%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SET599+3 : TPTP v8.1.2. Released v2.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n002.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 14:46:59 EDT 2023

% Result   : Theorem 3.58s 3.78s
% Output   : Proof 3.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SET599+3 : TPTP v8.1.2. Released v2.2.0.
% 0.07/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n002.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sat Aug 26 14:16:33 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.58/3.78  SZS status Theorem for theBenchmark.p
% 3.58/3.78  SZS output start Proof for theBenchmark.p
% 3.58/3.78  Clause #0 (by assumption #[]): Eq (∀ (B C : Iota), Eq (symmetric_difference B C) (union (difference B C) (difference C B))) True
% 3.58/3.78  Clause #1 (by assumption #[]): Eq (∀ (B C : Iota), subset B (union B C)) True
% 3.58/3.78  Clause #8 (by assumption #[]): Eq (Not (∀ (B C : Iota), subset (difference B C) (symmetric_difference B C))) True
% 3.58/3.78  Clause #10 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (C : Iota), subset a (union a C)) True
% 3.58/3.78  Clause #11 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (subset a (union a a_1)) True
% 3.58/3.78  Clause #19 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (C : Iota), Eq (symmetric_difference a C) (union (difference a C) (difference C a))) True
% 3.58/3.78  Clause #20 (by clausification #[19]): ∀ (a a_1 : Iota), Eq (Eq (symmetric_difference a a_1) (union (difference a a_1) (difference a_1 a))) True
% 3.58/3.78  Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota), Eq (symmetric_difference a a_1) (union (difference a a_1) (difference a_1 a))
% 3.58/3.78  Clause #22 (by superposition #[21, 11]): ∀ (a a_1 : Iota), Eq (subset (difference a a_1) (symmetric_difference a a_1)) True
% 3.58/3.78  Clause #34 (by clausification #[8]): Eq (∀ (B C : Iota), subset (difference B C) (symmetric_difference B C)) False
% 3.58/3.78  Clause #35 (by clausification #[34]): ∀ (a : Iota), Eq (Not (∀ (C : Iota), subset (difference (skS.0 0 a) C) (symmetric_difference (skS.0 0 a) C))) True
% 3.58/3.78  Clause #36 (by clausification #[35]): ∀ (a : Iota), Eq (∀ (C : Iota), subset (difference (skS.0 0 a) C) (symmetric_difference (skS.0 0 a) C)) False
% 3.58/3.78  Clause #37 (by clausification #[36]): ∀ (a a_1 : Iota),
% 3.58/3.78    Eq (Not (subset (difference (skS.0 0 a) (skS.0 1 a a_1)) (symmetric_difference (skS.0 0 a) (skS.0 1 a a_1)))) True
% 3.58/3.78  Clause #38 (by clausification #[37]): ∀ (a a_1 : Iota),
% 3.58/3.78    Eq (subset (difference (skS.0 0 a) (skS.0 1 a a_1)) (symmetric_difference (skS.0 0 a) (skS.0 1 a a_1))) False
% 3.58/3.78  Clause #39 (by superposition #[38, 22]): Eq False True
% 3.58/3.78  Clause #40 (by clausification #[39]): False
% 3.58/3.78  SZS output end Proof for theBenchmark.p
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