%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM684^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:57:01 EDT 2023

% Result   : Theorem 3.36s 3.57s
% Output   : Proof 3.36s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : NUM684^1 : TPTP v8.1.2. Released v3.7.0.
% 0.13/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n021.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Fri Aug 25 08:24:11 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.36/3.57  SZS status Theorem for theBenchmark.p
% 3.36/3.57  SZS output start Proof for theBenchmark.p
% 3.36/3.57  Clause #0 (by assumption #[]): Eq (Eq (pl z x) (pl z y)) True
% 3.36/3.57  Clause #1 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), Eq (pl Xx Xz) (pl Xy Xz) → Eq Xx Xy) True
% 3.36/3.57  Clause #2 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (pl Xx Xy) (pl Xy Xx)) True
% 3.36/3.57  Clause #3 (by assumption #[]): Eq (Not (Eq x y)) True
% 3.36/3.57  Clause #4 (by clausification #[3]): Eq (Eq x y) False
% 3.36/3.57  Clause #5 (by clausification #[4]): Ne x y
% 3.36/3.57  Clause #6 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), Eq (pl a Xz) (pl Xy Xz) → Eq a Xy) True
% 3.36/3.57  Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), Eq (pl a Xz) (pl a_1 Xz) → Eq a a_1) True
% 3.36/3.57  Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 : nat), Eq (Eq (pl a a_1) (pl a_2 a_1) → Eq a a_2) True
% 3.36/3.57  Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : nat), Or (Eq (Eq (pl a a_1) (pl a_2 a_1)) False) (Eq (Eq a a_2) True)
% 3.36/3.57  Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 : nat), Or (Eq (Eq a a_1) True) (Ne (pl a a_2) (pl a_1 a_2))
% 3.36/3.57  Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 : nat), Or (Ne (pl a a_1) (pl a_2 a_1)) (Eq a a_2)
% 3.36/3.57  Clause #13 (by clausification #[0]): Eq (pl z x) (pl z y)
% 3.36/3.57  Clause #16 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (pl a Xy) (pl Xy a)) True
% 3.36/3.57  Clause #17 (by clausification #[16]): ∀ (a a_1 : nat), Eq (Eq (pl a a_1) (pl a_1 a)) True
% 3.36/3.57  Clause #18 (by clausification #[17]): ∀ (a a_1 : nat), Eq (pl a a_1) (pl a_1 a)
% 3.36/3.57  Clause #21 (by superposition #[18, 11]): ∀ (a a_1 a_2 : nat), Or (Ne (pl a a_1) (pl a_1 a_2)) (Eq a a_2)
% 3.36/3.57  Clause #23 (by superposition #[21, 13]): ∀ (a : nat), Or (Ne (pl a z) (pl z y)) (Eq a x)
% 3.36/3.57  Clause #24 (by superposition #[23, 18]): ∀ (a : nat), Or (Ne (pl z a) (pl z y)) (Eq a x)
% 3.36/3.57  Clause #25 (by equality resolution #[24]): Eq y x
% 3.36/3.57  Clause #26 (by forward contextual literal cutting #[25, 5]): False
% 3.36/3.57  SZS output end Proof for theBenchmark.p
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