TSTP Solution File: NUM697^1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : NUM697^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:08 EDT 2023
% Result : Theorem 3.41s 3.73s
% Output : Proof 3.41s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.13/0.14 % Problem : NUM697^1 : TPTP v8.1.2. Released v3.7.0.
% 0.13/0.15 % Command : duper %s
% 0.15/0.36 % Computer : n016.cluster.edu
% 0.15/0.36 % Model : x86_64 x86_64
% 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36 % Memory : 8042.1875MB
% 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36 % CPULimit : 300
% 0.15/0.36 % WCLimit : 300
% 0.15/0.36 % DateTime : Fri Aug 25 10:57:25 EDT 2023
% 0.15/0.37 % CPUTime :
% 3.41/3.73 SZS status Theorem for theBenchmark.p
% 3.41/3.73 SZS output start Proof for theBenchmark.p
% 3.41/3.73 Clause #0 (by assumption #[]): Eq (more y x) True
% 3.41/3.73 Clause #1 (by assumption #[]): Eq (∀ (Xx Xy : nat), more Xy Xx → moreis Xy (pl Xx n_1)) True
% 3.41/3.73 Clause #2 (by assumption #[]): Eq (∀ (Xx : nat), Eq (pl Xx n_1) (suc Xx)) True
% 3.41/3.73 Clause #3 (by assumption #[]): Eq (Not (moreis y (suc x))) True
% 3.41/3.73 Clause #4 (by clausification #[3]): Eq (moreis y (suc x)) False
% 3.41/3.73 Clause #5 (by clausification #[2]): ∀ (a : nat), Eq (Eq (pl a n_1) (suc a)) True
% 3.41/3.73 Clause #6 (by clausification #[5]): ∀ (a : nat), Eq (pl a n_1) (suc a)
% 3.41/3.73 Clause #7 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy : nat), more Xy a → moreis Xy (pl a n_1)) True
% 3.41/3.73 Clause #8 (by clausification #[7]): ∀ (a a_1 : nat), Eq (more a a_1 → moreis a (pl a_1 n_1)) True
% 3.41/3.73 Clause #9 (by clausification #[8]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Eq (moreis a (pl a_1 n_1)) True)
% 3.41/3.73 Clause #10 (by forward demodulation #[9, 6]): ∀ (a a_1 : nat), Or (Eq (more a a_1) False) (Eq (moreis a (suc a_1)) True)
% 3.41/3.73 Clause #11 (by superposition #[10, 0]): Or (Eq (moreis y (suc x)) True) (Eq False True)
% 3.41/3.73 Clause #12 (by clausification #[11]): Eq (moreis y (suc x)) True
% 3.41/3.73 Clause #13 (by superposition #[12, 4]): Eq True False
% 3.41/3.73 Clause #14 (by clausification #[13]): False
% 3.41/3.73 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------