TSTP Solution File: SET632+3 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET632+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:13:56 EDT 2022

% Result   : Theorem 1.65s 1.89s
% Output   : Refutation 1.65s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :   15
% Syntax   : Number of clauses     :   30 (  12 unt;  11 nHn;  17 RR)
%            Number of literals    :   52 (   5 equ;  15 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    7 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   4 con; 0-2 aty)
%            Number of variables   :   36 (   8 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ subset(A,B)
    | ~ member(C,A)
    | member(C,B) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ intersect(A,B)
    | member(dollar_f2(A,B),B) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(5,axiom,
    ( intersect(A,B)
    | ~ member(C,A)
    | ~ member(C,B) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(6,axiom,
    ~ member(A,empty_set),
    file('SET632+3.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ disjoint(A,B)
    | ~ intersect(A,B) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(10,axiom,
    ( A = B
    | ~ subset(A,B)
    | ~ subset(B,A) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(11,axiom,
    ( ~ intersect(A,B)
    | intersect(B,A) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ empty(A)
    | ~ member(B,A) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(13,axiom,
    dollar_c3 != empty_set,
    file('SET632+3.p',unknown),
    [] ).

cnf(14,plain,
    empty_set != dollar_c3,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[13])]),
    [iquote('copy,13,flip.1')] ).

cnf(18,axiom,
    ( subset(A,B)
    | member(dollar_f1(A,B),A) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(19,axiom,
    ( disjoint(A,B)
    | intersect(A,B) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(21,axiom,
    ( empty(A)
    | member(dollar_f3(A),A) ),
    file('SET632+3.p',unknown),
    [] ).

cnf(22,axiom,
    subset(dollar_c3,dollar_c2),
    file('SET632+3.p',unknown),
    [] ).

cnf(23,axiom,
    subset(dollar_c3,dollar_c1),
    file('SET632+3.p',unknown),
    [] ).

cnf(24,axiom,
    disjoint(dollar_c2,dollar_c1),
    file('SET632+3.p',unknown),
    [] ).

cnf(33,plain,
    ( member(dollar_f1(A,B),A)
    | B = A
    | member(dollar_f1(B,A),B) ),
    inference(hyper,[status(thm)],[18,10,18]),
    [iquote('hyper,18,10,18')] ).

cnf(35,plain,
    ( disjoint(A,B)
    | intersect(B,A) ),
    inference(hyper,[status(thm)],[19,11]),
    [iquote('hyper,19,11')] ).

cnf(36,plain,
    ( disjoint(A,B)
    | member(dollar_f2(A,B),B) ),
    inference(hyper,[status(thm)],[19,4]),
    [iquote('hyper,19,4')] ).

cnf(39,plain,
    disjoint(dollar_c1,dollar_c2),
    inference(hyper,[status(thm)],[35,7,24]),
    [iquote('hyper,35,7,24')] ).

cnf(152,plain,
    ( disjoint(A,B)
    | member(dollar_f3(B),B) ),
    inference(hyper,[status(thm)],[36,12,21]),
    [iquote('hyper,36,12,21')] ).

cnf(166,plain,
    ( disjoint(A,dollar_c3)
    | member(dollar_f3(dollar_c3),dollar_c1) ),
    inference(hyper,[status(thm)],[152,1,23]),
    [iquote('hyper,152,1,23')] ).

cnf(167,plain,
    ( disjoint(A,dollar_c3)
    | member(dollar_f3(dollar_c3),dollar_c2) ),
    inference(hyper,[status(thm)],[152,1,22]),
    [iquote('hyper,152,1,22')] ).

cnf(218,plain,
    ( disjoint(A,dollar_c3)
    | intersect(dollar_c1,dollar_c2) ),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[167,5,166])]),
    [iquote('hyper,167,5,166,factor_simp')] ).

cnf(241,plain,
    disjoint(A,dollar_c3),
    inference(hyper,[status(thm)],[218,7,39]),
    [iquote('hyper,218,7,39')] ).

cnf(242,plain,
    disjoint(dollar_c3,A),
    inference(hyper,[status(thm)],[241,7,35]),
    [iquote('hyper,241,7,35')] ).

cnf(255,plain,
    ( A = empty_set
    | member(dollar_f1(A,empty_set),A) ),
    inference(hyper,[status(thm)],[33,6]),
    [iquote('hyper,33,6')] ).

cnf(546,plain,
    member(dollar_f1(dollar_c3,empty_set),dollar_c1),
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[255,1,23]),14]),
    [iquote('hyper,255,1,23,unit_del,14')] ).

cnf(636,plain,
    intersect(dollar_c3,dollar_c1),
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[546,5,255]),14]),
    [iquote('hyper,546,5,255,unit_del,14')] ).

