TSTP Solution File: SET006-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SET006-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:12:45 EDT 2022

% Result   : Unsatisfiable 1.99s 2.12s
% Output   : Refutation 1.99s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    9 (   6 unt;   1 nHn;   8 RR)
%            Number of literals    :   13 (   0 equ;   4 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    3 (   3 usr;   2 con; 0-2 aty)
%            Number of variables   :    8 (   1 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    ( ~ member(member_of_1_not_of_2(A,B),B)
    | subset(A,B) ),
    file('SET006-1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ intersection(A,B,C)
    | ~ member(D,C)
    | member(D,B) ),
    file('SET006-1.p',unknown),
    [] ).

cnf(10,axiom,
    ~ subset(d,a),
    file('SET006-1.p',unknown),
    [] ).

cnf(17,axiom,
    ( subset(A,B)
    | member(member_of_1_not_of_2(A,B),A) ),
    file('SET006-1.p',unknown),
    [] ).

cnf(20,axiom,
    intersection(d,a,d),
    file('SET006-1.p',unknown),
    [] ).

cnf(24,plain,
    member(member_of_1_not_of_2(d,a),d),
    inference(hyper,[status(thm)],[17,10]),
    [iquote('hyper,17,10')] ).

cnf(26,plain,
    member(member_of_1_not_of_2(d,a),a),
    inference(hyper,[status(thm)],[24,7,20]),
    [iquote('hyper,24,7,20')] ).

cnf(28,plain,
    subset(d,a),
    inference(hyper,[status(thm)],[26,2]),
    [iquote('hyper,26,2')] ).

