%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : NUM781^2 : TPTP v7.0.0. Released v5.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n164.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32218.625MB
% OS       : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan  8 13:11:42 EST 2018

% Result   : Theorem 0.37s
% Output   : Proof 0.37s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03  % Problem  : NUM781^2 : TPTP v7.0.0. Released v5.1.0.
% 0.00/0.04  % Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.03/0.23  % Computer : n164.star.cs.uiowa.edu
% 0.03/0.23  % Model    : x86_64 x86_64
% 0.03/0.23  % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.03/0.23  % Memory   : 32218.625MB
% 0.03/0.23  % OS       : Linux 3.10.0-693.2.2.el7.x86_64
% 0.03/0.23  % CPULimit : 300
% 0.03/0.23  % DateTime : Fri Jan  5 14:08:34 CST 2018
% 0.06/0.23  % CPUTime  : 
% 0.07/0.25  Python 2.7.13
% 0.37/0.56  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.37/0.56  FOF formula (<kernel.Constant object at 0x2acd39e00fc8>, <kernel.Type object at 0x2acd39e04cb0>) of role type named a_type
% 0.37/0.56  Using role type
% 0.37/0.56  Declaring a:Type
% 0.37/0.56  FOF formula (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))) of role conjecture named cES_eq_
% 0.37/0.56  Conjecture to prove = (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A))):Prop
% 0.37/0.56  Parameter a_DUMMY:a.
% 0.37/0.56  We need to prove ['(forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A)))']
% 0.37/0.56  Parameter a:Type.
% 0.37/0.56  Trying to prove (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A)))
% 0.37/0.56  Found eq_sym0:=(eq_sym a):(forall (a0:a) (b:a), ((((eq a) a0) b)->(((eq a) b) a0)))
% 0.37/0.56  Found (eq_sym a) as proof of (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A)))
% 0.37/0.56  Found (eq_sym a) as proof of (forall (A:a) (B:a), ((((eq a) A) B)->(((eq a) B) A)))
% 0.37/0.56  Got proof (eq_sym a)
% 0.37/0.56  Time elapsed = 0.050991s
% 0.37/0.56  node=2 cost=-97.000000 depth=1
% 0.37/0.56::::::::::::::::::::::
% 0.37/0.56  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.37/0.56  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.37/0.56  (eq_sym a)
% 0.37/0.56  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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