TSTP Solution File: SET915+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SET915+1 : TPTP v8.1.2. Released v3.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 14:48:02 EDT 2023
% Result : Theorem 3.73s 3.90s
% Output : Proof 3.73s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SET915+1 : TPTP v8.1.2. Released v3.2.0.
% 0.00/0.13 % Command : duper %s
% 0.15/0.35 % Computer : n014.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.35 % WCLimit : 300
% 0.15/0.35 % DateTime : Sat Aug 26 09:36:02 EDT 2023
% 0.15/0.35 % CPUTime :
% 3.73/3.90 SZS status Theorem for theBenchmark.p
% 3.73/3.90 SZS output start Proof for theBenchmark.p
% 3.73/3.90 Clause #4 (by assumption #[]): Eq (Not (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B)) True
% 3.73/3.90 Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B) True
% 3.73/3.90 Clause #17 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (in a B) → disjoint (singleton a) B) True
% 3.73/3.90 Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota), Eq (Not (in a a_1) → disjoint (singleton a) a_1) True
% 3.73/3.90 Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Or (Eq (Not (in a a_1)) False) (Eq (disjoint (singleton a) a_1) True)
% 3.73/3.90 Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Or (Eq (disjoint (singleton a) a_1) True) (Eq (in a a_1) True)
% 3.73/3.90 Clause #22 (by clausification #[4]): Eq (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B) False
% 3.73/3.90 Clause #23 (by clausification #[22]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Not (in (skS.0 2 a) B) → disjoint (singleton (skS.0 2 a)) B)) True
% 3.73/3.90 Clause #24 (by clausification #[23]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (in (skS.0 2 a) B) → disjoint (singleton (skS.0 2 a)) B) False
% 3.73/3.90 Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota),
% 3.73/3.90 Eq (Not (Not (in (skS.0 2 a) (skS.0 3 a a_1)) → disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1))) True
% 3.73/3.90 Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Eq (Not (in (skS.0 2 a) (skS.0 3 a a_1)) → disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False
% 3.73/3.90 Clause #27 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (Not (in (skS.0 2 a) (skS.0 3 a a_1))) True
% 3.73/3.90 Clause #28 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False
% 3.73/3.90 Clause #29 (by clausification #[27]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) False
% 3.73/3.90 Clause #30 (by superposition #[29, 20]): ∀ (a a_1 : Iota), Or (Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True) (Eq False True)
% 3.73/3.90 Clause #52 (by clausification #[30]): ∀ (a a_1 : Iota), Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True
% 3.73/3.90 Clause #53 (by superposition #[52, 28]): Eq True False
% 3.73/3.90 Clause #55 (by clausification #[53]): False
% 3.73/3.90 SZS output end Proof for theBenchmark.p
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