cnf(29,plain,
    $false,
    inference(binary,[status(thm)],[28,10]),
    [iquote('binary,28.1,10.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SET006-1 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n015.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 10:44:27 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.99/2.12  ----- Otter 3.3f, August 2004 -----
% 1.99/2.12  The process was started by sandbox2 on n015.cluster.edu,
% 1.99/2.12  Wed Jul 27 10:44:27 2022
% 1.99/2.12  The command was "./otter".  The process ID is 9223.
% 1.99/2.12  
% 1.99/2.12  set(prolog_style_variables).
% 1.99/2.12  set(auto).
% 1.99/2.12     dependent: set(auto1).
% 1.99/2.12     dependent: set(process_input).
% 1.99/2.12     dependent: clear(print_kept).
% 1.99/2.12     dependent: clear(print_new_demod).
% 1.99/2.12     dependent: clear(print_back_demod).
% 1.99/2.12     dependent: clear(print_back_sub).
% 1.99/2.12     dependent: set(control_memory).
% 1.99/2.12     dependent: assign(max_mem, 12000).
% 1.99/2.12     dependent: assign(pick_given_ratio, 4).
% 1.99/2.12     dependent: assign(stats_level, 1).
% 1.99/2.12     dependent: assign(max_seconds, 10800).
% 1.99/2.12  clear(print_given).
% 1.99/2.12  
% 1.99/2.12  list(usable).
% 1.99/2.12  0 [] -member(Element,Subset)| -subset(Subset,Superset)|member(Element,Superset).
% 1.99/2.12  0 [] subset(Subset,Superset)|member(member_of_1_not_of_2(Subset,Superset),Subset).
% 1.99/2.12  0 [] -member(member_of_1_not_of_2(Subset,Superset),Superset)|subset(Subset,Superset).
% 1.99/2.12  0 [] -e_qual_sets(Subset,Superset)|subset(Subset,Superset).
% 1.99/2.12  0 [] -e_qual_sets(Superset,Subset)|subset(Subset,Superset).
% 1.99/2.12  0 [] -subset(Set1,Set2)| -subset(Set2,Set1)|e_qual_sets(Set2,Set1).
% 1.99/2.12  0 [] -intersection(Set1,Set2,Intersection)| -member(Element,Intersection)|member(Element,Set1).
% 1.99/2.12  0 [] -intersection(Set1,Set2,Intersection)| -member(Element,Intersection)|member(Element,Set2).
% 1.99/2.12  0 [] -intersection(Set1,Set2,Intersection)| -member(Element,Set2)| -member(Element,Set1)|member(Element,Intersection).
% 1.99/2.12  0 [] member(h(Set1,Set2,Intersection),Intersection)|intersection(Set1,Set2,Intersection)|member(h(Set1,Set2,Intersection),Set1).
% 1.99/2.12  0 [] member(h(Set1,Set2,Intersection),Intersection)|intersection(Set1,Set2,Intersection)|member(h(Set1,Set2,Intersection),Set2).
% 1.99/2.12  0 [] -member(h(Set1,Set2,Intersection),Intersection)| -member(h(Set1,Set2,Intersection),Set2)| -member(h(Set1,Set2,Intersection),Set1)|intersection(Set1,Set2,Intersection).
% 1.99/2.12  0 [] intersection(d,a,d).
% 1.99/2.12  0 [] -subset(d,a).
% 1.99/2.12  end_of_list.
% 1.99/2.12  
% 1.99/2.12  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=4.
% 1.99/2.12  
% 1.99/2.12  This is a non-Horn set without equality.  The strategy will
% 1.99/2.12  be ordered hyper_res, unit deletion, and factoring, with
% 1.99/2.12  satellites in sos and with nuclei in usable.
% 1.99/2.12  
% 1.99/2.12     dependent: set(hyper_res).
% 1.99/2.12     dependent: set(factor).
% 1.99/2.12     dependent: set(unit_deletion).
% 1.99/2.12  
% 1.99/2.12  ------------> process usable:
% 1.99/2.12  ** KEPT (pick-wt=9): 1 [] -member(A,B)| -subset(B,C)|member(A,C).
% 1.99/2.12  ** KEPT (pick-wt=8): 2 [] -member(member_of_1_not_of_2(A,B),B)|subset(A,B).
% 1.99/2.12  ** KEPT (pick-wt=6): 3 [] -e_qual_sets(A,B)|subset(A,B).
% 1.99/2.12  ** KEPT (pick-wt=6): 4 [] -e_qual_sets(A,B)|subset(B,A).
% 1.99/2.12  ** KEPT (pick-wt=9): 5 [] -subset(A,B)| -subset(B,A)|e_qual_sets(B,A).
% 1.99/2.12  ** KEPT (pick-wt=10): 6 [] -intersection(A,B,C)| -member(D,C)|member(D,A).
% 1.99/2.12  ** KEPT (pick-wt=10): 7 [] -intersection(A,B,C)| -member(D,C)|member(D,B).
% 1.99/2.12  ** KEPT (pick-wt=13): 8 [] -intersection(A,B,C)| -member(D,B)| -member(D,A)|member(D,C).
% 1.99/2.12  ** KEPT (pick-wt=22): 9 [] -member(h(A,B,C),C)| -member(h(A,B,C),B)| -member(h(A,B,C),A)|intersection(A,B,C).
% 1.99/2.12  ** KEPT (pick-wt=3): 10 [] -subset(d,a).
% 1.99/2.12  
% 1.99/2.12  ------------> process sos:
% 1.99/2.12  ** KEPT (pick-wt=8): 17 [] subset(A,B)|member(member_of_1_not_of_2(A,B),A).
% 1.99/2.12  ** KEPT (pick-wt=16): 18 [] member(h(A,B,C),C)|intersection(A,B,C)|member(h(A,B,C),A).
% 1.99/2.12  ** KEPT (pick-wt=16): 19 [] member(h(A,B,C),C)|intersection(A,B,C)|member(h(A,B,C),B).
% 1.99/2.12  ** KEPT (pick-wt=4): 20 [] intersection(d,a,d).
% 1.99/2.12  
% 1.99/2.12  ======= end of input processing =======
% 1.99/2.12  
% 1.99/2.12  =========== start of search ===========
% 1.99/2.12  
% 1.99/2.12  -------- PROOF -------- 
% 1.99/2.12  
% 1.99/2.12  ----> UNIT CONFLICT at   0.00 sec ----> 29 [binary,28.1,10.1] $F.
% 1.99/2.12  
% 1.99/2.12  Length of proof is 3.  Level of proof is 3.
% 1.99/2.12  
% 1.99/2.12  ---------------- PROOF ----------------
% 1.99/2.12  % SZS status Unsatisfiable
% 1.99/2.12  % SZS output start Refutation
% See solution above
% 1.99/2.12  ------------ end of proof -------------
% 1.99/2.12  
% 1.99/2.12  
% 1.99/2.12  Search stopped by max_proofs option.
% 1.99/2.12  
% 1.99/2.12  
% 1.99/2.12  Search stopped by max_proofs option.
% 1.99/2.12  
% 1.99/2.12  ============ end of search ============
% 1.99/2.12  
% 1.99/2.12  -------------- statistics -------------
% 1.99/2.12  clauses given                  4
% 1.99/2.12  clauses generated             20
% 1.99/2.12  clauses kept                  28
% 1.99/2.12  clauses forward subsumed       6
% 1.99/2.12  clauses back subsumed          0
% 1.99/2.12  Kbytes malloced              976
% 1.99/2.12  
% 1.99/2.12  ----------- times (seconds) -----------
% 1.99/2.12  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.99/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.99/2.12  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.99/2.12  
% 1.99/2.12  That finishes the proof of the theorem.
% 1.99/2.12  
% 1.99/2.12  Process 9223 finished Wed Jul 27 10:44:28 2022
% 1.99/2.12  Otter interrupted
% 1.99/2.12  PROOF FOUND
%------------------------------------------------------------------------------