TSTP Solution File: RNG089+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : RNG089+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 20:41:26 EDT 2022

% Result   : Theorem 0.18s 0.51s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   13 (   8 unt;   0 nHn;  13 RR)
%            Number of literals    :   23 (   0 equ;  16 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    9 (   9 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aIdeal0(xI),
    file('RNG089+1.p',unknown),
    [] ).

cnf(4,axiom,
    aIdeal0(xJ),
    file('RNG089+1.p',unknown),
    [] ).

cnf(5,axiom,
    aElement0(xz),
    file('RNG089+1.p',unknown),
    [] ).

cnf(7,axiom,
    aElementOf0(xk,xI),
    file('RNG089+1.p',unknown),
    [] ).

cnf(8,axiom,
    aElementOf0(xl,xJ),
    file('RNG089+1.p',unknown),
    [] ).

cnf(38,axiom,
    ( ~ aElementOf0(sdtasdt0(xz,xl),xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    file('RNG089+1.p',unknown),
    [] ).

cnf(43,axiom,
    ( ~ aIdeal0(u)
    | ~ aElement0(v)
    | ~ aElementOf0(w,u)
    | aElementOf0(sdtasdt0(v,w),u) ),
    file('RNG089+1.p',unknown),
    [] ).

cnf(195,plain,
    ( ~ aIdeal0(xJ)
    | ~ aElement0(xz)
    | ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    inference(res,[status(thm),theory(equality)],[43,38]),
    [iquote('0:Res:43.3,38.0')] ).

cnf(199,plain,
    ( ~ aElementOf0(xl,xJ)
    | ~ aElementOf0(sdtasdt0(xz,xk),xI) ),
    inference(ssi,[status(thm)],[195,5,4]),
    [iquote('0:SSi:195.1,195.0,5.0,4.0')] ).

cnf(200,plain,
    ~ aElementOf0(sdtasdt0(xz,xk),xI),
    inference(mrr,[status(thm)],[199,8]),
    [iquote('0:MRR:199.0,8.0')] ).

cnf(206,plain,
    ( ~ aIdeal0(xI)
    | ~ aElement0(xz)
    | ~ aElementOf0(xk,xI) ),
    inference(res,[status(thm),theory(equality)],[43,200]),
    [iquote('0:Res:43.3,200.0')] ).

cnf(207,plain,
    ~ aElementOf0(xk,xI),
    inference(ssi,[status(thm)],[206,5,3]),
    [iquote('0:SSi:206.1,206.0,5.0,3.0')] ).

cnf(208,plain,
    $false,
    inference(mrr,[status(thm)],[207,7]),
    [iquote('0:MRR:207.0,7.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : RNG089+1 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n028.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon May 30 18:12:50 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.51  
% 0.18/0.51  SPASS V 3.9 
% 0.18/0.51  SPASS beiseite: Proof found.
% 0.18/0.51  % SZS status Theorem
% 0.18/0.51  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.18/0.51  SPASS derived 96 clauses, backtracked 0 clauses, performed 0 splits and kept 90 clauses.
% 0.18/0.51  SPASS allocated 98835 KBytes.
% 0.18/0.51  SPASS spent	0:00:00.16 on the problem.
% 0.18/0.51  		0:00:00.03 for the input.
% 0.18/0.51  		0:00:00.10 for the FLOTTER CNF translation.
% 0.18/0.51  		0:00:00.00 for inferences.
% 0.18/0.51  		0:00:00.00 for the backtracking.
% 0.18/0.51  		0:00:00.01 for the reduction.
% 0.18/0.51  
% 0.18/0.51  
% 0.18/0.51  Here is a proof with depth 2, length 13 :
% 0.18/0.51  % SZS output start Refutation
% See solution above
% 0.18/0.51  Formulae used in the proof : m__870 m__901 m__934 m__ mDefIdeal
% 0.18/0.51  
%------------------------------------------------------------------------------