TSTP Solution File: PUZ132+1 by Duper---1.0
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% File : Duper---1.0
% Problem : PUZ132+1 : TPTP v8.1.2. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 13:14:49 EDT 2023
% Result : Theorem 3.45s 3.61s
% Output : Proof 3.45s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : PUZ132+1 : TPTP v8.1.2. Released v4.1.0.
% 0.12/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n007.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Sat Aug 26 22:34:42 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.45/3.61 SZS status Theorem for theBenchmark.p
% 3.45/3.61 SZS output start Proof for theBenchmark.p
% 3.45/3.61 Clause #2 (by assumption #[]): Eq (∀ (A : Iota), capital A → city A) True
% 3.45/3.61 Clause #4 (by assumption #[]): Eq (capital washington) True
% 3.45/3.61 Clause #5 (by assumption #[]): Eq (country usa) True
% 3.45/3.61 Clause #7 (by assumption #[]): Eq (∀ (X : Iota), city X → has_crime X) True
% 3.45/3.61 Clause #8 (by assumption #[]): Eq (Eq (capital_city usa) washington) True
% 3.45/3.61 Clause #9 (by assumption #[]): Eq (∀ (X : Iota), country X → beautiful (capital_city X)) True
% 3.45/3.61 Clause #10 (by assumption #[]): Eq (Not (And (beautiful washington) (has_crime washington))) True
% 3.45/3.61 Clause #11 (by clausification #[2]): ∀ (a : Iota), Eq (capital a → city a) True
% 3.45/3.61 Clause #12 (by clausification #[11]): ∀ (a : Iota), Or (Eq (capital a) False) (Eq (city a) True)
% 3.45/3.61 Clause #13 (by superposition #[12, 4]): Or (Eq (city washington) True) (Eq False True)
% 3.45/3.61 Clause #14 (by clausification #[13]): Eq (city washington) True
% 3.45/3.61 Clause #15 (by clausification #[7]): ∀ (a : Iota), Eq (city a → has_crime a) True
% 3.45/3.61 Clause #16 (by clausification #[15]): ∀ (a : Iota), Or (Eq (city a) False) (Eq (has_crime a) True)
% 3.45/3.61 Clause #17 (by superposition #[16, 14]): Or (Eq (has_crime washington) True) (Eq False True)
% 3.45/3.61 Clause #21 (by clausification #[17]): Eq (has_crime washington) True
% 3.45/3.61 Clause #25 (by clausification #[9]): ∀ (a : Iota), Eq (country a → beautiful (capital_city a)) True
% 3.45/3.61 Clause #26 (by clausification #[25]): ∀ (a : Iota), Or (Eq (country a) False) (Eq (beautiful (capital_city a)) True)
% 3.45/3.61 Clause #27 (by superposition #[26, 5]): Or (Eq (beautiful (capital_city usa)) True) (Eq False True)
% 3.45/3.61 Clause #28 (by clausification #[27]): Eq (beautiful (capital_city usa)) True
% 3.45/3.61 Clause #29 (by clausification #[8]): Eq (capital_city usa) washington
% 3.45/3.61 Clause #30 (by backward demodulation #[29, 28]): Eq (beautiful washington) True
% 3.45/3.61 Clause #39 (by clausification #[10]): Eq (And (beautiful washington) (has_crime washington)) False
% 3.45/3.61 Clause #40 (by clausification #[39]): Or (Eq (beautiful washington) False) (Eq (has_crime washington) False)
% 3.45/3.61 Clause #41 (by forward demodulation #[40, 21]): Or (Eq (beautiful washington) False) (Eq True False)
% 3.45/3.61 Clause #42 (by clausification #[41]): Eq (beautiful washington) False
% 3.45/3.61 Clause #43 (by superposition #[42, 30]): Eq False True
% 3.45/3.61 Clause #44 (by clausification #[43]): False
% 3.45/3.61 SZS output end Proof for theBenchmark.p
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