%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM750^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:57:28 EDT 2023

% Result   : Theorem 3.37s 3.76s
% Output   : Proof 3.37s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM750^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n018.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Aug 25 12:37:13 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.37/3.76  SZS status Theorem for theBenchmark.p
% 3.37/3.76  SZS output start Proof for theBenchmark.p
% 3.37/3.76  Clause #0 (by assumption #[]): Eq (eq x y) True
% 3.37/3.76  Clause #1 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : frac), eq Xx Xy → eq Xz Xu → eq (pf Xx Xz) (pf Xy Xu)) True
% 3.37/3.76  Clause #2 (by assumption #[]): Eq (∀ (Xx : frac), eq Xx Xx) True
% 3.37/3.76  Clause #3 (by assumption #[]): Eq (Not (eq (pf x z) (pf y z))) True
% 3.37/3.76  Clause #4 (by clausification #[2]): ∀ (a : frac), Eq (eq a a) True
% 3.37/3.76  Clause #5 (by clausification #[3]): Eq (eq (pf x z) (pf y z)) False
% 3.37/3.76  Clause #6 (by clausification #[1]): ∀ (a : frac), Eq (∀ (Xy Xz Xu : frac), eq a Xy → eq Xz Xu → eq (pf a Xz) (pf Xy Xu)) True
% 3.37/3.76  Clause #7 (by clausification #[6]): ∀ (a a_1 : frac), Eq (∀ (Xz Xu : frac), eq a a_1 → eq Xz Xu → eq (pf a Xz) (pf a_1 Xu)) True
% 3.37/3.76  Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : frac), Eq (∀ (Xu : frac), eq a a_1 → eq a_2 Xu → eq (pf a a_2) (pf a_1 Xu)) True
% 3.37/3.76  Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 a_3 : frac), Eq (eq a a_1 → eq a_2 a_3 → eq (pf a a_2) (pf a_1 a_3)) True
% 3.37/3.76  Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 a_3 : frac), Or (Eq (eq a a_1) False) (Eq (eq a_2 a_3 → eq (pf a a_2) (pf a_1 a_3)) True)
% 3.37/3.76  Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 a_3 : frac), Or (Eq (eq a a_1) False) (Or (Eq (eq a_2 a_3) False) (Eq (eq (pf a a_2) (pf a_1 a_3)) True))
% 3.37/3.76  Clause #12 (by superposition #[11, 0]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Or (Eq (eq (pf x a) (pf y a_1)) True) (Eq False True))
% 3.37/3.76  Clause #17 (by clausification #[12]): ∀ (a a_1 : frac), Or (Eq (eq a a_1) False) (Eq (eq (pf x a) (pf y a_1)) True)
% 3.37/3.76  Clause #19 (by superposition #[17, 4]): ∀ (a : frac), Or (Eq (eq (pf x a) (pf y a)) True) (Eq False True)
% 3.37/3.76  Clause #20 (by clausification #[19]): ∀ (a : frac), Eq (eq (pf x a) (pf y a)) True
% 3.37/3.76  Clause #21 (by superposition #[20, 5]): Eq True False
% 3.37/3.76  Clause #25 (by clausification #[21]): False
% 3.37/3.76  SZS output end Proof for theBenchmark.p
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