TSTP Solution File: SEU150+3 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SEU150+3 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Jul 19 07:10:56 EDT 2022

% Result   : Theorem 0.45s 1.07s
% Output   : Refutation 0.45s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SEU150+3 : TPTP v8.1.0. Released v3.2.0.
% 0.03/0.12  % Command  : bliksem %s
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Sun Jun 19 15:25:53 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.45/1.07  *** allocated 10000 integers for termspace/termends
% 0.45/1.07  *** allocated 10000 integers for clauses
% 0.45/1.07  *** allocated 10000 integers for justifications
% 0.45/1.07  Bliksem 1.12
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Automatic Strategy Selection
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Clauses:
% 0.45/1.07  
% 0.45/1.07  { unordered_pair( X, Y ) = unordered_pair( Y, X ) }.
% 0.45/1.07  { empty( skol1 ) }.
% 0.45/1.07  { ! empty( skol2 ) }.
% 0.45/1.07  { ! singleton( X ) = unordered_pair( Y, Z ), X = Y }.
% 0.45/1.07  { singleton( skol5 ) = unordered_pair( skol3, skol4 ) }.
% 0.45/1.07  { ! skol3 = skol4 }.
% 0.45/1.07  
% 0.45/1.07  percentage equality = 0.714286, percentage horn = 1.000000
% 0.45/1.07  This is a problem with some equality
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Options Used:
% 0.45/1.07  
% 0.45/1.07  useres =            1
% 0.45/1.07  useparamod =        1
% 0.45/1.07  useeqrefl =         1
% 0.45/1.07  useeqfact =         1
% 0.45/1.07  usefactor =         1
% 0.45/1.07  usesimpsplitting =  0
% 0.45/1.07  usesimpdemod =      5
% 0.45/1.07  usesimpres =        3
% 0.45/1.07  
% 0.45/1.07  resimpinuse      =  1000
% 0.45/1.07  resimpclauses =     20000
% 0.45/1.07  substype =          eqrewr
% 0.45/1.07  backwardsubs =      1
% 0.45/1.07  selectoldest =      5
% 0.45/1.07  
% 0.45/1.07  litorderings [0] =  split
% 0.45/1.07  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.45/1.07  
% 0.45/1.07  termordering =      kbo
% 0.45/1.07  
% 0.45/1.07  litapriori =        0
% 0.45/1.07  termapriori =       1
% 0.45/1.07  litaposteriori =    0
% 0.45/1.07  termaposteriori =   0
% 0.45/1.07  demodaposteriori =  0
% 0.45/1.07  ordereqreflfact =   0
% 0.45/1.07  
% 0.45/1.07  litselect =         negord
% 0.45/1.07  
% 0.45/1.07  maxweight =         15
% 0.45/1.07  maxdepth =          30000
% 0.45/1.07  maxlength =         115
% 0.45/1.07  maxnrvars =         195
% 0.45/1.07  excuselevel =       1
% 0.45/1.07  increasemaxweight = 1
% 0.45/1.07  
% 0.45/1.07  maxselected =       10000000
% 0.45/1.07  maxnrclauses =      10000000
% 0.45/1.07  
% 0.45/1.07  showgenerated =    0
% 0.45/1.07  showkept =         0
% 0.45/1.07  showselected =     0
% 0.45/1.07  showdeleted =      0
% 0.45/1.07  showresimp =       1
% 0.45/1.07  showstatus =       2000
% 0.45/1.07  
% 0.45/1.07  prologoutput =     0
% 0.45/1.07  nrgoals =          5000000
% 0.45/1.07  totalproof =       1
% 0.45/1.07  
% 0.45/1.07  Symbols occurring in the translation:
% 0.45/1.07  
% 0.45/1.07  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.45/1.07  .  [1, 2]      (w:1, o:21, a:1, s:1, b:0), 
% 0.45/1.07  !  [4, 1]      (w:0, o:14, a:1, s:1, b:0), 
% 0.45/1.07  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.45/1.07  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.45/1.07  unordered_pair  [37, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.45/1.07  empty  [38, 1]      (w:1, o:19, a:1, s:1, b:0), 
% 0.45/1.07  singleton  [40, 1]      (w:1, o:20, a:1, s:1, b:0), 
% 0.45/1.07  skol1  [41, 0]      (w:1, o:9, a:1, s:1, b:1), 
% 0.45/1.07  skol2  [42, 0]      (w:1, o:10, a:1, s:1, b:1), 
% 0.45/1.07  skol3  [43, 0]      (w:1, o:11, a:1, s:1, b:1), 
% 0.45/1.07  skol4  [44, 0]      (w:1, o:12, a:1, s:1, b:1), 
% 0.45/1.07  skol5  [45, 0]      (w:1, o:13, a:1, s:1, b:1).
