TSTP Solution File: NUM677^1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : NUM677^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:59 EDT 2023

% Result   : Theorem 3.61s 3.78s
% Output   : Proof 3.61s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.10  % Problem    : NUM677^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.11  % Command    : duper %s
% 0.10/0.30  % Computer : n032.cluster.edu
% 0.10/0.30  % Model    : x86_64 x86_64
% 0.10/0.30  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.30  % Memory   : 8042.1875MB
% 0.10/0.30  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.30  % CPULimit   : 300
% 0.10/0.30  % WCLimit    : 300
% 0.10/0.30  % DateTime   : Fri Aug 25 11:33:43 EDT 2023
% 0.10/0.30  % CPUTime    : 
% 3.61/3.78  SZS status Theorem for theBenchmark.p
% 3.61/3.78  SZS output start Proof for theBenchmark.p
% 3.61/3.78  Clause #0 (by assumption #[]): Eq (Eq x y) True
% 3.61/3.78  Clause #1 (by assumption #[]): Eq (more z u) True
% 3.61/3.78  Clause #2 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : nat), Eq Xx Xy → more Xz Xu → more (pl Xx Xz) (pl Xy Xu)) True
% 3.61/3.78  Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (pl Xx Xy) (pl Xy Xx)) True
% 3.61/3.78  Clause #4 (by assumption #[]): Eq (Not (more (pl z x) (pl u y))) True
% 3.61/3.78  Clause #5 (by clausification #[0]): Eq x y
% 3.61/3.78  Clause #6 (by clausification #[4]): Eq (more (pl z x) (pl u y)) False
% 3.61/3.78  Clause #7 (by forward demodulation #[6, 5]): Eq (more (pl z y) (pl u y)) False
% 3.61/3.78  Clause #8 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (pl a Xy) (pl Xy a)) True
% 3.61/3.78  Clause #9 (by clausification #[8]): ∀ (a a_1 : nat), Eq (Eq (pl a a_1) (pl a_1 a)) True
% 3.61/3.78  Clause #10 (by clausification #[9]): ∀ (a a_1 : nat), Eq (pl a a_1) (pl a_1 a)
% 3.61/3.78  Clause #11 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), Eq a Xy → more Xz Xu → more (pl a Xz) (pl Xy Xu)) True
% 3.61/3.78  Clause #12 (by clausification #[11]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), Eq a a_1 → more Xz Xu → more (pl a Xz) (pl a_1 Xu)) True
% 3.61/3.78  Clause #13 (by clausification #[12]): ∀ (a a_1 a_2 : nat), Eq (∀ (Xu : nat), Eq a a_1 → more a_2 Xu → more (pl a a_2) (pl a_1 Xu)) True
% 3.61/3.78  Clause #14 (by clausification #[13]): ∀ (a a_1 a_2 a_3 : nat), Eq (Eq a a_1 → more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True
% 3.61/3.78  Clause #15 (by clausification #[14]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (Eq a a_1) False) (Eq (more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True)
% 3.61/3.78  Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1 → more (pl a_2 a) (pl a_3 a_1)) True) (Ne a_2 a_3)
% 3.61/3.78  Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 a_3 : nat), Or (Ne a a_1) (Or (Eq (more a_2 a_3) False) (Eq (more (pl a a_2) (pl a_1 a_3)) True))
% 3.61/3.78  Clause #18 (by destructive equality resolution #[17]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a_2 a) (pl a_2 a_1)) True)
% 3.61/3.78  Clause #19 (by superposition #[18, 1]): ∀ (a : nat), Or (Eq (more (pl a z) (pl a u)) True) (Eq False True)
% 3.61/3.78  Clause #20 (by clausification #[19]): ∀ (a : nat), Eq (more (pl a z) (pl a u)) True
% 3.61/3.78  Clause #23 (by superposition #[20, 10]): ∀ (a : nat), Eq (more (pl z a) (pl a u)) True
% 3.61/3.78  Clause #25 (by superposition #[23, 10]): ∀ (a : nat), Eq (more (pl z a) (pl u a)) True
% 3.61/3.78  Clause #26 (by superposition #[25, 7]): Eq True False
% 3.61/3.78  Clause #28 (by clausification #[26]): False
% 3.61/3.78  SZS output end Proof for theBenchmark.p
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