TSTP Solution File: PRO019^1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : PRO019^1 : TPTP v8.1.2. Released v7.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 13:06:55 EDT 2023

% Result   : Theorem 3.94s 4.15s
% Output   : Proof 3.94s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem    : PRO019^1 : TPTP v8.1.2. Released v7.0.0.
% 0.10/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n028.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Mon Aug 28 19:38:25 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.94/4.15  SZS status Theorem for theBenchmark.p
% 3.94/4.15  SZS output start Proof for theBenchmark.p
% 3.94/4.15  Clause #2 (by assumption #[]): Eq
% 3.94/4.15    (∀ (A : Type) (Process : proces634752977rocess A),
% 3.94/4.15      Not (proces10484146Action A Process) → proces401113213Choice A Process)
% 3.94/4.15    True
% 3.94/4.15  Clause #268 (by assumption #[]): Eq (Not (Or (proces10484146Action a p) (proces401113213Choice a p))) True
% 3.94/4.15  Clause #273 (by clausification #[2]): ∀ (a : Type),
% 3.94/4.15    Eq (∀ (Process : proces634752977rocess a), Not (proces10484146Action a Process) → proces401113213Choice a Process)
% 3.94/4.15      True
% 3.94/4.15  Clause #274 (by clausification #[273]): ∀ (a : Type) (a_1 : proces634752977rocess a), Eq (Not (proces10484146Action a a_1) → proces401113213Choice a a_1) True
% 3.94/4.15  Clause #275 (by clausification #[274]): ∀ (a : Type) (a_1 : proces634752977rocess a),
% 3.94/4.15    Or (Eq (Not (proces10484146Action a a_1)) False) (Eq (proces401113213Choice a a_1) True)
% 3.94/4.15  Clause #276 (by clausification #[275]): ∀ (a : Type) (a_1 : proces634752977rocess a),
% 3.94/4.15    Or (Eq (proces401113213Choice a a_1) True) (Eq (proces10484146Action a a_1) True)
% 3.94/4.15  Clause #472 (by clausification #[268]): Eq (Or (proces10484146Action a p) (proces401113213Choice a p)) False
% 3.94/4.15  Clause #473 (by clausification #[472]): Eq (proces401113213Choice a p) False
% 3.94/4.15  Clause #474 (by clausification #[472]): Eq (proces10484146Action a p) False
% 3.94/4.15  Clause #475 (by superposition #[473, 276]): Or (Eq False True) (Eq (proces10484146Action a p) True)
% 3.94/4.15  Clause #476 (by clausification #[475]): Eq (proces10484146Action a p) True
% 3.94/4.15  Clause #477 (by superposition #[476, 474]): Eq True False
% 3.94/4.15  Clause #494 (by clausification #[477]): False
% 3.94/4.15  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------