TSTP Solution File: SEU158+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SEU158+1 : TPTP v8.1.2. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 16:40:30 EDT 2023
% Result : Theorem 3.66s 3.88s
% Output : Proof 3.66s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEU158+1 : TPTP v8.1.2. Released v3.3.0.
% 0.00/0.14 % Command : duper %s
% 0.16/0.35 % Computer : n001.cluster.edu
% 0.16/0.35 % Model : x86_64 x86_64
% 0.16/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.35 % Memory : 8042.1875MB
% 0.16/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.35 % CPULimit : 300
% 0.16/0.35 % WCLimit : 300
% 0.16/0.35 % DateTime : Wed Aug 23 16:16:54 EDT 2023
% 0.16/0.35 % CPUTime :
% 3.66/3.88 SZS status Theorem for theBenchmark.p
% 3.66/3.88 SZS output start Proof for theBenchmark.p
% 3.66/3.88 Clause #3 (by assumption #[]): Eq (Not (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B))) True
% 3.66/3.88 Clause #4 (by assumption #[]): Eq (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B)) True
% 3.66/3.88 Clause #11 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset (singleton a) B) (in a B)) True
% 3.66/3.88 Clause #12 (by clausification #[11]): ∀ (a a_1 : Iota), Eq (Iff (subset (singleton a) a_1) (in a a_1)) True
% 3.66/3.88 Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) a_1) True) (Eq (in a a_1) False)
% 3.66/3.88 Clause #14 (by clausification #[12]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton a) a_1) False) (Eq (in a a_1) True)
% 3.66/3.88 Clause #16 (by clausification #[3]): Eq (∀ (A B : Iota), Iff (subset (singleton A) B) (in A B)) False
% 3.66/3.88 Clause #17 (by clausification #[16]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Iff (subset (singleton (skS.0 0 a)) B) (in (skS.0 0 a) B))) True
% 3.66/3.88 Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (∀ (B : Iota), Iff (subset (singleton (skS.0 0 a)) B) (in (skS.0 0 a) B)) False
% 3.66/3.88 Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Eq (Not (Iff (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (in (skS.0 0 a) (skS.0 1 a a_1)))) True
% 3.66/3.88 Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Eq (Iff (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) (in (skS.0 0 a) (skS.0 1 a a_1))) False
% 3.66/3.88 Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota),
% 3.66/3.88 Or (Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) False) (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) False)
% 3.66/3.88 Clause #22 (by clausification #[20]): ∀ (a a_1 : Iota),
% 3.66/3.88 Or (Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) True) (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True)
% 3.66/3.88 Clause #29 (by superposition #[22, 14]): ∀ (a a_1 : Iota),
% 3.66/3.88 Or (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True) (Or (Eq True False) (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True))
% 3.66/3.88 Clause #31 (by clausification #[29]): ∀ (a a_1 : Iota), Or (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True) (Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True)
% 3.66/3.88 Clause #32 (by eliminate duplicate literals #[31]): ∀ (a a_1 : Iota), Eq (in (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.66/3.88 Clause #33 (by backward demodulation #[32, 21]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) False) (Eq True False)
% 3.66/3.88 Clause #36 (by superposition #[32, 13]): ∀ (a a_1 : Iota), Or (Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) True) (Eq True False)
% 3.66/3.88 Clause #38 (by clausification #[36]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) True
% 3.66/3.88 Clause #40 (by clausification #[33]): ∀ (a a_1 : Iota), Eq (subset (singleton (skS.0 0 a)) (skS.0 1 a a_1)) False
% 3.66/3.88 Clause #41 (by superposition #[40, 38]): Eq False True
% 3.66/3.88 Clause #42 (by clausification #[41]): False
% 3.66/3.88 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------