%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : NUM781^3 : TPTP v7.0.0. Released v5.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n059.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:43 EST 2018

% Result   : Theorem 0.35s
% Output   : Proof 0.35s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM781^3 : TPTP v7.0.0. Released v5.1.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.23  % Computer : n059.star.cs.uiowa.edu
% 0.02/0.23  % Model    : x86_64 x86_64
% 0.02/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23  % Memory   : 32218.625MB
% 0.02/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23  % CPULimit : 300
% 0.02/0.23  % DateTime : Fri Jan  5 14:08:18 CST 2018
% 0.06/0.24  % CPUTime  : 
% 0.06/0.25  Python 2.7.13
% 0.35/0.58  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.35/0.58  FOF formula (<kernel.Constant object at 0x2ae9f45d84d0>, <kernel.Constant object at 0x2ae9f45d8488>) of role type named cY
% 0.35/0.58  Using role type
% 0.35/0.58  Declaring cY:fofType
% 0.35/0.58  FOF formula (<kernel.Constant object at 0x2ae9f45cc128>, <kernel.Single object at 0x2ae9f45d8320>) of role type named cX
% 0.35/0.58  Using role type
% 0.35/0.58  Declaring cX:fofType
% 0.35/0.58  FOF formula ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)) of role conjecture named cTHM76
% 0.35/0.58  Conjecture to prove = ((((eq fofType) cY) cX)->(((eq fofType) cX) cY)):Prop
% 0.35/0.58  We need to prove ['((((eq fofType) cY) cX)->(((eq fofType) cX) cY))']
% 0.35/0.58  Parameter fofType:Type.
% 0.35/0.58  Parameter cY:fofType.
% 0.35/0.58  Parameter cX:fofType.
% 0.35/0.58  Trying to prove ((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Found eq_sym000:=(eq_sym00 cX):((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Found (eq_sym00 cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Found ((eq_sym0 cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Found (((eq_sym fofType) cY) cX) as proof of ((((eq fofType) cY) cX)->(((eq fofType) cX) cY))
% 0.35/0.58  Got proof (((eq_sym fofType) cY) cX)
% 0.35/0.58  Time elapsed = 0.067406s
% 0.35/0.58  node=4 cost=-290.000000 depth=3
% 0.35/0.58::::::::::::::::::::::
% 0.35/0.58  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.35/0.58  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.35/0.58  (((eq_sym fofType) cY) cX)
% 0.35/0.58  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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