TSTP Solution File: NUM707^1 by cocATP---0.2.0
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% File : cocATP---0.2.0
% Problem : NUM707^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n171.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.625MB
% OS : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan 8 13:11:31 EST 2018
% Result : Theorem 0.51s
% Output : Proof 0.51s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : NUM707^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.03/0.23 % Computer : n171.star.cs.uiowa.edu
% 0.03/0.23 % Model : x86_64 x86_64
% 0.03/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.03/0.23 % Memory : 32218.625MB
% 0.03/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64
% 0.03/0.23 % CPULimit : 300
% 0.03/0.23 % DateTime : Fri Jan 5 13:07:50 CST 2018
% 0.03/0.23 % CPUTime :
% 0.03/0.25 Python 2.7.13
% 0.51/0.70 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.Type object at 0x2b782a22fe18>) of role type named nat_type
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring nat:Type
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22fcf8>, <kernel.Constant object at 0x2b782a22fea8>) of role type named x
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring x:nat
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a30df38>, <kernel.Constant object at 0x2b782a22fea8>) of role type named y
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring y:nat
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.DependentProduct object at 0x2b782a5facf8>) of role type named pl
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring pl:(nat->(nat->nat))
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22fcf8>, <kernel.DependentProduct object at 0x2b782a5faf38>) of role type named ts
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring ts:(nat->(nat->nat))
% 0.51/0.70 FOF formula (<kernel.Constant object at 0x2b782a22f2d8>, <kernel.DependentProduct object at 0x2b782a5facb0>) of role type named suc
% 0.51/0.70 Using role type
% 0.51/0.70 Declaring suc:(nat->nat)
% 0.51/0.70 FOF formula (forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx))) of role axiom named satz28b
% 0.51/0.70 A new axiom: (forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx)))
% 0.51/0.70 FOF formula (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))) of role conjecture named satz28f
% 0.51/0.70 Conjecture to prove = (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y))):Prop
% 0.51/0.70 We need to prove ['(((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))']
% 0.51/0.70 Parameter nat:Type.
% 0.51/0.70 Parameter x:nat.
% 0.51/0.70 Parameter y:nat.
% 0.51/0.70 Parameter pl:(nat->(nat->nat)).
% 0.51/0.70 Parameter ts:(nat->(nat->nat)).
% 0.51/0.70 Parameter suc:(nat->nat).
% 0.51/0.70 Axiom satz28b:(forall (Xx:nat) (Xy:nat), (((eq nat) ((ts Xx) (suc Xy))) ((pl ((ts Xx) Xy)) Xx))).
% 0.51/0.70 Trying to prove (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Found eq_ref00:=(eq_ref0 ((ts x) (suc y))):(((eq nat) ((ts x) (suc y))) ((ts x) (suc y)))
% 0.51/0.70 Found (eq_ref0 ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y)))
% 0.51/0.70 Found ((eq_ref nat) ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y)))
% 0.51/0.70 Found ((eq_ref nat) ((ts x) (suc y))) as proof of (((eq nat) ((ts x) (suc y))) ((ts x) (suc y)))
% 0.51/0.70 Found (satz28b000 ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Found ((satz28b00 (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Found (((satz28b0 y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Found ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Found ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y)))) as proof of (((eq nat) ((pl ((ts x) y)) x)) ((ts x) (suc y)))
% 0.51/0.70 Got proof ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y))))
% 0.51/0.70 Time elapsed = 0.176334s
% 0.51/0.70 node=27 cost=-103.000000 depth=7
% 0.51/0.70::::::::::::::::::::::
% 0.51/0.70 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.51/0.70 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.51/0.70 ((((satz28b x) y) (fun (x1:nat)=> (((eq nat) x1) ((ts x) (suc y))))) ((eq_ref nat) ((ts x) (suc y))))
% 0.51/0.70 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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