TSTP Solution File: SEU116+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEU116+1 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 16:40:15 EDT 2023

% Result   : Theorem 3.96s 4.15s
% Output   : Proof 3.96s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEU116+1 : TPTP v8.1.2. Released v3.2.0.
% 0.00/0.14  % Command    : duper %s
% 0.15/0.35  % Computer : n022.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35  % CPULimit   : 300
% 0.15/0.35  % WCLimit    : 300
% 0.15/0.35  % DateTime   : Wed Aug 23 16:18:56 EDT 2023
% 0.15/0.35  % CPUTime    : 
% 3.96/4.15  SZS status Theorem for theBenchmark.p
% 3.96/4.15  SZS output start Proof for theBenchmark.p
% 3.96/4.15  Clause #20 (by assumption #[]): Eq (∀ (A B : Iota), element B (finite_subsets A) → finite B) True
% 3.96/4.15  Clause #29 (by assumption #[]): Eq (Not (∀ (A B : Iota), element B (finite_subsets A) → finite B)) True
% 3.96/4.15  Clause #40 (by clausification #[20]): ∀ (a : Iota), Eq (∀ (B : Iota), element B (finite_subsets a) → finite B) True
% 3.96/4.15  Clause #41 (by clausification #[40]): ∀ (a a_1 : Iota), Eq (element a (finite_subsets a_1) → finite a) True
% 3.96/4.15  Clause #42 (by clausification #[41]): ∀ (a a_1 : Iota), Or (Eq (element a (finite_subsets a_1)) False) (Eq (finite a) True)
% 3.96/4.15  Clause #48 (by clausification #[29]): Eq (∀ (A B : Iota), element B (finite_subsets A) → finite B) False
% 3.96/4.15  Clause #49 (by clausification #[48]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), element B (finite_subsets (skS.0 1 a)) → finite B)) True
% 3.96/4.15  Clause #50 (by clausification #[49]): ∀ (a : Iota), Eq (∀ (B : Iota), element B (finite_subsets (skS.0 1 a)) → finite B) False
% 3.96/4.15  Clause #51 (by clausification #[50]): ∀ (a a_1 : Iota), Eq (Not (element (skS.0 2 a a_1) (finite_subsets (skS.0 1 a)) → finite (skS.0 2 a a_1))) True
% 3.96/4.15  Clause #52 (by clausification #[51]): ∀ (a a_1 : Iota), Eq (element (skS.0 2 a a_1) (finite_subsets (skS.0 1 a)) → finite (skS.0 2 a a_1)) False
% 3.96/4.15  Clause #53 (by clausification #[52]): ∀ (a a_1 : Iota), Eq (element (skS.0 2 a a_1) (finite_subsets (skS.0 1 a))) True
% 3.96/4.15  Clause #54 (by clausification #[52]): ∀ (a a_1 : Iota), Eq (finite (skS.0 2 a a_1)) False
% 3.96/4.15  Clause #55 (by superposition #[53, 42]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (finite (skS.0 2 a a_1)) True)
% 3.96/4.15  Clause #215 (by clausification #[55]): ∀ (a a_1 : Iota), Eq (finite (skS.0 2 a a_1)) True
% 3.96/4.15  Clause #216 (by superposition #[215, 54]): Eq True False
% 3.96/4.15  Clause #218 (by clausification #[216]): False
% 3.96/4.15  SZS output end Proof for theBenchmark.p
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