cnf(698,plain,
    $false,
    inference(hyper,[status(thm)],[636,7,242]),
    [iquote('hyper,636,7,242')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem  : SET632+3 : TPTP v8.1.0. Released v2.2.0.
% 0.03/0.13  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n022.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 10:42:05 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 1.65/1.89  ----- Otter 3.3f, August 2004 -----
% 1.65/1.89  The process was started by sandbox2 on n022.cluster.edu,
% 1.65/1.89  Wed Jul 27 10:42:05 2022
% 1.65/1.89  The command was "./otter".  The process ID is 22857.
% 1.65/1.89  
% 1.65/1.89  set(prolog_style_variables).
% 1.65/1.89  set(auto).
% 1.65/1.89     dependent: set(auto1).
% 1.65/1.89     dependent: set(process_input).
% 1.65/1.89     dependent: clear(print_kept).
% 1.65/1.89     dependent: clear(print_new_demod).
% 1.65/1.89     dependent: clear(print_back_demod).
% 1.65/1.89     dependent: clear(print_back_sub).
% 1.65/1.89     dependent: set(control_memory).
% 1.65/1.89     dependent: assign(max_mem, 12000).
% 1.65/1.89     dependent: assign(pick_given_ratio, 4).
% 1.65/1.89     dependent: assign(stats_level, 1).
% 1.65/1.89     dependent: assign(max_seconds, 10800).
% 1.65/1.89  clear(print_given).
% 1.65/1.89  
% 1.65/1.89  formula_list(usable).
% 1.65/1.89  all A (A=A).
% 1.65/1.89  all B C (subset(B,C)<-> (all D (member(D,B)->member(D,C)))).
% 1.65/1.89  all B C (intersect(B,C)<-> (exists D (member(D,B)&member(D,C)))).
% 1.65/1.89  all B (-member(B,empty_set)).
% 1.65/1.89  all B C (disjoint(B,C)<-> -intersect(B,C)).
% 1.65/1.89  all B C (B=C<->subset(B,C)&subset(C,B)).
% 1.65/1.89  all B C (intersect(B,C)->intersect(C,B)).
% 1.65/1.89  all B subset(B,B).
% 1.65/1.89  all B (empty(B)<-> (all C (-member(C,B)))).
% 1.65/1.89  -(all B C D (subset(B,C)&subset(B,D)&disjoint(C,D)->B=empty_set)).
% 1.65/1.89  end_of_list.
% 1.65/1.89  
% 1.65/1.89  -------> usable clausifies to:
% 1.65/1.89  
% 1.65/1.89  list(usable).
% 1.65/1.89  0 [] A=A.
% 1.65/1.89  0 [] -subset(B,C)| -member(D,B)|member(D,C).
% 1.65/1.89  0 [] subset(B,C)|member($f1(B,C),B).
% 1.65/1.89  0 [] subset(B,C)| -member($f1(B,C),C).
% 1.65/1.89  0 [] -intersect(B,C)|member($f2(B,C),B).
% 1.65/1.89  0 [] -intersect(B,C)|member($f2(B,C),C).
% 1.65/1.89  0 [] intersect(B,C)| -member(D,B)| -member(D,C).
% 1.65/1.89  0 [] -member(B,empty_set).
% 1.65/1.89  0 [] -disjoint(B,C)| -intersect(B,C).
% 1.65/1.89  0 [] disjoint(B,C)|intersect(B,C).
% 1.65/1.89  0 [] B!=C|subset(B,C).
% 1.65/1.89  0 [] B!=C|subset(C,B).
% 1.65/1.89  0 [] B=C| -subset(B,C)| -subset(C,B).
% 1.65/1.89  0 [] -intersect(B,C)|intersect(C,B).
% 1.65/1.89  0 [] subset(B,B).
% 1.65/1.89  0 [] -empty(B)| -member(C,B).
% 1.65/1.89  0 [] empty(B)|member($f3(B),B).
% 1.65/1.89  0 [] subset($c3,$c2).
% 1.65/1.89  0 [] subset($c3,$c1).
% 1.65/1.89  0 [] disjoint($c2,$c1).
% 1.65/1.89  0 [] $c3!=empty_set.
% 1.65/1.89  end_of_list.
% 1.65/1.89  
% 1.65/1.89  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=3.
% 1.65/1.89  
% 1.65/1.89  This ia a non-Horn set with equality.  The strategy will be
% 1.65/1.89  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.65/1.89  deletion, with positive clauses in sos and nonpositive
% 1.65/1.89  clauses in usable.
% 1.65/1.89  
% 1.65/1.89     dependent: set(knuth_bendix).
% 1.65/1.89     dependent: set(anl_eq).
% 1.65/1.89     dependent: set(para_from).
% 1.65/1.89     dependent: set(para_into).
% 1.65/1.89     dependent: clear(para_from_right).
% 1.65/1.89     dependent: clear(para_into_right).
% 1.65/1.89     dependent: set(para_from_vars).
% 1.65/1.89     dependent: set(eq_units_both_ways).