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Starting Search:
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Bliksems!, er is een bewijs:
% 0.45/1.07  % SZS status Theorem
% 0.45/1.07  % SZS output start Refutation
% 0.45/1.07  
% 0.45/1.07  (0) {G0,W7,D3,L1,V2,M1} I { unordered_pair( X, Y ) = unordered_pair( Y, X )
% 0.45/1.07     }.
% 0.45/1.07  (3) {G0,W9,D3,L2,V3,M2} I { ! singleton( X ) = unordered_pair( Y, Z ), X = 
% 0.45/1.07    Y }.
% 0.45/1.07  (4) {G0,W6,D3,L1,V0,M1} I { unordered_pair( skol3, skol4 ) ==> singleton( 
% 0.45/1.07    skol5 ) }.
% 0.45/1.07  (5) {G0,W3,D2,L1,V0,M1} I { ! skol4 ==> skol3 }.
% 0.45/1.07  (6) {G1,W6,D3,L1,V0,M1} P(0,4) { unordered_pair( skol4, skol3 ) ==> 
% 0.45/1.07    singleton( skol5 ) }.
% 0.45/1.07  (15) {G1,W8,D3,L2,V1,M2} P(4,3) { ! singleton( X ) = singleton( skol5 ), X 
% 0.45/1.07    = skol3 }.
% 0.45/1.07  (21) {G1,W9,D3,L2,V2,M2} P(3,5) { ! X = skol3, ! singleton( X ) = 
% 0.45/1.07    unordered_pair( skol4, Y ) }.
% 0.45/1.07  (26) {G2,W6,D3,L1,V1,M1} Q(21) { ! unordered_pair( skol4, X ) ==> singleton
% 0.45/1.07    ( skol3 ) }.
% 0.45/1.07  (28) {G2,W3,D2,L1,V0,M1} Q(15) { skol5 ==> skol3 }.
% 0.45/1.07  (51) {G3,W0,D0,L0,V0,M0} S(6);d(28);r(26) {  }.
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  % SZS output end Refutation
% 0.45/1.07  found a proof!
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Unprocessed initial clauses:
% 0.45/1.07  
% 0.45/1.07  (53) {G0,W7,D3,L1,V2,M1}  { unordered_pair( X, Y ) = unordered_pair( Y, X )
% 0.45/1.07     }.
% 0.45/1.07  (54) {G0,W2,D2,L1,V0,M1}  { empty( skol1 ) }.
% 0.45/1.07  (55) {G0,W2,D2,L1,V0,M1}  { ! empty( skol2 ) }.
% 0.45/1.07  (56) {G0,W9,D3,L2,V3,M2}  { ! singleton( X ) = unordered_pair( Y, Z ), X = 
% 0.45/1.07    Y }.
% 0.45/1.07  (57) {G0,W6,D3,L1,V0,M1}  { singleton( skol5 ) = unordered_pair( skol3, 
% 0.45/1.07    skol4 ) }.
% 0.45/1.07  (58) {G0,W3,D2,L1,V0,M1}  { ! skol3 = skol4 }.
% 0.45/1.07  
% 0.45/1.07  
% 0.45/1.07  Total Proof:
% 0.45/1.07  
% 0.45/1.07  subsumption: (0) {G0,W7,D3,L1,V2,M1} I { unordered_pair( X, Y ) = 
% 0.45/1.07    unordered_pair( Y, X ) }.
% 0.45/1.07  parent0: (53) {G0,W7,D3,L1,V2,M1}  { unordered_pair( X, Y ) = 
% 0.45/1.07    unordered_pair( Y, X ) }.
% 0.45/1.07  substitution0:
% 0.45/1.07     X := X
% 0.45/1.07     Y := Y
% 0.45/1.07  end
% 0.45/1.07  permutation0:
% 0.45/1.07     0 ==> 0
% 0.45/1.07  end
% 0.45/1.07  
% 0.45/1.07  subsumption: (3) {G0,W9,D3,L2,V3,M2} I { ! singleton( X ) = unordered_pair
% 0.45/1.07    ( Y, Z ), X = Y }.
% 0.45/1.07  parent0: (56) {G0,W9,D3,L2,V3,M2}  { ! singleton( X ) = unordered_pair( Y, 
% 0.45/1.07    Z ), X = Y }.
% 0.45/1.07  substitution0:
% 0.45/1.07     X := X
% 0.45/1.07     Y := Y
% 0.45/1.07     Z := Z
% 0.45/1.07  end
% 0.45/1.07  permutation0:
% 0.45/1.07     0 ==> 0
% 0.45/1.07     1 ==> 1
% 0.45/1.07  end
% 0.45/1.07  
% 0.45/1.07  eqswap: (65) Cputime limit exceeded (core dumped)
%------------------------------------------------------------------------------