TSTP Solution File: ROB010-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : ROB010-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:12:22 EDT 2022

% Result   : Unsatisfiable 1.94s 2.12s
% Output   : Refutation 1.94s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    4
% Syntax   : Number of clauses     :    8 (   8 unt;   0 nHn;   6 RR)
%            Number of literals    :    8 (   7 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    6 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-2 aty)
%            Number of variables   :    4 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    negate(add(c,negate(add(b,a)))) != a,
    file('ROB010-1.p',unknown),
    [] ).

cnf(3,axiom,
    add(A,B) = add(B,A),
    file('ROB010-1.p',unknown),
    [] ).

cnf(6,axiom,
    negate(add(negate(add(A,B)),negate(add(A,negate(B))))) = A,
    file('ROB010-1.p',unknown),
    [] ).

cnf(8,axiom,
    negate(add(a,negate(b))) = c,
    file('ROB010-1.p',unknown),
    [] ).

cnf(10,plain,
    negate(add(negate(add(b,a)),c)) != a,
    inference(para_from,[status(thm),theory(equality)],[3,1]),
    [iquote('para_from,3.1.1,1.1.1.1')] ).

cnf(14,plain,
    negate(add(negate(add(a,b)),c)) != a,
    inference(para_into,[status(thm),theory(equality)],[10,3]),
    [iquote('para_into,10.1.1.1.1.1,3.1.1')] ).

cnf(50,plain,
    negate(add(negate(add(a,b)),c)) = a,
    inference(para_into,[status(thm),theory(equality)],[6,8]),
    [iquote('para_into,6.1.1.1.2,8.1.1')] ).

