TSTP Solution File: SET915+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SET915+1 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:48:02 EDT 2023

% Result   : Theorem 3.73s 3.90s
% Output   : Proof 3.73s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SET915+1 : TPTP v8.1.2. Released v3.2.0.
% 0.00/0.13  % Command    : duper %s
% 0.15/0.35  % Computer : n014.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35  % CPULimit   : 300
% 0.15/0.35  % WCLimit    : 300
% 0.15/0.35  % DateTime   : Sat Aug 26 09:36:02 EDT 2023
% 0.15/0.35  % CPUTime    : 
% 3.73/3.90  SZS status Theorem for theBenchmark.p
% 3.73/3.90  SZS output start Proof for theBenchmark.p
% 3.73/3.90  Clause #4 (by assumption #[]): Eq (Not (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B)) True
% 3.73/3.90  Clause #5 (by assumption #[]): Eq (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B) True
% 3.73/3.90  Clause #17 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (in a B) → disjoint (singleton a) B) True
% 3.73/3.90  Clause #18 (by clausification #[17]): ∀ (a a_1 : Iota), Eq (Not (in a a_1) → disjoint (singleton a) a_1) True
% 3.73/3.90  Clause #19 (by clausification #[18]): ∀ (a a_1 : Iota), Or (Eq (Not (in a a_1)) False) (Eq (disjoint (singleton a) a_1) True)
% 3.73/3.90  Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Or (Eq (disjoint (singleton a) a_1) True) (Eq (in a a_1) True)
% 3.73/3.90  Clause #22 (by clausification #[4]): Eq (∀ (A B : Iota), Not (in A B) → disjoint (singleton A) B) False
% 3.73/3.90  Clause #23 (by clausification #[22]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), Not (in (skS.0 2 a) B) → disjoint (singleton (skS.0 2 a)) B)) True
% 3.73/3.90  Clause #24 (by clausification #[23]): ∀ (a : Iota), Eq (∀ (B : Iota), Not (in (skS.0 2 a) B) → disjoint (singleton (skS.0 2 a)) B) False
% 3.73/3.90  Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota),
% 3.73/3.90    Eq (Not (Not (in (skS.0 2 a) (skS.0 3 a a_1)) → disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1))) True
% 3.73/3.90  Clause #26 (by clausification #[25]): ∀ (a a_1 : Iota), Eq (Not (in (skS.0 2 a) (skS.0 3 a a_1)) → disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False
% 3.73/3.90  Clause #27 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (Not (in (skS.0 2 a) (skS.0 3 a a_1))) True
% 3.73/3.90  Clause #28 (by clausification #[26]): ∀ (a a_1 : Iota), Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) False
% 3.73/3.90  Clause #29 (by clausification #[27]): ∀ (a a_1 : Iota), Eq (in (skS.0 2 a) (skS.0 3 a a_1)) False
% 3.73/3.90  Clause #30 (by superposition #[29, 20]): ∀ (a a_1 : Iota), Or (Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True) (Eq False True)
% 3.73/3.90  Clause #52 (by clausification #[30]): ∀ (a a_1 : Iota), Eq (disjoint (singleton (skS.0 2 a)) (skS.0 3 a a_1)) True
% 3.73/3.90  Clause #53 (by superposition #[52, 28]): Eq True False
% 3.73/3.90  Clause #55 (by clausification #[53]): False
% 3.73/3.90  SZS output end Proof for theBenchmark.p
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