TSTP Solution File: RNG098+2 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG098+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:28 EDT 2022

% Result   : Theorem 0.10s 0.57s
% Output   : Refutation 0.10s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :   16
% Syntax   : Number of clauses     :   27 (  15 unt;   0 nHn;  27 RR)
%            Number of literals    :   49 (   0 equ;  27 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    4 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   1 prp; 0-2 aty)
%            Number of functors    :   14 (  14 usr;  11 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    aElement0(sz10),
    file('RNG098+2.p',unknown),
    [] ).

cnf(5,axiom,
    aSet0(xJ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(6,axiom,
    aIdeal0(xJ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(7,axiom,
    aElement0(xx),
    file('RNG098+2.p',unknown),
    [] ).

cnf(8,axiom,
    aElement0(xy),
    file('RNG098+2.p',unknown),
    [] ).

cnf(10,axiom,
    aElementOf0(xa,xI),
    file('RNG098+2.p',unknown),
    [] ).

cnf(11,axiom,
    aElementOf0(xb,xJ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(17,axiom,
    ( ~ aElement0(u)
    | aElement0(smndt0(u)) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(18,axiom,
    ~ aElementOf0(sdtpldt0(xw,smndt0(xx)),xI),
    file('RNG098+2.p',unknown),
    [] ).

cnf(27,axiom,
    aElementOf0(sdtasdt0(xx,sdtpldt0(xb,smndt0(sz10))),xI),
    file('RNG098+2.p',unknown),
    [] ).

cnf(30,axiom,
    ( ~ aSet0(u)
    | ~ aElementOf0(v,u)
    | aElement0(v) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(37,axiom,
    ( ~ aElement0(u)
    | equal(sdtasdt0(u,smndt0(sz10)),smndt0(u)) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(43,axiom,
    ( ~ aElement0(u)
    | ~ aElementOf0(v,xI)
    | aElementOf0(sdtasdt0(u,v),xI) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(47,axiom,
    ( ~ aElementOf0(u,xI)
    | ~ aElementOf0(v,xI)
    | aElementOf0(sdtpldt0(u,v),xI) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(52,axiom,
    equal(sdtpldt0(sdtasdt0(xy,xa),sdtpldt0(sdtasdt0(xx,xb),smndt0(xx))),sdtpldt0(xw,smndt0(xx))),
    file('RNG098+2.p',unknown),
    [] ).

cnf(69,axiom,
    ( ~ aElement0(u)
    | ~ aElement0(v)
    | ~ aElement0(w)
    | equal(sdtasdt0(w,sdtpldt0(v,u)),sdtpldt0(sdtasdt0(w,v),sdtasdt0(w,u))) ),
    file('RNG098+2.p',unknown),
    [] ).

cnf(108,plain,
    ( ~ aSet0(xJ)
    | aElement0(xb) ),
    inference(res,[status(thm),theory(equality)],[11,30]),
    [iquote('0:Res:11.0,30.1')] ).

cnf(116,plain,
    aElement0(xb),
    inference(ssi,[status(thm)],[108,6,5]),
    [iquote('0:SSi:108.0,6.0,5.0')] ).

cnf(363,plain,
    ( ~ aElementOf0(sdtasdt0(xy,xa),xI)
    | ~ aElementOf0(sdtpldt0(sdtasdt0(xx,xb),smndt0(xx)),xI)
    | aElementOf0(sdtpldt0(xw,smndt0(xx)),xI) ),
    inference(spr,[status(thm),theory(equality)],[52,47]),
    [iquote('0:SpR:52.0,47.2')] ).

cnf(371,plain,
    ( ~ aElementOf0(sdtasdt0(xy,xa),xI)
    | ~ aElementOf0(sdtpldt0(sdtasdt0(xx,xb),smndt0(xx)),xI) ),
    inference(mrr,[status(thm)],[363,18]),
    [iquote('0:MRR:363.2,18.0')] ).

