TSTP Solution File: SET627+3 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET627+3 : TPTP v8.1.0. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:13:54 EDT 2022

% Result   : Theorem 1.70s 1.90s
% Output   : Refutation 1.70s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    4
% Syntax   : Number of clauses     :    7 (   4 unt;   2 nHn;   4 RR)
%            Number of literals    :   10 (   0 equ;   3 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   2 con; 0-2 aty)
%            Number of variables   :    8 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ member(A,empty_set),
    file('SET627+3.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ intersect(A,B)
    | member(dollar_f1(A,B),B) ),
    file('SET627+3.p',unknown),
    [] ).

cnf(8,axiom,
    ~ disjoint(dollar_c1,empty_set),
    file('SET627+3.p',unknown),
    [] ).

cnf(10,axiom,
    ( disjoint(A,B)
    | intersect(A,B) ),
    file('SET627+3.p',unknown),
    [] ).

cnf(13,plain,
    ( disjoint(A,B)
    | member(dollar_f1(A,B),B) ),
    inference(hyper,[status(thm)],[10,3]),
    [iquote('hyper,10,3')] ).

cnf(19,plain,
    disjoint(A,empty_set),
    inference(hyper,[status(thm)],[13,1]),
    [iquote('hyper,13,1')] ).

cnf(20,plain,
    $false,
    inference(binary,[status(thm)],[19,8]),
    [iquote('binary,19.1,8.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13  % Problem  : SET627+3 : TPTP v8.1.0. Released v2.2.0.
% 0.04/0.13  % Command  : otter-tptp-script %s
% 0.13/0.35  % Computer : n022.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 300
% 0.13/0.35  % DateTime : Wed Jul 27 10:43:05 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 1.70/1.90  ----- Otter 3.3f, August 2004 -----
% 1.70/1.90  The process was started by sandbox on n022.cluster.edu,
% 1.70/1.90  Wed Jul 27 10:43:05 2022
% 1.70/1.90  The command was "./otter".  The process ID is 29788.
% 1.70/1.90  
% 1.70/1.90  set(prolog_style_variables).
% 1.70/1.90  set(auto).
% 1.70/1.90     dependent: set(auto1).
% 1.70/1.90     dependent: set(process_input).
% 1.70/1.90     dependent: clear(print_kept).
% 1.70/1.90     dependent: clear(print_new_demod).
% 1.70/1.90     dependent: clear(print_back_demod).
% 1.70/1.90     dependent: clear(print_back_sub).
% 1.70/1.90     dependent: set(control_memory).
% 1.70/1.90     dependent: assign(max_mem, 12000).
% 1.70/1.90     dependent: assign(pick_given_ratio, 4).
% 1.70/1.90     dependent: assign(stats_level, 1).
% 1.70/1.90     dependent: assign(max_seconds, 10800).
% 1.70/1.90  clear(print_given).
% 1.70/1.90  
% 1.70/1.90  formula_list(usable).
% 1.70/1.90  all B (-member(B,empty_set)).
% 1.70/1.90  all B C (intersect(B,C)<-> (exists D (member(D,B)&member(D,C)))).
% 1.70/1.90  all B C (disjoint(B,C)<-> -intersect(B,C)).
% 1.70/1.90  all B C (intersect(B,C)->intersect(C,B)).
% 1.70/1.90  all B (empty(B)<-> (all C (-member(C,B)))).
% 1.70/1.90  -(all B disjoint(B,empty_set)).
% 1.70/1.90  end_of_list.
% 1.70/1.90  
% 1.70/1.90  -------> usable clausifies to:
% 1.70/1.90  
% 1.70/1.90  list(usable).
% 1.70/1.90  0 [] -member(B,empty_set).
% 1.70/1.90  0 [] -intersect(B,C)|member($f1(B,C),B).
% 1.70/1.90  0 [] -intersect(B,C)|member($f1(B,C),C).
% 1.70/1.90  0 [] intersect(B,C)| -member(D,B)| -member(D,C).
