TSTP Solution File: NUM972_5 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM972_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:58:29 EDT 2023

% Result   : Theorem 8.37s 8.58s
% Output   : Proof 8.37s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM972_5 : TPTP v8.1.2. Released v6.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n025.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Fri Aug 25 10:44:22 EDT 2023
% 0.12/0.34  % CPUTime    : 
% 8.37/8.58  SZS status Theorem for theBenchmark.p
% 8.37/8.58  SZS output start Proof for theBenchmark.p
% 8.37/8.58  Clause #0 (by assumption #[]): Eq (Eq t (one_one int)) True
% 8.37/8.58  Clause #1 (by assumption #[]): Eq
% 8.37/8.58    (twoSqu1567020053sum2sq
% 8.37/8.58      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))
% 8.37/8.58        t))
% 8.37/8.58    True
% 8.37/8.58  Clause #7 (by assumption #[]): Eq (∀ (L1 K3 : int), Eq (times_times int (bit1 K3) L1) (plus_plus int (bit0 (times_times int K3 L1)) L1)) True
% 8.37/8.58  Clause #9 (by assumption #[]): Eq (∀ (L1 K3 : int), Eq (plus_plus int (bit0 K3) (bit1 L1)) (bit1 (plus_plus int K3 L1))) True
% 8.37/8.58  Clause #25 (by assumption #[]): Eq (Eq (bit0 pls) pls) True
% 8.37/8.58  Clause #26 (by assumption #[]): Eq (∀ (W : int), Eq (times_times int pls W) pls) True
% 8.37/8.58  Clause #27 (by assumption #[]): Eq (∀ (L1 K3 : int), Eq (times_times int (bit0 K3) L1) (bit0 (times_times int K3 L1))) True
% 8.37/8.58  Clause #31 (by assumption #[]): Eq (∀ (K3 : int), Eq (number_number_of int K3) K3) True
% 8.37/8.58  Clause #32 (by assumption #[]): Eq (∀ (K3 : int), Eq (plus_plus int K3 pls) K3) True
% 8.37/8.58  Clause #33 (by assumption #[]): Eq (∀ (K3 : int), Eq (plus_plus int pls K3) K3) True
% 8.37/8.58  Clause #46 (by assumption #[]): Eq (∀ (A : Type), number_ring A → ∀ (A1 : A), Eq (times_times A A1 (number_number_of A (bit1 pls))) A1) True
% 8.37/8.58  Clause #48 (by assumption #[]): Eq (Eq (one_one int) (number_number_of int (bit1 pls))) True
% 8.37/8.58  Clause #100 (by assumption #[]): Eq (number_ring int) True
% 8.37/8.58  Clause #110 (by assumption #[]): Eq
% 8.37/8.58    (Not
% 8.37/8.58      (twoSqu1567020053sum2sq
% 8.37/8.58        (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int))))
% 8.37/8.58    True
% 8.37/8.58  Clause #111 (by clausification #[0]): Eq t (one_one int)
% 8.37/8.58  Clause #112 (by forward demodulation #[1, 111]): Eq
% 8.37/8.58    (twoSqu1567020053sum2sq
% 8.37/8.58      (times_times int (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) t) t))
% 8.37/8.58    True
% 8.37/8.58  Clause #126 (by clausification #[25]): Eq (bit0 pls) pls
% 8.37/8.58  Clause #140 (by clausification #[31]): ∀ (a : int), Eq (Eq (number_number_of int a) a) True
% 8.37/8.58  Clause #141 (by clausification #[140]): ∀ (a : int), Eq (number_number_of int a) a
% 8.37/8.58  Clause #142 (by backward demodulation #[141, 112]): Eq (twoSqu1567020053sum2sq (times_times int (plus_plus int (times_times int (bit0 (bit0 (bit1 pls))) m) t) t)) True
