TSTP Solution File: RNG103+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG103+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:29 EDT 2022

% Result   : Theorem 0.71s 0.89s
% Output   : Refutation 0.71s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   7 unt;   0 nHn;  11 RR)
%            Number of literals    :   22 (   0 equ;  15 neg)
%            Maximal clause size   :    4 (   2 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   10 (  10 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aElement0(xc),
    file('RNG103+1.p',unknown),
    [] ).

cnf(5,axiom,
    aElement0(xu),
    file('RNG103+1.p',unknown),
    [] ).

cnf(6,axiom,
    aElement0(xv),
    file('RNG103+1.p',unknown),
    [] ).

cnf(17,axiom,
    equal(sdtasdt0(xc,xu),xx),
    file('RNG103+1.p',unknown),
    [] ).

cnf(18,axiom,
    equal(sdtasdt0(xc,xv),xy),
    file('RNG103+1.p',unknown),
    [] ).

cnf(35,axiom,
    ~ equal(sdtasdt0(xc,sdtpldt0(xu,xv)),sdtpldt0(xx,xy)),
    file('RNG103+1.p',unknown),
    [] ).

cnf(81,axiom,
    ( ~ aElement0(u)
    | ~ aElement0(v)
    | ~ aElement0(w)
    | equal(sdtasdt0(w,sdtpldt0(v,u)),sdtpldt0(sdtasdt0(w,v),sdtasdt0(w,u))) ),
    file('RNG103+1.p',unknown),
    [] ).

cnf(2226,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc)
    | ~ equal(sdtpldt0(sdtasdt0(xc,xu),sdtasdt0(xc,xv)),sdtpldt0(xx,xy)) ),
    inference(spl,[status(thm),theory(equality)],[81,35]),
    [iquote('0:SpL:81.3,35.0')] ).

cnf(2230,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc)
    | ~ equal(sdtpldt0(xx,xy),sdtpldt0(xx,xy)) ),
    inference(rew,[status(thm),theory(equality)],[17,2226,18]),
    [iquote('0:Rew:17.0,2226.3,18.0,2226.3')] ).

cnf(2231,plain,
    ( ~ aElement0(xv)
    | ~ aElement0(xu)
    | ~ aElement0(xc) ),
    inference(obv,[status(thm),theory(equality)],[2230]),
    [iquote('0:Obv:2230.3')] ).

cnf(2232,plain,
    $false,
    inference(ssi,[status(thm)],[2231,3,5,6]),
    [iquote('0:SSi:2231.2,2231.1,2231.0,3.0,5.0,6.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : RNG103+1 : TPTP v8.1.0. Released v4.0.0.
% 0.12/0.13  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n024.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon May 30 18:40:06 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.71/0.89  
% 0.71/0.89  SPASS V 3.9 
% 0.71/0.89  SPASS beiseite: Proof found.
% 0.71/0.89  % SZS status Theorem
% 0.71/0.89  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.71/0.89  SPASS derived 1472 clauses, backtracked 65 clauses, performed 3 splits and kept 710 clauses.
% 0.71/0.89  SPASS allocated 99966 KBytes.
% 0.71/0.89  SPASS spent	0:00:00.52 on the problem.
% 0.71/0.89  		0:00:00.04 for the input.
% 0.71/0.89  		0:00:00.12 for the FLOTTER CNF translation.
% 0.71/0.89  		0:00:00.02 for inferences.
% 0.71/0.89  		0:00:00.00 for the backtracking.
% 0.71/0.89  		0:00:00.31 for the reduction.
% 0.71/0.89  
% 0.71/0.89  
% 0.71/0.89  Here is a proof with depth 1, length 11 :
% 0.71/0.89  % SZS output start Refutation
% See solution above
% 0.71/0.89  Formulae used in the proof : m__1905 m__1956 m__1979 m__ mAMDistr
% 0.71/0.89  
%------------------------------------------------------------------------------