TSTP Solution File: NUM689^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM689^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:03 EDT 2023
% Result : Theorem 3.76s 4.14s
% Output : Proof 3.76s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM689^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n014.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 13:07:03 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.76/4.14 SZS status Theorem for theBenchmark.p
% 3.76/4.14 SZS output start Proof for theBenchmark.p
% 3.76/4.14 Clause #0 (by assumption #[]): Eq (lessis x y) True
% 3.76/4.14 Clause #1 (by assumption #[]): Eq (some fun Xv => diffprop u z Xv) True
% 3.76/4.14 Clause #2 (by assumption #[]): Eq
% 3.76/4.14 (∀ (Xx Xy Xz Xu : nat),
% 3.76/4.14 moreis Xx Xy → (some fun Xu_0 => diffprop Xz Xu Xu_0) → some fun Xu_0 => diffprop (pl Xx Xz) (pl Xy Xu) Xu_0)
% 3.76/4.14 True
% 3.76/4.14 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : nat), lessis Xx Xy → moreis Xy Xx) True
% 3.76/4.14 Clause #4 (by assumption #[]): Eq (Not (some fun Xv => diffprop (pl y u) (pl x z) Xv)) True
% 3.76/4.14 Clause #5 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy : nat), lessis a Xy → moreis Xy a) True
% 3.76/4.14 Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (lessis a a_1 → moreis a_1 a) True
% 3.76/4.14 Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Or (Eq (lessis a a_1) False) (Eq (moreis a_1 a) True)
% 3.76/4.14 Clause #8 (by superposition #[7, 0]): Or (Eq (moreis y x) True) (Eq False True)
% 3.76/4.14 Clause #9 (by clausification #[8]): Eq (moreis y x) True
% 3.76/4.14 Clause #10 (by betaEtaReduce #[1]): Eq (some (diffprop u z)) True
% 3.76/4.14 Clause #11 (by betaEtaReduce #[4]): Eq (Not (some (diffprop (pl y u) (pl x z)))) True
% 3.76/4.14 Clause #12 (by clausification #[11]): Eq (some (diffprop (pl y u) (pl x z))) False
% 3.76/4.14 Clause #13 (by betaEtaReduce #[2]): Eq (∀ (Xx Xy Xz Xu : nat), moreis Xx Xy → some (diffprop Xz Xu) → some (diffprop (pl Xx Xz) (pl Xy Xu))) True
% 3.76/4.14 Clause #14 (by clausification #[13]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), moreis a Xy → some (diffprop Xz Xu) → some (diffprop (pl a Xz) (pl Xy Xu))) True
% 3.76/4.14 Clause #15 (by clausification #[14]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), moreis a a_1 → some (diffprop Xz Xu) → some (diffprop (pl a Xz) (pl a_1 Xu))) True
% 3.76/4.14 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 : nat),
% 3.76/4.14 Eq (∀ (Xu : nat), moreis a a_1 → some (diffprop a_2 Xu) → some (diffprop (pl a a_2) (pl a_1 Xu))) True
% 3.76/4.14 Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 a_3 : nat), Eq (moreis a a_1 → some (diffprop a_2 a_3) → some (diffprop (pl a a_2) (pl a_1 a_3))) True
% 3.76/4.14 Clause #18 (by clausification #[17]): ∀ (a a_1 a_2 a_3 : nat),
% 3.76/4.14 Or (Eq (moreis a a_1) False) (Eq (some (diffprop a_2 a_3) → some (diffprop (pl a a_2) (pl a_1 a_3))) True)
% 3.76/4.14 Clause #19 (by clausification #[18]): ∀ (a a_1 a_2 a_3 : nat),
% 3.76/4.14 Or (Eq (moreis a a_1) False)
% 3.76/4.14 (Or (Eq (some (diffprop a_2 a_3)) False) (Eq (some (diffprop (pl a a_2) (pl a_1 a_3))) True))
% 3.76/4.14 Clause #20 (by superposition #[19, 9]): ∀ (a a_1 : nat),
% 3.76/4.14 Or (Eq (some (diffprop a a_1)) False) (Or (Eq (some (diffprop (pl y a) (pl x a_1))) True) (Eq False True))
% 3.76/4.14 Clause #21 (by clausification #[20]): ∀ (a a_1 : nat), Or (Eq (some (diffprop a a_1)) False) (Eq (some (diffprop (pl y a) (pl x a_1))) True)
% 3.76/4.14 Clause #22 (by superposition #[21, 10]): Or (Eq (some (diffprop (pl y u) (pl x z))) True) (Eq False True)
% 3.76/4.14 Clause #23 (by clausification #[22]): Eq (some (diffprop (pl y u) (pl x z))) True
% 3.76/4.14 Clause #24 (by superposition #[23, 12]): Eq True False
% 3.76/4.14 Clause #26 (by clausification #[24]): False
% 3.76/4.14 SZS output end Proof for theBenchmark.p
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