% 1.65/1.89     dependent: set(dynamic_demod_all).
% 1.65/1.89     dependent: set(dynamic_demod).
% 1.65/1.89     dependent: set(order_eq).
% 1.65/1.89     dependent: set(back_demod).
% 1.65/1.89     dependent: set(lrpo).
% 1.65/1.89     dependent: set(hyper_res).
% 1.65/1.89     dependent: set(unit_deletion).
% 1.65/1.89     dependent: set(factor).
% 1.65/1.89  
% 1.65/1.89  ------------> process usable:
% 1.65/1.89  ** KEPT (pick-wt=9): 1 [] -subset(A,B)| -member(C,A)|member(C,B).
% 1.65/1.89  ** KEPT (pick-wt=8): 2 [] subset(A,B)| -member($f1(A,B),B).
% 1.65/1.89  ** KEPT (pick-wt=8): 3 [] -intersect(A,B)|member($f2(A,B),A).
% 1.65/1.89  ** KEPT (pick-wt=8): 4 [] -intersect(A,B)|member($f2(A,B),B).
% 1.65/1.89  ** KEPT (pick-wt=9): 5 [] intersect(A,B)| -member(C,A)| -member(C,B).
% 1.65/1.89  ** KEPT (pick-wt=3): 6 [] -member(A,empty_set).
% 1.65/1.89  ** KEPT (pick-wt=6): 7 [] -disjoint(A,B)| -intersect(A,B).
% 1.65/1.89  ** KEPT (pick-wt=6): 8 [] A!=B|subset(A,B).
% 1.65/1.89  ** KEPT (pick-wt=6): 9 [] A!=B|subset(B,A).
% 1.65/1.89  ** KEPT (pick-wt=9): 10 [] A=B| -subset(A,B)| -subset(B,A).
% 1.65/1.89  ** KEPT (pick-wt=6): 11 [] -intersect(A,B)|intersect(B,A).
% 1.65/1.89  ** KEPT (pick-wt=5): 12 [] -empty(A)| -member(B,A).
% 1.65/1.89  ** KEPT (pick-wt=3): 14 [copy,13,flip.1] empty_set!=$c3.
% 1.65/1.89  
% 1.65/1.89  ------------> process sos:
% 1.65/1.89  ** KEPT (pick-wt=3): 17 [] A=A.
% 1.65/1.89  ** KEPT (pick-wt=8): 18 [] subset(A,B)|member($f1(A,B),A).
% 1.65/1.89  ** KEPT (pick-wt=6): 19 [] disjoint(A,B)|intersect(A,B).
% 1.65/1.89  ** KEPT (pick-wt=3): 20 [] subset(A,A).
% 1.65/1.89  ** KEPT (pick-wt=6): 21 [] empty(A)|member($f3(A),A).
% 1.65/1.89  ** KEPT (pick-wt=3): 22 [] subset($c3,$c2).
% 1.65/1.89  ** KEPT (pick-wt=3): 23 [] subset($c3,$c1).
% 1.65/1.89  ** KEPT (pick-wt=3): 24 [] disjoint($c2,$c1).
% 1.65/1.89    Following clause subsumed by 17 during input processing: 0 [copy,17,flip.1] A=A.
% 1.65/1.89  17 back subsumes 16.
% 1.65/1.89  
% 1.65/1.89  ======= end of input processing =======
% 1.65/1.89  
% 1.65/1.89  =========== start of search ===========
% 1.65/1.89  
% 1.65/1.89  -------- PROOF -------- 
% 1.65/1.89  
% 1.65/1.89  -----> EMPTY CLAUSE at   0.06 sec ----> 698 [hyper,636,7,242] $F.
% 1.65/1.89  
% 1.65/1.89  Length of proof is 14.  Level of proof is 6.
% 1.65/1.89  
% 1.65/1.89  ---------------- PROOF ----------------
% 1.65/1.89  % SZS status Theorem
% 1.65/1.89  % SZS output start Refutation
% See solution above
% 1.65/1.89  ------------ end of proof -------------
% 1.65/1.89  
% 1.65/1.89  
% 1.65/1.89  Search stopped by max_proofs option.
% 1.65/1.89  
% 1.65/1.89  
% 1.65/1.89  Search stopped by max_proofs option.
% 1.65/1.89  
% 1.65/1.89  ============ end of search ============
% 1.65/1.89  
% 1.65/1.89  -------------- statistics -------------
% 1.65/1.89  clauses given                 68
% 1.65/1.89  clauses generated           2076
% 1.65/1.89  clauses kept                 696
% 1.65/1.89  clauses forward subsumed    1381
% 1.65/1.89  clauses back subsumed        189
% 1.65/1.89  Kbytes malloced             1953
% 1.65/1.89  
% 1.65/1.89  ----------- times (seconds) -----------
% 1.65/1.89  user CPU time          0.06          (0 hr, 0 min, 0 sec)
% 1.65/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.65/1.89  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.65/1.89  
% 1.65/1.89  That finishes the proof of the theorem.
% 1.65/1.89  
% 1.65/1.89  Process 22857 finished Wed Jul 27 10:42:07 2022
% 1.65/1.89  Otter interrupted
% 1.65/1.89  PROOF FOUND
%------------------------------------------------------------------------------