cnf(52,plain,
    $false,
    inference(binary,[status(thm)],[50,14]),
    [iquote('binary,50.1,14.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : ROB010-1 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.32  % Computer : n006.cluster.edu
% 0.12/0.32  % Model    : x86_64 x86_64
% 0.12/0.32  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % Memory   : 8042.1875MB
% 0.12/0.32  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit : 300
% 0.12/0.32  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 04:03:16 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.94/2.12  ----- Otter 3.3f, August 2004 -----
% 1.94/2.12  The process was started by sandbox on n006.cluster.edu,
% 1.94/2.12  Wed Jul 27 04:03:17 2022
% 1.94/2.12  The command was "./otter".  The process ID is 30814.
% 1.94/2.12  
% 1.94/2.12  set(prolog_style_variables).
% 1.94/2.12  set(auto).
% 1.94/2.12     dependent: set(auto1).
% 1.94/2.12     dependent: set(process_input).
% 1.94/2.12     dependent: clear(print_kept).
% 1.94/2.12     dependent: clear(print_new_demod).
% 1.94/2.12     dependent: clear(print_back_demod).
% 1.94/2.12     dependent: clear(print_back_sub).
% 1.94/2.12     dependent: set(control_memory).
% 1.94/2.12     dependent: assign(max_mem, 12000).
% 1.94/2.12     dependent: assign(pick_given_ratio, 4).
% 1.94/2.12     dependent: assign(stats_level, 1).
% 1.94/2.12     dependent: assign(max_seconds, 10800).
% 1.94/2.12  clear(print_given).
% 1.94/2.12  
% 1.94/2.12  list(usable).
% 1.94/2.12  0 [] A=A.
% 1.94/2.12  0 [] add(X,Y)=add(Y,X).
% 1.94/2.12  0 [] add(add(X,Y),Z)=add(X,add(Y,Z)).
% 1.94/2.12  0 [] negate(add(negate(add(X,Y)),negate(add(X,negate(Y)))))=X.
% 1.94/2.12  0 [] negate(add(a,negate(b)))=c.
% 1.94/2.12  0 [] negate(add(c,negate(add(b,a))))!=a.
% 1.94/2.12  end_of_list.
% 1.94/2.12  
% 1.94/2.12  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.94/2.12  
% 1.94/2.12  All clauses are units, and equality is present; the
% 1.94/2.12  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.94/2.12  
% 1.94/2.12     dependent: set(knuth_bendix).
% 1.94/2.12     dependent: set(anl_eq).
% 1.94/2.12     dependent: set(para_from).
% 1.94/2.12     dependent: set(para_into).
% 1.94/2.12     dependent: clear(para_from_right).
% 1.94/2.12     dependent: clear(para_into_right).
% 1.94/2.12     dependent: set(para_from_vars).
% 1.94/2.12     dependent: set(eq_units_both_ways).
% 1.94/2.12     dependent: set(dynamic_demod_all).
% 1.94/2.12     dependent: set(dynamic_demod).
% 1.94/2.12     dependent: set(order_eq).
% 1.94/2.12     dependent: set(back_demod).
% 1.94/2.12     dependent: set(lrpo).
% 1.94/2.12  
% 1.94/2.12  ------------> process usable:
% 1.94/2.12  ** KEPT (pick-wt=9): 1 [] negate(add(c,negate(add(b,a))))!=a.
% 1.94/2.12  
% 1.94/2.12  ------------> process sos:
% 1.94/2.12  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.94/2.12  ** KEPT (pick-wt=7): 3 [] add(A,B)=add(B,A).
% 1.94/2.12  ** KEPT (pick-wt=11): 4 [] add(add(A,B),C)=add(A,add(B,C)).
% 1.94/2.12  ---> New Demodulator: 5 [new_demod,4] add(add(A,B),C)=add(A,add(B,C)).
% 1.94/2.12  ** KEPT (pick-wt=13): 6 [] negate(add(negate(add(A,B)),negate(add(A,negate(B)))))=A.
% 1.94/2.12  ---> New Demodulator: 7 [new_demod,6] negate(add(negate(add(A,B)),negate(add(A,negate(B)))))=A.
% 1.94/2.12  ** KEPT (pick-wt=7): 8 [] negate(add(a,negate(b)))=c.
% 1.94/2.12  ---> New Demodulator: 9 [new_demod,8] negate(add(a,negate(b)))=c.
% 1.94/2.12    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.94/2.12    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] add(A,B)=add(B,A).
% 1.94/2.12  >>>> Starting back demodulation with 5.
% 1.94/2.12  >>>> Starting back demodulation with 7.
% 1.94/2.12  >>>> Starting back demodulation with 9.
% 1.94/2.12  
% 1.94/2.12  ======= end of input processing =======
% 1.94/2.12  
% 1.94/2.12  =========== start of search ===========
% 1.94/2.12  
% 1.94/2.12  -------- PROOF -------- 
% 1.94/2.12  
% 1.94/2.12  ----> UNIT CONFLICT at   0.00 sec ----> 52 [binary,50.1,14.1] $F.
% 1.94/2.12  
% 1.94/2.12  Length of proof is 3.  Level of proof is 2.
% 1.94/2.12  
% 1.94/2.12  ---------------- PROOF ----------------
% 1.94/2.12  % SZS status Unsatisfiable
% 1.94/2.12  % SZS output start Refutation
% See solution above
% 1.94/2.12  ------------ end of proof -------------
% 1.94/2.12  
% 1.94/2.12  
% 1.94/2.12  Search stopped by max_proofs option.
% 1.94/2.12  
% 1.94/2.12  
% 1.94/2.12  Search stopped by max_proofs option.
% 1.94/2.12  
% 1.94/2.12  ============ end of search ============
% 1.94/2.12  
% 1.94/2.12  -------------- statistics -------------
% 1.94/2.12  clauses given                 11
% 1.94/2.12  clauses generated             62
% 1.94/2.12  clauses kept                  35
% 1.94/2.12  clauses forward subsumed      48
% 1.94/2.12  clauses back subsumed          0
% 1.94/2.12  Kbytes malloced              976
% 1.94/2.12  
% 1.94/2.12  ----------- times (seconds) -----------
% 1.94/2.12  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.94/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.94/2.12  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.94/2.12  
% 1.94/2.12  That finishes the proof of the theorem.
% 1.94/2.12  
% 1.94/2.12  Process 30814 finished Wed Jul 27 04:03:18 2022
% 1.94/2.12  Otter interrupted
% 1.94/2.12  PROOF FOUND
%------------------------------------------------------------------------------