ~ element(u,v)
    | empty(v)
    | in(u,v) ),
    file('SEU186+1.p',unknown),
    [] ).

cnf(28,axiom,
    ( ~ relation(u)
    | ~ in(v,u)
    | equal(ordered_pair(skf5(v),skf4(v)),v) ),
    file('SEU186+1.p',unknown),
    [] ).

cnf(30,plain,
    ( ~ in(u,skc5)
    | equal(ordered_pair(skf5(u),skf4(u)),u) ),
    inference(res,[status(thm),theory(equality)],[1,28]),
    [iquote('0:Res:1.0,28.0')] ).

cnf(31,plain,
    ~ empty(skc5),
    inference(res,[status(thm),theory(equality)],[19,11]),
    [iquote('0:Res:19.1,11.0')] ).

cnf(54,plain,
    ( empty(u)
    | in(skf9(u),u) ),
    inference(res,[status(thm),theory(equality)],[12,25]),
    [iquote('0:Res:12.0,25.0')] ).

cnf(78,plain,
    ( ~ in(u,skc5)
    | ~ in(u,skc5) ),
    inference(spl,[status(thm),theory(equality)],[30,17]),
    [iquote('0:SpL:30.1,17.0')] ).

cnf(81,plain,
    ~ in(u,skc5),
    inference(obv,[status(thm),theory(equality)],[78]),
    [iquote('0:Obv:78.0')] ).

cnf(83,plain,
    empty(skc5),
    inference(res,[status(thm),theory(equality)],[54,81]),
    [iquote('0:Res:54.1,81.0')] ).

cnf(84,plain,
    $false,
    inference(mrr,[status(thm)],[83,31]),
    [iquote('0:MRR:83.0,31.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.10  % Problem  : SEU186+1 : TPTP v8.1.0. Released v3.3.0.
% 0.06/0.11  % Command  : run_spass %d %s
% 0.12/0.32  % Computer : n027.cluster.edu
% 0.12/0.32  % Model    : x86_64 x86_64
% 0.12/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % Memory   : 8042.1875MB
% 0.12/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit : 300
% 0.12/0.32  % WCLimit  : 600
% 0.12/0.32  % DateTime : Sun Jun 19 15:32:24 EDT 2022
% 0.12/0.32  % CPUTime  : 
% 0.17/0.42  
% 0.17/0.42  SPASS V 3.9 
% 0.17/0.42  SPASS beiseite: Proof found.
% 0.17/0.42  % SZS status Theorem
% 0.17/0.42  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.17/0.42  SPASS derived 49 clauses, backtracked 0 clauses, performed 0 splits and kept 44 clauses.
% 0.17/0.42  SPASS allocated 97688 KBytes.
% 0.17/0.42  SPASS spent	0:00:00.09 on the problem.
% 0.17/0.42  		0:00:00.03 for the input.
% 0.17/0.42  		0:00:00.03 for the FLOTTER CNF translation.
% 0.17/0.42  		0:00:00.00 for inferences.
% 0.17/0.42  		0:00:00.00 for the backtracking.
% 0.17/0.42  		0:00:00.00 for the reduction.
% 0.17/0.42  
% 0.17/0.42  
% 0.17/0.42  Here is a proof with depth 3, length 14 :
% 0.17/0.42  % SZS output start Refutation
% See solution above
% 0.17/0.42  Formulae used in the proof : t56_relat_1 existence_m1_subset_1 t6_boole t2_subset d1_relat_1
% 0.17/0.42  
%------------------------------------------------------------------------------