TSTP Solution File: NUM759^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM759^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:33 EDT 2023
% Result : Theorem 3.63s 3.82s
% Output : Proof 3.63s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12 % Problem : NUM759^1 : TPTP v8.1.2. Released v3.7.0.
% 0.10/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n005.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Fri Aug 25 17:19:53 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.63/3.82 SZS status Theorem for theBenchmark.p
% 3.63/3.82 SZS output start Proof for theBenchmark.p
% 3.63/3.82 Clause #0 (by assumption #[]): Eq (eq (pf z x) (pf z y)) True
% 3.63/3.82 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy Xz : frac), eq (pf Xx Xz) (pf Xy Xz) → eq Xx Xy) True
% 3.63/3.82 Clause #2 (by assumption #[]): Eq (∀ (Xx Xy Xz : frac), eq Xx Xy → eq Xy Xz → eq Xx Xz) True
% 3.63/3.82 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : frac), eq (pf Xx Xy) (pf Xy Xx)) True
% 3.63/3.82 Clause #4 (by assumption #[]): Eq (Not (eq x y)) True
% 3.63/3.82 Clause #5 (by clausification #[4]): Eq (eq x y) False
% 3.63/3.82 Clause #6 (by clausification #[1]): ∀ (a : frac), Eq (∀ (Xy Xz : frac), eq (pf a Xz) (pf Xy Xz) → eq a Xy) True
% 3.63/3.82 Clause #7 (by clausification #[6]): ∀ (a a_1 : frac), Eq (∀ (Xz : frac), eq (pf a Xz) (pf a_1 Xz) → eq a a_1) True
% 3.63/3.82 Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : frac), Eq (eq (pf a a_1) (pf a_2 a_1) → eq a a_2) True
% 3.63/3.82 Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : frac), Or (Eq (eq (pf a a_1) (pf a_2 a_1)) False) (Eq (eq a a_2) True)
% 3.63/3.82 Clause #10 (by clausification #[2]): ∀ (a : frac), Eq (∀ (Xy Xz : frac), eq a Xy → eq Xy Xz → eq a Xz) True
% 3.63/3.82 Clause #11 (by clausification #[10]): ∀ (a a_1 : frac), Eq (∀ (Xz : frac), eq a a_1 → eq a_1 Xz → eq a Xz) True
% 3.63/3.82 Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : frac), Eq (eq a a_1 → eq a_1 a_2 → eq a a_2) True
% 3.63/3.82 Clause #13 (by clausification #[12]): ∀ (a a_1 a_2 : frac), Or (Eq (eq a a_1) False) (Eq (eq a_1 a_2 → eq a a_2) True)
% 3.63/3.82 Clause #14 (by clausification #[13]): ∀ (a a_1 a_2 : frac), Or (Eq (eq a a_1) False) (Or (Eq (eq a_1 a_2) False) (Eq (eq a a_2) True))
% 3.63/3.82 Clause #15 (by superposition #[14, 0]): ∀ (a : frac), Or (Eq (eq (pf z y) a) False) (Or (Eq (eq (pf z x) a) True) (Eq False True))
% 3.63/3.82 Clause #16 (by clausification #[3]): ∀ (a : frac), Eq (∀ (Xy : frac), eq (pf a Xy) (pf Xy a)) True
% 3.63/3.82 Clause #17 (by clausification #[16]): ∀ (a a_1 : frac), Eq (eq (pf a a_1) (pf a_1 a)) True
% 3.63/3.82 Clause #19 (by superposition #[17, 14]): ∀ (a a_1 a_2 : frac), Or (Eq True False) (Or (Eq (eq (pf a a_1) a_2) False) (Eq (eq (pf a_1 a) a_2) True))
% 3.63/3.82 Clause #20 (by clausification #[15]): ∀ (a : frac), Or (Eq (eq (pf z y) a) False) (Eq (eq (pf z x) a) True)
% 3.63/3.82 Clause #21 (by superposition #[20, 17]): Or (Eq (eq (pf z x) (pf y z)) True) (Eq False True)
% 3.63/3.82 Clause #26 (by clausification #[21]): Eq (eq (pf z x) (pf y z)) True
% 3.63/3.82 Clause #30 (by clausification #[19]): ∀ (a a_1 a_2 : frac), Or (Eq (eq (pf a a_1) a_2) False) (Eq (eq (pf a_1 a) a_2) True)
% 3.63/3.82 Clause #33 (by superposition #[30, 26]): Or (Eq (eq (pf x z) (pf y z)) True) (Eq False True)
% 3.63/3.82 Clause #35 (by clausification #[33]): Eq (eq (pf x z) (pf y z)) True
% 3.63/3.82 Clause #36 (by superposition #[35, 9]): Or (Eq True False) (Eq (eq x y) True)
% 3.63/3.82 Clause #39 (by clausification #[36]): Eq (eq x y) True
% 3.63/3.82 Clause #40 (by superposition #[39, 5]): Eq True False
% 3.63/3.82 Clause #42 (by clausification #[40]): False
% 3.63/3.82 SZS output end Proof for theBenchmark.p
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