% 8.37/8.58  Clause #150 (by clausification #[48]): Eq (one_one int) (number_number_of int (bit1 pls))
% 8.37/8.58  Clause #151 (by forward demodulation #[150, 111]): Eq t (number_number_of int (bit1 pls))
% 8.37/8.58  Clause #152 (by superposition #[151, 141]): Eq t (bit1 pls)
% 8.37/8.58  Clause #163 (by clausification #[26]): ∀ (a : int), Eq (Eq (times_times int pls a) pls) True
% 8.37/8.58  Clause #164 (by clausification #[163]): ∀ (a : int), Eq (times_times int pls a) pls
% 8.37/8.58  Clause #168 (by clausification #[33]): ∀ (a : int), Eq (Eq (plus_plus int pls a) a) True
% 8.37/8.58  Clause #169 (by clausification #[168]): ∀ (a : int), Eq (plus_plus int pls a) a
% 8.37/8.58  Clause #170 (by clausification #[32]): ∀ (a : int), Eq (Eq (plus_plus int a pls) a) True
% 8.37/8.58  Clause #171 (by clausification #[170]): ∀ (a : int), Eq (plus_plus int a pls) a
% 8.37/8.58  Clause #174 (by clausification #[7]): ∀ (a : int), Eq (∀ (K3 : int), Eq (times_times int (bit1 K3) a) (plus_plus int (bit0 (times_times int K3 a)) a)) True
% 8.37/8.58  Clause #175 (by clausification #[174]): ∀ (a a_1 : int), Eq (Eq (times_times int (bit1 a) a_1) (plus_plus int (bit0 (times_times int a a_1)) a_1)) True
% 8.37/8.58  Clause #176 (by clausification #[175]): ∀ (a a_1 : int), Eq (times_times int (bit1 a) a_1) (plus_plus int (bit0 (times_times int a a_1)) a_1)
% 8.37/8.58  Clause #178 (by superposition #[176, 164]): ∀ (a : int), Eq (times_times int (bit1 pls) a) (plus_plus int (bit0 pls) a)
% 8.37/8.58  Clause #184 (by forward demodulation #[178, 152]): ∀ (a : int), Eq (times_times int t a) (plus_plus int (bit0 pls) a)
% 8.37/8.58  Clause #185 (by forward demodulation #[184, 126]): ∀ (a : int), Eq (times_times int t a) (plus_plus int pls a)
% 8.37/8.58  Clause #186 (by forward demodulation #[185, 169]): ∀ (a : int), Eq (times_times int t a) a
% 8.37/8.58  Clause #208 (by clausification #[9]): ∀ (a : int), Eq (∀ (K3 : int), Eq (plus_plus int (bit0 K3) (bit1 a)) (bit1 (plus_plus int K3 a))) True
% 8.37/8.60  Clause #209 (by clausification #[208]): ∀ (a a_1 : int), Eq (Eq (plus_plus int (bit0 a) (bit1 a_1)) (bit1 (plus_plus int a a_1))) True
% 8.37/8.60  Clause #210 (by clausification #[209]): ∀ (a a_1 : int), Eq (plus_plus int (bit0 a) (bit1 a_1)) (bit1 (plus_plus int a a_1))
% 8.37/8.60  Clause #214 (by superposition #[210, 152]): ∀ (a : int), Eq (plus_plus int (bit0 a) t) (bit1 (plus_plus int a pls))
% 8.37/8.60  Clause #391 (by clausification #[27]): ∀ (a : int), Eq (∀ (K3 : int), Eq (times_times int (bit0 K3) a) (bit0 (times_times int K3 a))) True
% 8.37/8.60  Clause #392 (by clausification #[391]): ∀ (a a_1 : int), Eq (Eq (times_times int (bit0 a) a_1) (bit0 (times_times int a a_1))) True
% 8.37/8.60  Clause #393 (by clausification #[392]): ∀ (a a_1 : int), Eq (times_times int (bit0 a) a_1) (bit0 (times_times int a a_1))
% 8.37/8.60  Clause #414 (by superposition #[393, 186]): ∀ (a : int), Eq (times_times int (bit0 t) a) (bit0 a)
% 8.37/8.60  Clause #434 (by superposition #[414, 393]): ∀ (a : int), Eq (times_times int (bit0 (bit0 t)) a) (bit0 (bit0 a))