cnf(1339,plain,
    ( ~ aElement0(smndt0(sz10))
    | ~ aElement0(xb)
    | ~ aElement0(xx)
    | aElementOf0(sdtpldt0(sdtasdt0(xx,xb),sdtasdt0(xx,smndt0(sz10))),xI) ),
    inference(spr,[status(thm),theory(equality)],[69,27]),
    [iquote('0:SpR:69.3,27.0')] ).

cnf(1387,plain,
    ( ~ aElement0(smndt0(sz10))
    | ~ aElement0(xb)
    | ~ aElement0(xx)
    | aElementOf0(sdtpldt0(sdtasdt0(xx,xb),smndt0(xx)),xI) ),
    inference(rew,[status(thm),theory(equality)],[37,1339]),
    [iquote('0:Rew:37.1,1339.3')] ).

cnf(1388,plain,
    aElementOf0(sdtpldt0(sdtasdt0(xx,xb),smndt0(xx)),xI),
    inference(ssi,[status(thm)],[1387,7,116,17,2]),
    [iquote('0:SSi:1387.2,1387.1,1387.0,7.0,116.1,17.0,2.0')] ).

cnf(1389,plain,
    ~ aElementOf0(sdtasdt0(xy,xa),xI),
    inference(mrr,[status(thm)],[371,1388]),
    [iquote('0:MRR:371.1,1388.0')] ).

cnf(1448,plain,
    ( ~ aElement0(xy)
    | ~ aElementOf0(xa,xI) ),
    inference(res,[status(thm),theory(equality)],[43,1389]),
    [iquote('0:Res:43.2,1389.0')] ).

cnf(1450,plain,
    ~ aElementOf0(xa,xI),
    inference(ssi,[status(thm)],[1448,8]),
    [iquote('0:SSi:1448.0,8.0')] ).

cnf(1451,plain,
    $false,
    inference(mrr,[status(thm)],[1450,10]),
    [iquote('0:MRR:1450.0,10.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.07  % Problem  : RNG098+2 : TPTP v8.1.0. Released v4.0.0.
% 0.00/0.07  % Command  : run_spass %d %s
% 0.06/0.25  % Computer : n025.cluster.edu
% 0.06/0.25  % Model    : x86_64 x86_64
% 0.06/0.25  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.06/0.25  % Memory   : 8042.1875MB
% 0.06/0.25  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.06/0.25  % CPULimit : 300
% 0.06/0.25  % WCLimit  : 600
% 0.06/0.25  % DateTime : Mon May 30 10:26:27 EDT 2022
% 0.06/0.25  % CPUTime  : 
% 0.10/0.57  
% 0.10/0.57  SPASS V 3.9 
% 0.10/0.57  SPASS beiseite: Proof found.
% 0.10/0.57  % SZS status Theorem
% 0.10/0.57  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.10/0.57  SPASS derived 919 clauses, backtracked 0 clauses, performed 0 splits and kept 402 clauses.
% 0.10/0.57  SPASS allocated 99165 KBytes.
% 0.10/0.57  SPASS spent	0:00:00.29 on the problem.
% 0.10/0.57  		0:00:00.03 for the input.
% 0.10/0.57  		0:00:00.10 for the FLOTTER CNF translation.
% 0.10/0.57  		0:00:00.01 for inferences.
% 0.10/0.57  		0:00:00.00 for the backtracking.
% 0.10/0.57  		0:00:00.13 for the reduction.
% 0.10/0.57  
% 0.10/0.57  
% 0.10/0.57  Here is a proof with depth 2, length 27 :
% 0.10/0.57  % SZS output start Refutation
% See solution above
% 0.10/0.57  Formulae used in the proof : mSortsC_01 m__1205 m__1217 m__1294 mSortsU m__ m__1393 mEOfElem mMulMnOne m__1374 mAMDistr
% 0.10/0.57  
%------------------------------------------------------------------------------