% 1.70/1.90  0 [] -disjoint(B,C)| -intersect(B,C).
% 1.70/1.90  0 [] disjoint(B,C)|intersect(B,C).
% 1.70/1.90  0 [] -intersect(B,C)|intersect(C,B).
% 1.70/1.90  0 [] -empty(B)| -member(C,B).
% 1.70/1.90  0 [] empty(B)|member($f2(B),B).
% 1.70/1.90  0 [] -disjoint($c1,empty_set).
% 1.70/1.90  end_of_list.
% 1.70/1.90  
% 1.70/1.90  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 1.70/1.90  
% 1.70/1.90  This is a non-Horn set without equality.  The strategy will
% 1.70/1.90  be ordered hyper_res, unit deletion, and factoring, with
% 1.70/1.90  satellites in sos and with nuclei in usable.
% 1.70/1.90  
% 1.70/1.90     dependent: set(hyper_res).
% 1.70/1.90     dependent: set(factor).
% 1.70/1.90     dependent: set(unit_deletion).
% 1.70/1.90  
% 1.70/1.90  ------------> process usable:
% 1.70/1.90  ** KEPT (pick-wt=3): 1 [] -member(A,empty_set).
% 1.70/1.90  ** KEPT (pick-wt=8): 2 [] -intersect(A,B)|member($f1(A,B),A).
% 1.70/1.90  ** KEPT (pick-wt=8): 3 [] -intersect(A,B)|member($f1(A,B),B).
% 1.70/1.90  ** KEPT (pick-wt=9): 4 [] intersect(A,B)| -member(C,A)| -member(C,B).
% 1.70/1.90  ** KEPT (pick-wt=6): 5 [] -disjoint(A,B)| -intersect(A,B).
% 1.70/1.90  ** KEPT (pick-wt=6): 6 [] -intersect(A,B)|intersect(B,A).
% 1.70/1.90  ** KEPT (pick-wt=5): 7 [] -empty(A)| -member(B,A).
% 1.70/1.90  ** KEPT (pick-wt=3): 8 [] -disjoint($c1,empty_set).
% 1.70/1.90  
% 1.70/1.90  ------------> process sos:
% 1.70/1.90  ** KEPT (pick-wt=6): 10 [] disjoint(A,B)|intersect(A,B).
% 1.70/1.90  ** KEPT (pick-wt=6): 11 [] empty(A)|member($f2(A),A).
% 1.70/1.90  
% 1.70/1.90  ======= end of input processing =======
% 1.70/1.90  
% 1.70/1.90  =========== start of search ===========
% 1.70/1.90  
% 1.70/1.90  -------- PROOF -------- 
% 1.70/1.90  
% 1.70/1.90  ----> UNIT CONFLICT at   0.00 sec ----> 20 [binary,19.1,8.1] $F.
% 1.70/1.90  
% 1.70/1.90  Length of proof is 2.  Level of proof is 2.
% 1.70/1.90  
% 1.70/1.90  ---------------- PROOF ----------------
% 1.70/1.90  % SZS status Theorem
% 1.70/1.90  % SZS output start Refutation
% See solution above
% 1.70/1.90  ------------ end of proof -------------
% 1.70/1.90  
% 1.70/1.90  
% 1.70/1.90  Search stopped by max_proofs option.
% 1.70/1.90  
% 1.70/1.90  
% 1.70/1.90  Search stopped by max_proofs option.
% 1.70/1.90  
% 1.70/1.90  ============ end of search ============
% 1.70/1.90  
% 1.70/1.90  -------------- statistics -------------
% 1.70/1.90  clauses given                  4
% 1.70/1.90  clauses generated             12
% 1.70/1.90  clauses kept                  19
% 1.70/1.90  clauses forward subsumed       3
% 1.70/1.90  clauses back subsumed          0
% 1.70/1.90  Kbytes malloced              976
% 1.70/1.90  
% 1.70/1.90  ----------- times (seconds) -----------
% 1.70/1.90  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.70/1.90  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.70/1.90  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.70/1.90  
% 1.70/1.90  That finishes the proof of the theorem.
% 1.70/1.90  
% 1.70/1.90  Process 29788 finished Wed Jul 27 10:43:07 2022
% 1.70/1.90  Otter interrupted
% 1.70/1.90  PROOF FOUND
%------------------------------------------------------------------------------