% 8.37/8.60  Clause #735 (by clausification #[46]): ∀ (a : Type), Eq (number_ring a → ∀ (A1 : a), Eq (times_times a A1 (number_number_of a (bit1 pls))) A1) True
% 8.37/8.60  Clause #736 (by clausification #[735]): ∀ (a : Type),
% 8.37/8.60    Or (Eq (number_ring a) False) (Eq (∀ (A1 : a), Eq (times_times a A1 (number_number_of a (bit1 pls))) A1) True)
% 8.37/8.60  Clause #737 (by clausification #[736]): ∀ (a : Type) (a_1 : a),
% 8.37/8.60    Or (Eq (number_ring a) False) (Eq (Eq (times_times a a_1 (number_number_of a (bit1 pls))) a_1) True)
% 8.37/8.60  Clause #738 (by clausification #[737]): ∀ (a : Type) (a_1 : a), Or (Eq (number_ring a) False) (Eq (times_times a a_1 (number_number_of a (bit1 pls))) a_1)
% 8.37/8.60  Clause #739 (by forward demodulation #[738, 152]): ∀ (a : Type) (a_1 : a), Or (Eq (number_ring a) False) (Eq (times_times a a_1 (number_number_of a t)) a_1)
% 8.37/8.60  Clause #740 (by superposition #[739, 100]): ∀ (a : int), Or (Eq (times_times int a (number_number_of int t)) a) (Eq False True)
% 8.37/8.60  Clause #741 (by clausification #[740]): ∀ (a : int), Eq (times_times int a (number_number_of int t)) a
% 8.37/8.60  Clause #742 (by forward demodulation #[741, 141]): ∀ (a : int), Eq (times_times int a t) a
% 8.37/8.60  Clause #1009 (by forward demodulation #[214, 171]): ∀ (a : int), Eq (plus_plus int (bit0 a) t) (bit1 a)
% 8.37/8.60  Clause #1522 (by clausification #[110]): Eq
% 8.37/8.60    (twoSqu1567020053sum2sq
% 8.37/8.60      (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) (one_one int)))
% 8.37/8.60    False
% 8.37/8.60  Clause #1523 (by forward demodulation #[1522, 111]): Eq (twoSqu1567020053sum2sq (plus_plus int (times_times int (number_number_of int (bit0 (bit0 (bit1 pls)))) m) t)) False
% 8.37/8.60  Clause #1524 (by forward demodulation #[1523, 141]): Eq (twoSqu1567020053sum2sq (plus_plus int (times_times int (bit0 (bit0 (bit1 pls))) m) t)) False
% 8.37/8.60  Clause #1525 (by forward demodulation #[1524, 152]): Eq (twoSqu1567020053sum2sq (plus_plus int (times_times int (bit0 (bit0 t)) m) t)) False
% 8.37/8.60  Clause #1526 (by forward demodulation #[1525, 434]): Eq (twoSqu1567020053sum2sq (plus_plus int (bit0 (bit0 m)) t)) False
% 8.37/8.60  Clause #1527 (by forward demodulation #[1526, 1009]): Eq (twoSqu1567020053sum2sq (bit1 (bit0 m))) False
% 8.37/8.60  Clause #1588 (by forward demodulation #[142, 742]): Eq (twoSqu1567020053sum2sq (plus_plus int (times_times int (bit0 (bit0 (bit1 pls))) m) t)) True
% 8.37/8.60  Clause #1589 (by forward demodulation #[1588, 152]): Eq (twoSqu1567020053sum2sq (plus_plus int (times_times int (bit0 (bit0 t)) m) t)) True
% 8.37/8.60  Clause #1590 (by forward demodulation #[1589, 434]): Eq (twoSqu1567020053sum2sq (plus_plus int (bit0 (bit0 m)) t)) True
% 8.37/8.60  Clause #1591 (by forward demodulation #[1590, 1009]): Eq (twoSqu1567020053sum2sq (bit1 (bit0 m))) True
% 8.37/8.60  Clause #1592 (by superposition #[1591, 1527]): Eq True False
% 8.37/8.60  Clause #1595 (by clausification #[1592]): False
% 8.37/8.60  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------