TSTP Solution File: NUM808^5 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : NUM808^5 : TPTP v7.0.0. Bugfixed v5.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n171.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:49 EST 2018

% Result   : Unknown 0.84s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----No solution output by system
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM808^5 : TPTP v7.0.0. Bugfixed v5.2.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.02/0.22  % Computer : n171.star.cs.uiowa.edu
% 0.02/0.22  % Model    : x86_64 x86_64
% 0.02/0.22  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.22  % Memory   : 32218.625MB
% 0.02/0.22  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.22  % CPULimit : 300
% 0.02/0.22  % DateTime : Fri Jan  5 14:24:50 CST 2018
% 0.02/0.23  % CPUTime  : 
% 0.02/0.24  Python 2.7.13
% 0.84/1.08  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.84/1.08  FOF formula (<kernel.Constant object at 0x2b082a628440>, <kernel.Constant object at 0x2b082a628638>) of role type named c0_type
% 0.84/1.08  Using role type
% 0.84/1.08  Declaring c0:fofType
% 0.84/1.08  FOF formula (<kernel.Constant object at 0x2b082ad45908>, <kernel.DependentProduct object at 0x2b082a628878>) of role type named cS_type
% 0.84/1.08  Using role type
% 0.84/1.08  Declaring cS:(fofType->fofType)
% 0.84/1.08  FOF formula (<kernel.Constant object at 0x2b082a628b00>, <kernel.DependentProduct object at 0x2b082a628440>) of role type named r_type
% 0.84/1.08  Using role type
% 0.84/1.08  Declaring r:(fofType->(fofType->Prop))
% 0.84/1.08  FOF formula (<kernel.Constant object at 0x2b082a628488>, <kernel.Sort object at 0x2b082a679560>) of role type named cIND_type
% 0.84/1.08  Using role type
% 0.84/1.08  Declaring cIND:Prop
% 0.84/1.08  FOF formula (((eq Prop) cIND) (forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx))))) of role definition named cIND_def
% 0.84/1.08  A new definition: (((eq Prop) cIND) (forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx)))))
% 0.84/1.08  Defined: cIND:=(forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx))))
% 0.84/1.08  FOF formula (((and ((and cIND) ((r c0) c0))) (forall (Xx:fofType), (((r Xx) Xx)->((r (cS Xx)) (cS Xx)))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((r Xx) Xy))))) of role conjecture named cTHM130A
% 0.84/1.08  Conjecture to prove = (((and ((and cIND) ((r c0) c0))) (forall (Xx:fofType), (((r Xx) Xx)->((r (cS Xx)) (cS Xx)))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((r Xx) Xy))))):Prop
% 0.84/1.08  We need to prove ['(((and ((and cIND) ((r c0) c0))) (forall (Xx:fofType), (((r Xx) Xx)->((r (cS Xx)) (cS Xx)))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((r Xx) Xy)))))']
% 0.84/1.08  Parameter fofType:Type.
% 0.84/1.08  Parameter c0:fofType.
% 0.84/1.08  Parameter cS:(fofType->fofType).
% 0.84/1.08  Parameter r:(fofType->(fofType->Prop)).
% 0.84/1.08  Definition cIND:=(forall (Xp:(fofType->Prop)), (((and (Xp c0)) (forall (Xx:fofType), ((Xp Xx)->(Xp (cS Xx)))))->(forall (Xx:fofType), (Xp Xx)))):Prop.
% 0.84/1.08  Trying to prove (((and ((and cIND) ((r c0) c0))) (forall (Xx:fofType), (((r Xx) Xx)->((r (cS Xx)) (cS Xx)))))->(forall (Xx:fofType), ((ex fofType) (fun (Xy:fofType)=> ((r Xx) Xy)))))
% 0.84/1.08  % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
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